我想转换时间的持续时间，即秒数，以冒号分隔的时间字符串(hh:mm:ss)
我在这里找到了一些有用的答案，但它们都谈到了转换成x小时和x分钟的格式。
那么有一个小片段，这是在jQuery或只是原始JavaScript?
当前回答
function secondsToTime(secs)
{
var hours = Math.floor(secs / (60 * 60));
var divisor_for_minutes = secs % (60 * 60);
var minutes = Math.floor(divisor_for_minutes / 60);
var divisor_for_seconds = divisor_for_minutes % 60;
var seconds = Math.ceil(divisor_for_seconds);
if(hours >= 12)
{
var m= 'pm' ;
}
else
{
var m='am'
}
if(hours-12 >0)
{
var hrs = hours-12;
}
else if(hours-12 <0)
{
var hrs = hours;
}
var obj = {
"h": hrs,
"m": minutes,
"s": seconds,
"a":m
};
return obj;
}
var d = new Date();
var n = d.getHours();
var hms = d.getHours()+':'+d.getMinutes()+':'+d.getSeconds(); // your input string
var a = hms.split(':'); // split it at the colons
// minutes are worth 60 seconds. Hours are worth 60 minutes.
var seconds = (+a[0]) * 60 * 60 + (+a[1]) * 60 + (+a[2]);
console.log(seconds);
console.log(secondsToTime(seconds))
https://jsfiddle.net/jithinksoft/9x6z4sdt/
其他回答
function secondsToTime(secs)
{
var hours = Math.floor(secs / (60 * 60));
var divisor_for_minutes = secs % (60 * 60);
var minutes = Math.floor(divisor_for_minutes / 60);
var divisor_for_seconds = divisor_for_minutes % 60;
var seconds = Math.ceil(divisor_for_seconds);
if(hours >= 12)
{
var m= 'pm' ;
}
else
{
var m='am'
}
if(hours-12 >0)
{
var hrs = hours-12;
}
else if(hours-12 <0)
{
var hrs = hours;
}
var obj = {
"h": hrs,
"m": minutes,
"s": seconds,
"a":m
};
return obj;
}
var d = new Date();
var n = d.getHours();
var hms = d.getHours()+':'+d.getMinutes()+':'+d.getSeconds(); // your input string
var a = hms.split(':'); // split it at the colons
// minutes are worth 60 seconds. Hours are worth 60 minutes.
var seconds = (+a[0]) * 60 * 60 + (+a[1]) * 60 + (+a[2]);
console.log(seconds);
console.log(secondsToTime(seconds))
https://jsfiddle.net/jithinksoft/9x6z4sdt/
我个人更喜欢不带前导零的开头单位(天、小时、分钟)。但是秒应该总是以分钟(0:13)开头，这种表示很容易被认为是“持续时间”，不需要进一步解释(标记为min, sec(s)等)，可用于各种语言(国际化)。
// returns (-)d.h:mm:ss(.f)
// (-)h:mm:ss(.f)
// (-)m:ss(.f)
function formatSeconds (value, fracDigits) {
var isNegative = false;
if (isNaN(value)) {
return value;
} else if (value < 0) {
isNegative = true;
value = Math.abs(value);
}
var days = Math.floor(value / 86400);
value %= 86400;
var hours = Math.floor(value / 3600);
value %= 3600;
var minutes = Math.floor(value / 60);
var seconds = (value % 60).toFixed(fracDigits || 0);
if (seconds < 10) {
seconds = '0' + seconds;
}
var res = hours ? (hours + ':' + ('0' + minutes).slice(-2) + ':' + seconds) : (minutes + ':' + seconds);
if (days) {
res = days + '.' + res;
}
return (isNegative ? ('-' + res) : res);
}
//模仿服务器端(.net, c#)持续时间格式:
public static string Format(this TimeSpan interval)
{
string pattern;
if (interval.Days > 0) pattern = @"d\.h\:mm\:ss";
else if (interval.Hours > 0) pattern = @"h\:mm\:ss";
else pattern = @"m\:ss";
return string.Format("{0}", interval.ToString(pattern));
}
String.prototype.toHHMMSS = function () {
var sec_num = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(sec_num / 3600);
var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
var seconds = sec_num - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
return hours+':'+minutes+':'+seconds;
}
你现在可以这样使用它:
alert("5678".toHHMMSS());
工作代码片段:
String.prototype.toHHMMSS = function () { var sec_num = parseInt(this, 10); // don't forget the second param var hours = Math.floor(sec_num / 3600); var minutes = Math.floor((sec_num - (hours * 3600)) / 60); var seconds = sec_num - (hours * 3600) - (minutes * 60); if (hours < 10) {hours = "0"+hours;} if (minutes < 10) {minutes = "0"+minutes;} if (seconds < 10) {seconds = "0"+seconds;} return hours + ':' + minutes + ':' + seconds; } console.log("5678".toHHMMSS());
要获得格式为hh:MM:ss的时间部分，可以使用下面的正则表达式:
(上面有人在同一篇文章中提到了这一点，谢谢。)
var替换= new日期().toTimeString () .replace (/ . * (\ d {2}: \ d {2}: \ d{2})。* / " $ 1 "); console.log(替换)
新的日期().toString()。分割(" ")[4];
结果15:08:03
