Code
2024-02-03 08:00:02

使用Newtonsoft反序列化JSON到.NET对象(或LINQ到JSON ?)

我知道有一些关于Newtonsoft的帖子，所以希望这不是一次重复……我试图将Kazaa的API返回的JSON数据转换为某种类型的漂亮对象

WebClient client = new WebClient();
Stream stream = client.OpenRead("http://api.kazaa.com/api/v1/search.json?q=muse&type=Album");
StreamReader reader = new StreamReader(stream);

List<string> list = Newtonsoft.Json.JsonConvert.DeserializeObject<List<string>>(reader.Read().ToString());

foreach (string item in list)
{
    Console.WriteLine(item);
}

//Console.WriteLine(reader.ReadLine());
stream.Close();

那JsonConvert行只是最近一个我正在尝试…我不太明白，希望通过问你们来消除一些步法。我本来是想把它转换成字典什么的……实际上，我只需要在那里抓住几个值，所以根据文档判断，也许Newtonsoft的LINQ到JSON可能是一个更好的选择?想法/链接?

下面是JSON返回数据的示例:

{
  "page": 1,
  "total_pages": 8,
  "total_entries": 74,
  "q": "muse",
  "albums": [
    {
      "name": "Muse",
      "permalink": "Muse",
      "cover_image_url": "http://image.kazaa.com/images/69/01672812 1569/Yaron_Herman_Trio/Muse/Yaron_Herman_Trio-Muse_1.jpg",
      "id": 93098,
      "artist_name": "Yaron Herman Trio"
    },
    {
      "name": "Muse",
      "permalink": "Muse",
      "cover_image_url": "htt p://image.kazaa.com/images/54/888880301154/Candy_Lo/Muse/Candy_Lo-Muse_1.jpg",
      "i d": 102702,
      "artist_name": "\u76e7\u5de7\u97f3"
    },
    {
      "name": "Absolution",
      "permalink": " Absolution",
      "cover_image_url": "http://image.kazaa.com/images/65/093624873365/Mus e/Absolution/Muse-Absolution_1.jpg",
      "id": 48896,
      "artist_name": "Muse"
    },
    {
      "name": "Ab solution",
      "permalink": "Absolution-2",
      "cover_image_url": "http://image.kazaa.com/i mages/20/825646911820/Muse/Absolution/Muse-Absolution_1.jpg",
      "id": 118573,
      "artist _name": "Muse"
    },
    {
      "name": "Black Holes And Revelations",
      "permalink": "Black-Holes-An d-Revelations",
      "cover_image_url": "http://image.kazaa.com/images/66/093624428466/ Muse/Black_Holes_And_Revelations/Muse-Black_Holes_And_Revelations_1.jpg",
      "id": 48813,
      "artist_name": "Muse"
    },
    {
      "name": "Black Holes And Revelations",
      "permalink": "Bla ck-Holes-And-Revelations-2",
      "cover_image_url": "http://image.kazaa.com/images/86/ 825646911486/Muse/Black_Holes_And_Revelations/Muse-Black_Holes_And_Revelations_1 .jpg",
      "id": 118543,
      "artist_name": "Muse"
    },
    {
      "name": "Origin Of Symmetry",
      "permalink": "Origin-Of-Symmetry",
      "cover_image_url": "http://image.kazaa.com/images/29/825646 912629/Muse/Origin_Of_Symmetry/Muse-Origin_Of_Symmetry_1.jpg",
      "id": 120491,
      "artis t_name": "Muse"
    },
    {
      "name": "Showbiz",
      "permalink": "Showbiz",
      "cover_image_url": "http: //image.kazaa.com/images/68/825646182268/Muse/Showbiz/Muse-Showbiz_1.jpg",
      "id": 60444,
      "artist_name": "Muse"
    },
    {
      "name": "Showbiz",
      "permalink": "Showbiz-2",
      "cover_imag e_url": "http://image.kazaa.com/images/50/825646912650/Muse/Showbiz/Muse-Showbiz_ 1.jpg",
      "id": 118545,
      "artist_name": "Muse"
    },
    {
      "name": "The Resistance",
      "permalink": "T he-Resistance",
      "cover_image_url": "http://image.kazaa.com/images/36/825646864836/ Muse/The_Resistance/Muse-The_Resistance_1.jpg",
      "id": 121171,
      "artist_name": "Muse"
    }
  ],
  "per_page": 10
}

