在JavaScript中检测IE版本(v9之前)

如果我们网站的用户使用的是v9之前版本的Internet Explorer，我希望将他们弹出到一个错误页面。不值得我们花时间和金钱去支持iev9之前的版本。所有其他非ie浏览器的用户都没问题，不应该被弹出。以下是提议的代码:

if(navigator.appName.indexOf("Internet Explorer")!=-1){     //yeah, he's using IE
    var badBrowser=(
        navigator.appVersion.indexOf("MSIE 9")==-1 &&   //v9 is ok
        navigator.appVersion.indexOf("MSIE 1")==-1  //v10, 11, 12, etc. is fine too
    );

    if(badBrowser){
        // navigate to error page
    }
}

这段代码能行吗?

为了阻止一些可能会出现在我面前的评论:

Yes, I know that users can forge their useragent string. I'm not concerned. Yes, I know that programming pros prefer sniffing out feature-support instead of browser-type but I don't feel this approach makes sense in this case. I already know that all (relevant) non-IE browsers support the features that I need and that all pre-v9 IE browsers don't. Checking feature by feature throughout the site would be a waste. Yes, I know that someone trying to access the site using IE v1 (or >= 20) wouldn't get 'badBrowser' set to true and the warning page wouldn't be displayed properly. That's a risk we're willing to take. Yes, I know that Microsoft has "conditional comments" that can be used for precise browser version detection. IE no longer supports conditional comments as of IE 10, rendering this approach absolutely useless.

还有其他明显需要注意的问题吗?

当前回答

if (!document.addEventListener) {
    // ie8
} else if (!window.btoa) {
    // ie9
}
// others

2015-11-12 06:56:56

其他回答

下面的代码依赖标识了所有情况下的IE版本(IE<=9, IE10, IE11和IE/Edge)

function detectIE() {
    var ua = window.navigator.userAgent;
    var msie = ua.indexOf('MSIE ');
    if (msie > 0) {
        // IE 10 or older => return version number
        return parseInt(ua.substring(msie + 5, ua.indexOf('.', msie)), 10);
    }
    var trident = ua.indexOf('Trident/');
    if (trident > 0) {
        // IE 11 => return version number
        var rv = ua.indexOf('rv:');
        return parseInt(ua.substring(rv + 3, ua.indexOf('.', rv)), 10);
    }
    var edge = ua.indexOf('Edge/');
    if (edge > 0) {
        // Edge (IE 12+) => return version number
        return parseInt(ua.substring(edge + 5, ua.indexOf('.', edge)), 10);
    }
    // other browser
    return false;
}

裁判:https://codepen.io/gapcode/pen/vEJNZN

2016-09-06 07:04:56

轻松检测MSIE (v6 - v7 - v8 - v9 - v10 - v11):

if (navigator.userAgent.indexOf('MSIE') !== -1 || navigator.appVersion.indexOf('Trident/') > 0) {
   // MSIE
}

2013-12-05 21:58:05

简单的解决方案，停止思考浏览器和使用年。

var year = eval(today.getYear());
if(year < 1900 )
 {alert('Good to go: All browsers and IE 9 & >');}
else
 {alert('Get with it and upgrade your IE to 9 or >');}

2015-02-20 18:01:22

这是我喜欢的做法。它提供了最大限度的控制。(注意:条件语句仅在IE5 - 9中支持。)

首先正确地设置ie类

<!DOCTYPE html>
<!--[if lt IE 7]> <html class="lt-ie9 lt-ie8 lt-ie7"> <![endif]-->
<!--[if IE 7]>    <html class="lt-ie9 lt-ie8"> <![endif]-->
<!--[if IE 8]>    <html class="lt-ie9"> <![endif]-->
<!--[if gt IE 8]><!--> <html> <!--<![endif]-->    
<head>

然后你可以使用CSS来创建样式异常，或者，如果你需要，你可以添加一些简单的JavaScript:

(function ($) {
    "use strict";

    // Detecting IE
    var oldIE;
    if ($('html').is('.lt-ie7, .lt-ie8, .lt-ie9')) {
        oldIE = true;
    }

    if (oldIE) {
        // Here's your JS for IE..
    } else {
        // ..And here's the full-fat code for everyone else
    }

}(jQuery));

感谢Paul Irish。

2012-06-09 22:38:20

下面是AngularJS检查IE的方法

/**
 * documentMode is an IE-only property
 * http://msdn.microsoft.com/en-us/library/ie/cc196988(v=vs.85).aspx
 */
var msie = document.documentMode;

if (msie < 9) {
    // code for IE < 9
}

2015-07-08 12:54:12

在JavaScript中检测IE版本(v9之前)

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