我可以用printf打印十六进制或八进制数字。是否有格式标签打印为二进制或任意基数?

我正在运行gcc。

printf("%d %x %o\n", 10, 10, 10); //prints "10 A 12\n"
printf("%b\n", 10); // prints "%b\n"

当前回答

即使是支持%b的运行时库,它似乎也只适用于整数值。

如果您想打印二进制的浮点值,我写了一些代码,您可以在http://www.exploringbinary.com/converting-floating-point-numbers-to-binary-strings-in-c/上找到。

其他回答

之前发布的答案都不是我想要的,所以我写了一个。在printf中使用%B是超级简单的!

/*
 * File:   main.c
 * Author: Techplex.Engineer
 *
 * Created on February 14, 2012, 9:16 PM
 */

#include <stdio.h>
#include <stdlib.h>
#include <printf.h>
#include <math.h>
#include <string.h>

static int printf_arginfo_M(const struct printf_info *info, size_t n, int *argtypes)
{
    /* "%M" always takes one argument, a pointer to uint8_t[6]. */
    if (n > 0) {
        argtypes[0] = PA_POINTER;
    }
    return 1;
}

static int printf_output_M(FILE *stream, const struct printf_info *info, const void *const *args)
{
    int value = 0;
    int len;

    value = *(int **) (args[0]);

    // Beginning of my code ------------------------------------------------------------
    char buffer [50] = "";  // Is this bad?
    char buffer2 [50] = "";  // Is this bad?
    int bits = info->width;
    if (bits <= 0)
        bits = 8;  // Default to 8 bits

    int mask = pow(2, bits - 1);
    while (mask > 0) {
        sprintf(buffer, "%s", ((value & mask) > 0 ? "1" : "0"));
        strcat(buffer2, buffer);
        mask >>= 1;
    }
    strcat(buffer2, "\n");
    // End of my code --------------------------------------------------------------
    len = fprintf(stream, "%s", buffer2);
    return len;
}

int main(int argc, char** argv)
{
    register_printf_specifier('B', printf_output_M, printf_arginfo_M);

    printf("%4B\n", 65);

    return EXIT_SUCCESS;
}

你可以使用一个小表格来提高速度。类似的技术在嵌入式世界中也很有用,例如,反转一个字节:

const char *bit_rep[16] = {
    [ 0] = "0000", [ 1] = "0001", [ 2] = "0010", [ 3] = "0011",
    [ 4] = "0100", [ 5] = "0101", [ 6] = "0110", [ 7] = "0111",
    [ 8] = "1000", [ 9] = "1001", [10] = "1010", [11] = "1011",
    [12] = "1100", [13] = "1101", [14] = "1110", [15] = "1111",
};

void print_byte(uint8_t byte)
{
    printf("%s%s", bit_rep[byte >> 4], bit_rep[byte & 0x0F]);
}

1我主要指的是嵌入式应用程序,其中优化器不是那么激进,速度差异是可见的。

这里有一个快速的技巧来演示如何做你想做的事情。

#include <stdio.h>      /* printf */
#include <string.h>     /* strcat */
#include <stdlib.h>     /* strtol */

const char *byte_to_binary
(
    int x
)
{
    static char b[9];
    b[0] = '\0';

    int z;
    for (z = 128; z > 0; z >>= 1)
    {
        strcat(b, ((x & z) == z) ? "1" : "0");
    }

    return b;
}

int main
(
    void
)
{
    {
        /* binary string to int */

        char *tmp;
        char *b = "0101";

        printf("%d\n", strtol(b, &tmp, 2));
    }

    {
        /* byte to binary string */

        printf("%s\n", byte_to_binary(5));
    }
    
    return 0;
}

一些运行时支持“%b”,尽管这不是标准。

也可以在这里看到一个有趣的讨论:

http://bytes.com/forum/thread591027.html

HTH

const char* byte_to_binary(int x)
{
    static char b[sizeof(int)*8+1] = {0};
    int y;
    long long z;

    for (z = 1LL<<sizeof(int)*8-1, y = 0; z > 0; z >>= 1, y++) {
        b[y] = (((x & z) == z) ? '1' : '0');
    }
    b[y] = 0;

    return b;
}