我做了更多的阅读，发现Newtonsoft的LINQ到JSON正是我想要的…使用WebClient，流，StreamReader，和Newtonsoft…我可以点击Kazaa获取JSON数据，提取URL，下载文件，这一切都在七行代码中完成!我很喜欢。

WebClient client = new WebClient();
Stream stream = client.OpenRead("http://api.kazaa.com/api/v1/search.json?q=muse&type=Album");
StreamReader reader = new StreamReader(stream);

Newtonsoft.Json.Linq.JObject jObject = Newtonsoft.Json.Linq.JObject.Parse(reader.ReadLine());

// Instead of WriteLine, 2 or 3 lines of code here using WebClient to download the file
Console.WriteLine((string)jObject["albums"][0]["cover_image_url"]);
stream.Close();

这篇文章点击率很高，我认为在评论中加入“使用”的部分可能会有所帮助。

using(var client = new WebClient())
using(var stream = client.OpenRead("http://api.kazaa.com/api/v1/search.json?q=muse&type=Album"))
using (var reader = new StreamReader(stream))
{
    var jObject = Newtonsoft.Json.Linq.JObject.Parse(reader.ReadLine());
    Console.WriteLine((string) jObject["albums"][0]["cover_image_url"]);
}

当前回答

使用JsonConvert.DeserializeObject()函数进行反序列化

public class ApiValues
    {
        [JsonProperty("Address")]
        public string Address { get; set; }

        [JsonProperty("BaseUrl")]
        public string BaseUrl{ get; set; }
    }

var json = 
{ 
    "Address":"some-address",
    "BaseUrl":"some-url-value"
}


var values = JsonConvert.DeserializeObject<ApiValues>(json);
2020-07-31 19:48:05

其他回答

虽然很晚了，但我今天在工作中遇到了这个问题。下面是我解决这个问题的方法。

我正在访问第三方API来检索图书列表。该对象返回一个包含大约20多个字段的大型JSON对象，其中我只需要ID作为List字符串对象。我在动态对象上使用linq检索我需要的特定字段，然后将其插入到我的List字符串对象中。

dynamic content = JsonConvert.DeserializeObject(requestContent);
var contentCodes = ((IEnumerable<dynamic>)content).Where(p => p._id != null).Select(p=>p._id).ToList();

List<string> codes = new List<string>();

foreach (var code in contentCodes)
{
    codes.Add(code?.ToString());
}
2018-07-12 21:38:53

使用dynamic关键字，解析任何这类对象变得非常容易:

dynamic x = Newtonsoft.Json.JsonConvert.DeserializeObject(jsonString);
var page = x.page;
var total_pages = x.total_pages
var albums = x.albums;
foreach(var album in albums)
{
    var albumName = album.name;

    // Access album data;
}
2014-08-28 06:54:55

我喜欢这个方法:

using Newtonsoft.Json.Linq;
// jsonString is your JSON-formatted string
JObject jsonObj = JObject.Parse(jsonString);
Dictionary<string, object> dictObj = jsonObj.ToObject<Dictionary<string, object>>();

现在可以使用dictObj作为字典访问任何想要的内容。如果您希望以字符串形式获取值，也可以使用Dictionary<string, string>。

您可以使用相同的方法将其转换为任何类型的. net对象。

2016-03-29 17:26:50

如果我说错了，请纠正我，但我认为前面的例子与James Newton的Json的最新版本略有不同步。网络图书馆。

var o = JObject.Parse(stringFullOfJson);
var page = (int)o["page"];
var totalPages = (int)o["total_pages"];
2011-01-20 17:54:54

使用JsonConvert.DeserializeObject()函数进行反序列化

public class ApiValues
    {
        [JsonProperty("Address")]
        public string Address { get; set; }

        [JsonProperty("BaseUrl")]
        public string BaseUrl{ get; set; }
    }

var json = 
{ 
    "Address":"some-address",
    "BaseUrl":"some-url-value"
}


var values = JsonConvert.DeserializeObject<ApiValues>(json);
2020-07-31 19:48:05

推荐文章

aliyun

最新文章

标签

2024 code 京ICP备15047053号-1