如果我们网站的用户使用的是v9之前版本的Internet Explorer,我希望将他们弹出到一个错误页面。不值得我们花时间和金钱去支持iev9之前的版本。所有其他非ie浏览器的用户都没问题,不应该被弹出。以下是提议的代码:

if(navigator.appName.indexOf("Internet Explorer")!=-1){     //yeah, he's using IE
    var badBrowser=(
        navigator.appVersion.indexOf("MSIE 9")==-1 &&   //v9 is ok
        navigator.appVersion.indexOf("MSIE 1")==-1  //v10, 11, 12, etc. is fine too
    );

    if(badBrowser){
        // navigate to error page
    }
}

这段代码能行吗?

为了阻止一些可能会出现在我面前的评论:

Yes, I know that users can forge their useragent string. I'm not concerned. Yes, I know that programming pros prefer sniffing out feature-support instead of browser-type but I don't feel this approach makes sense in this case. I already know that all (relevant) non-IE browsers support the features that I need and that all pre-v9 IE browsers don't. Checking feature by feature throughout the site would be a waste. Yes, I know that someone trying to access the site using IE v1 (or >= 20) wouldn't get 'badBrowser' set to true and the warning page wouldn't be displayed properly. That's a risk we're willing to take. Yes, I know that Microsoft has "conditional comments" that can be used for precise browser version detection. IE no longer supports conditional comments as of IE 10, rendering this approach absolutely useless.

还有其他明显需要注意的问题吗?


当前回答

// Detect ie <= 10
var ie = /MSIE ([0-9]+)/g.exec(window.navigator.userAgent)[1] || undefined;

console.log(ie);
// Return version ie or undefined if not ie or ie > 10

其他回答

function getIEVersion(){
     if (/MSIE |Trident\//.test( navigator.userAgent )=== false) return -1;
    /**[IE <=9]*/
    var isIE9L = typeof ( window.attachEvent ) === 'function' && !( Object.prototype.toString.call( window.opera ) == '[object Opera]' ) ? true : false;
    var re;
    if(isIE9L){
        re = new RegExp( "MSIE ([0-9]{1,}[\.0-9]{0,})" );
        if(re.exec( navigator.userAgent ) !== null)
            return parseFloat( RegExp.$1 );
        return -1;
    }
    /**[/IE <=9]*/
    /** [IE >= 10]*/
    if(navigator.userAgent.indexOf( 'Trident/' ) > -1){
        re = new RegExp( "rv:([0-9]{1,}[\.0-9]{0,})" );
        if(re.exec( navigator.userAgent ) !== null)
            return parseFloat( RegExp.$1 );
        return -1;
    }
    /**[/IE >= 10]*/
    return -1;
};

点击这里==>

var ieVersion = getIEVersion();

if(ieVersion < 0){
    //Not IE
}
//A version of IE

了解关于浏览器导航器的更多信息 https://developer.mozilla.org/en-US/docs/Web/API/Window/navigator

使用条件注释。您正在尝试检测IE < 9的用户,条件注释将在这些浏览器中工作;在其他浏览器(IE >= 10和非IE)中,注释将被视为正常的HTML注释,这就是它们的本质。

示例HTML:

<!--[if lt IE 9]>
WE DON'T LIKE YOUR BROWSER
<![endif]-->

如果你需要,你也可以用脚本来完成:

var div = document.createElement("div");
div.innerHTML = "<!--[if lt IE 9]><i></i><![endif]-->";
var isIeLessThan9 = (div.getElementsByTagName("i").length == 1);
if (isIeLessThan9) {
    alert("WE DON'T LIKE YOUR BROWSER");
}

要检测Internet Explorer 10|11,你可以在body标签后立即使用这个小脚本:

在我的情况下,我使用jQuery库加载头部。

<!DOCTYPE HTML>
<html>
<head>
    <script src="//code.jquery.com/jquery-1.11.0.min.js"></script>
</head>
<body>
    <script>if (navigator.appVersion.indexOf('Trident/') != -1) $("body").addClass("ie10");</script>
</body>
</html>

这对我很有用。我用它来重定向到一个页面,解释为什么我们不喜欢< IE9,并提供链接到我们更喜欢的浏览器。

<!--[if lt IE 9]>
<meta http-equiv="refresh" content="0;URL=http://google.com">
<![endif]-->

使用特征检测来检测IE版本(IE6+,在IE6之前的浏览器被检测为6,非IE浏览器返回null):

var ie = (function (){
    if (window.ActiveXObject === undefined) return null; //Not IE
    if (!window.XMLHttpRequest) return 6;
    if (!document.querySelector) return 7;
    if (!document.addEventListener) return 8;
    if (!window.atob) return 9;
    if (!document.__proto__) return 10;
    return 11;
})();

编辑:为了方便起见,我创建了一个bower/npm repo: ie-version

更新:

更紧凑的版本可以写成一行:

return window.ActiveXObject === undefined ? null : !window.XMLHttpRequest ? 6 : !document.querySelector ? 7 : !document.addEventListener ? 8 : !window.atob ? 9 : !document.__proto__ ? 10 : 11;