目前在Django 2.2中，当开始一个新项目时，推荐的方法是创建一个自定义的用户模型，它继承自AbstractUser，然后将AUTH_USER_MODEL指向该模型。

来源:https://docs.djangoproject.com/en/2.2/topics/auth/customizing/ using-a-custom-user-model-when-starting-a-project

自2008年以来已经过去了一段时间，是时候给出一些新的答案了。从Django 1.5开始，你将能够创建自定义User类。实际上，在我写这个的时候，它已经合并到master中了，所以你可以试试。

在文档中有一些关于它的信息，如果你想深入了解，在这个提交中。

您所要做的就是将AUTH_USER_MODEL添加到具有自定义用户类路径的设置中，它扩展了AbstractBaseUser(更可定制的版本)或AbstractUser(或多或少可以扩展的旧用户类)。

对于那些懒得点击的人，这里有一个代码示例(摘自docs):

from django.db import models
from django.contrib.auth.models import (
    BaseUserManager, AbstractBaseUser
)


class MyUserManager(BaseUserManager):
    def create_user(self, email, date_of_birth, password=None):
        """
        Creates and saves a User with the given email, date of
        birth and password.
        """
        if not email:
            raise ValueError('Users must have an email address')

        user = self.model(
            email=MyUserManager.normalize_email(email),
            date_of_birth=date_of_birth,
        )

        user.set_password(password)
        user.save(using=self._db)
        return user

    def create_superuser(self, username, date_of_birth, password):
        """
        Creates and saves a superuser with the given email, date of
        birth and password.
        """
        u = self.create_user(username,
                        password=password,
                        date_of_birth=date_of_birth
                    )
        u.is_admin = True
        u.save(using=self._db)
        return u


class MyUser(AbstractBaseUser):
    email = models.EmailField(
                        verbose_name='email address',
                        max_length=255,
                        unique=True,
                    )
    date_of_birth = models.DateField()
    is_active = models.BooleanField(default=True)
    is_admin = models.BooleanField(default=False)

    objects = MyUserManager()

    USERNAME_FIELD = 'email'
    REQUIRED_FIELDS = ['date_of_birth']

    def get_full_name(self):
        # The user is identified by their email address
        return self.email

    def get_short_name(self):
        # The user is identified by their email address
        return self.email

    def __unicode__(self):
        return self.email

    def has_perm(self, perm, obj=None):
        "Does the user have a specific permission?"
        # Simplest possible answer: Yes, always
        return True

    def has_module_perms(self, app_label):
        "Does the user have permissions to view the app `app_label`?"
        # Simplest possible answer: Yes, always
        return True

    @property
    def is_staff(self):
        "Is the user a member of staff?"
        # Simplest possible answer: All admins are staff
        return self.is_admin

试试这个:

创建一个名为Profile的模型，并使用OneToOneField引用用户，并提供一个related_name选项。

models.py

from django.db import models
from django.contrib.auth.models import *
from django.dispatch import receiver
from django.db.models.signals import post_save

class Profile(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE, related_name='user_profile')

    def __str__(self):
        return self.user.username

@receiver(post_save, sender=User)
def create_profile(sender, instance, created, **kwargs):
    try:
        if created:
            Profile.objects.create(user=instance).save()
    except Exception as err:
        print('Error creating user profile!')

现在要使用User对象直接访问配置文件，可以使用related_name。

views.py

from django.http import HttpResponse

def home(request):
    profile = f'profile of {request.user.user_profile}'
    return HttpResponse(profile)

从Django 1.5开始，你可以很容易地扩展用户模型，在数据库中只保留一个表。

from django.contrib.auth.models import AbstractUser
from django.db import models
from django.utils.translation import ugettext_lazy as _

class UserProfile(AbstractUser):
    age = models.PositiveIntegerField(_("age"))

您还必须在设置文件中将其配置为当前用户类

# supposing you put it in apps/profiles/models.py
AUTH_USER_MODEL = "profiles.UserProfile"

如果你想添加很多用户的首选项，OneToOneField选项可能是一个更好的选择。

给开发第三方库的人一个提示:如果您需要访问用户类，请记住人们可以更改它。使用官方帮助获取正确的类

from django.contrib.auth import get_user_model

User = get_user_model()

目前在Django 2.2中，当开始一个新项目时，推荐的方法是创建一个自定义的用户模型，它继承自AbstractUser，然后将AUTH_USER_MODEL指向该模型。

来源:https://docs.djangoproject.com/en/2.2/topics/auth/customizing/ using-a-custom-user-model-when-starting-a-project

像Pro一样扩展Django用户模型(UserProfile)

我发现这个非常有用:link

摘录:

from django.contrib.auth.models import User

class Employee(models.Model):
    user = models.OneToOneField(User)
    department = models.CharField(max_length=100)

>>> u = User.objects.get(username='fsmith')
>>> freds_department = u.employee.department