我可以用printf打印十六进制或八进制数字。是否有格式标签打印为二进制或任意基数?
我正在运行gcc。
printf("%d %x %o\n", 10, 10, 10); //prints "10 A 12\n"
printf("%b\n", 10); // prints "%b\n"
我可以用printf打印十六进制或八进制数字。是否有格式标签打印为二进制或任意基数?
我正在运行gcc。
printf("%d %x %o\n", 10, 10, 10); //prints "10 A 12\n"
printf("%b\n", 10); // prints "%b\n"
当前回答
之前发布的答案都不是我想要的,所以我写了一个。在printf中使用%B是超级简单的!
/*
* File: main.c
* Author: Techplex.Engineer
*
* Created on February 14, 2012, 9:16 PM
*/
#include <stdio.h>
#include <stdlib.h>
#include <printf.h>
#include <math.h>
#include <string.h>
static int printf_arginfo_M(const struct printf_info *info, size_t n, int *argtypes)
{
/* "%M" always takes one argument, a pointer to uint8_t[6]. */
if (n > 0) {
argtypes[0] = PA_POINTER;
}
return 1;
}
static int printf_output_M(FILE *stream, const struct printf_info *info, const void *const *args)
{
int value = 0;
int len;
value = *(int **) (args[0]);
// Beginning of my code ------------------------------------------------------------
char buffer [50] = ""; // Is this bad?
char buffer2 [50] = ""; // Is this bad?
int bits = info->width;
if (bits <= 0)
bits = 8; // Default to 8 bits
int mask = pow(2, bits - 1);
while (mask > 0) {
sprintf(buffer, "%s", ((value & mask) > 0 ? "1" : "0"));
strcat(buffer2, buffer);
mask >>= 1;
}
strcat(buffer2, "\n");
// End of my code --------------------------------------------------------------
len = fprintf(stream, "%s", buffer2);
return len;
}
int main(int argc, char** argv)
{
register_printf_specifier('B', printf_output_M, printf_arginfo_M);
printf("%4B\n", 65);
return EXIT_SUCCESS;
}
其他回答
下面是我对unsigned int的处理方法
void printb(unsigned int v) {
unsigned int i, s = 1<<((sizeof(v)<<3)-1); // s = only most significant bit at 1
for (i = s; i; i>>=1) printf("%d", v & i || 0 );
}
void PrintBinary( int Value, int Places, char* TargetString)
{
int Mask;
Mask = 1 << Places;
while( Places--) {
Mask >>= 1; /* Preshift, because we did one too many above */
*TargetString++ = (Value & Mask)?'1':'0';
}
*TargetString = 0; /* Null terminator for C string */
}
调用函数“拥有”字符串…:
char BinaryString[17];
...
PrintBinary( Value, 16, BinaryString);
printf( "yadda yadda %s yadda...\n", BinaryString);
取决于您的CPU, PrintBinary中的大多数操作呈现给一个或很少几个机器指令。
const char* byte_to_binary(int x)
{
static char b[sizeof(int)*8+1] = {0};
int y;
long long z;
for (z = 1LL<<sizeof(int)*8-1, y = 0; z > 0; z >>= 1, y++) {
b[y] = (((x & z) == z) ? '1' : '0');
}
b[y] = 0;
return b;
}
void DisplayBinary(int n)
{
int arr[8];
int top =-1;
while (n)
{
if (n & 1)
arr[++top] = 1;
else
arr[++top] = 0;
n >>= 1;
}
for (int i = top ; i > -1;i--)
{
printf("%d",arr[i]);
}
printf("\n");
}
void DisplayBinary(unsigned int n)
{
int l = sizeof(n) * 8;
for (int i = l - 1 ; i >= 0; i--) {
printf("%x", (n & (1 << i)) >> i);
}
}