我试了一下

public static void main(String[] args) 
{
    String rowString = "replace the value ${var1} with ${var2}";
    
    Map<String,String> mappedValues = new HashMap<>();
    
    mappedValues.put("var1", "Value 1");
    mappedValues.put("var2", "Value 2");
    
    System.out.println(replaceOccurence(rowString, mappedValues));
}

private static  String replaceOccurence(String baseStr ,Map<String,String> mappedValues)
{
    for(String key :mappedValues.keySet())
    {
        baseStr = baseStr.replace("${"+key+"}", mappedValues.get(key));
    }
    
    return baseStr;
}

试试Freemarker，模板库。

在编写本文时，Java中还没有内置任何东西。我建议编写自己的实现。我的偏好是一个简单流畅的构建器接口，而不是创建一个映射并将其传递给函数——你最终会得到一个漂亮的连续代码块，例如:

String result = new TemplatedStringBuilder("My name is {{name}} and I from {{town}}")
   .replace("name", "John Doe")
   .replace("town", "Sydney")
   .finish();

下面是一个简单的实现:

class TemplatedStringBuilder {

    private final static String TEMPLATE_START_TOKEN = "{{";
    private final static String TEMPLATE_CLOSE_TOKEN = "}}";

    private final String template;
    private final Map<String, String> parameters = new HashMap<>();

    public TemplatedStringBuilder(String template) {
        if (template == null) throw new NullPointerException();
        this.template = template;
    }

    public TemplatedStringBuilder replace(String key, String value){
        parameters.put(key, value);
        return this;
    }

    public String finish(){

        StringBuilder result = new StringBuilder();

        int startIndex = 0;

        while (startIndex < template.length()){

            int openIndex  = template.indexOf(TEMPLATE_START_TOKEN, startIndex);

            if (openIndex < 0){
                result.append(template.substring(startIndex));
                break;
            }

            int closeIndex = template.indexOf(TEMPLATE_CLOSE_TOKEN, openIndex);

            if(closeIndex < 0){
                result.append(template.substring(startIndex));
                break;
            }

            String key = template.substring(openIndex + TEMPLATE_START_TOKEN.length(), closeIndex);

            if (!parameters.containsKey(key)) throw new RuntimeException("missing value for key: " + key);

            result.append(template.substring(startIndex, openIndex));
            result.append(parameters.get(key));

            startIndex = closeIndex + TEMPLATE_CLOSE_TOKEN.length();
        }

        return result.toString();
    }
}

Apache Commons Lang的replaceEach方法可能会根据您的特定需求派上用场。你可以简单地用这个方法调用来替换占位符:

StringUtils.replaceEach("There's an incorrect value '%(value)' in column # %(column)",
            new String[] { "%(value)", "%(column)" }, new String[] { x, y });

给定一些输入文本，这将用第二个字符串数组中的相应值替换第一个字符串数组中出现的所有占位符。

截至2022年，最新的解决方案是Apache Commons Text StringSubstitutor

医生说:

// Build map
 Map<String, String> valuesMap = new HashMap<>();
 valuesMap.put("animal", "quick brown fox");
 valuesMap.put("target", "lazy dog");
 String templateString = "The ${animal} jumped over the ${target} ${undefined.number:-1234567890} times.";

 // Build StringSubstitutor
 StringSubstitutor sub = new StringSubstitutor(valuesMap);

 // Replace
 String resolvedString = sub.replace(templateString)

;

我最终得到了下一个解决方案: 使用substitute()方法创建类templatessubstitute，并使用它格式化输出 然后创建一个字符串模板，并用值填充它

import java.util.*;
public class MyClass {

    public static void main(String args[]) {
    String template = "WRR = {WRR}, SRR = {SRR}\n" +
                      "char_F1 = {char_F1}, word_F1 = {word_F1}\n";
    
    Map<String, Object> values = new HashMap<>();
    values.put("WRR", 99.9);
    values.put("SRR", 99.8);
    values.put("char_F1", 80);
    values.put("word_F1", 70);
    
    String message = TemplateSubstitutor.substitute(values, template);
    
    System.out.println(message);
    }
}

class TemplateSubstitutor {
    public static String substitute(Map<String, Object> map, String input_str) {
        String output_str = input_str;
        for (Map.Entry<String, Object> entry : map.entrySet()) {
            String key = entry.getKey();
            Object value = entry.getValue();
            output_str = output_str.replace("{" + key + "}", String.valueOf(value));
        }
        return output_str;
    }
    
}