var list = (from u in db.Users join c in db.Customers on u.CustomerId equals c.CustomerId where u.Username == username
   select new {u.UserId, u.CustomerId, u.ClientId, u.RoleId, u.Username, u.Email, u.Password, u.Salt, u.Hint1, u.Hint2, u.Hint3, u.Locked, u.Active,c.ProfilePic}).First();

编写所需的表名，并初始化select以获得字段的结果。

因为我更喜欢表达式链语法，下面是你如何做到这一点:

var dealerContracts = DealerContact.Join(Dealer, 
                                 contact => contact.DealerId,
                                 dealer => dealer.DealerId,
                                 (contact, dealer) => contact);

实际上，在linq中，通常最好不要加入。当有导航属性时，一个非常简洁的方式来写你的linq语句是:

from dealer in db.Dealers
from contact in dealer.DealerContacts
select new { whatever you need from dealer or contact }

它转换为where子句:

SELECT <columns>
FROM Dealer, DealerContact
WHERE Dealer.DealerID = DealerContact.DealerID

使用Linq Join操作符:

var q =  from d in Dealer
         join dc in DealerConact on d.DealerID equals dc.DealerID
         select dc;

从d1在dealercontract中加入d2在dealercontract中d1.dealearid = d2.dealerid select new {dealercontract.*}

var data=(from t in db.your tableName(t1) 
          join s in db.yourothertablename(t2) on t1.fieldname equals t2.feldname
          (where condtion)).tolist();