如果你有jquery的访问。Cookie插件，你可以用这种方式删除所有的Cookie:

for (var it in $.cookie()) $.removeCookie(it);

据我所知，没有办法对域名上的任何cookie集进行全面删除。如果知道cookie的名称，并且脚本与cookie在同一个域中，则可以清除cookie。

你可以将值设置为空，过期日期设置为过去的某个时间:

var mydate = new Date();
mydate.setTime(mydate.getTime() - 1);
document.cookie = "username=; expires=" + mydate.toGMTString(); 

这里有一篇关于使用javascript操作cookie的优秀文章。

Jquery:

var cookies = $.cookie();
for(var cookie in cookies) {
$.removeCookie(cookie);
}

香草JS

function clearListCookies()
{   
 var cookies = document.cookie.split(";");
 for (var i = 0; i < cookies.length; i++)
  {   
    var spcook =  cookies[i].split("=");
    deleteCookie(spcook[0]);
  }
  function deleteCookie(cookiename)
   {
    var d = new Date();
    d.setDate(d.getDate() - 1);
    var expires = ";expires="+d;
    var name=cookiename;
    //alert(name);
    var value="";
    document.cookie = name + "=" + value + expires + "; path=/acc/html";                    
}
window.location = ""; // TO REFRESH THE PAGE
}

你可以通过查看文档得到一个列表。饼干变量。清除它们只是一个循环遍历所有它们并一个一个地清除它们的问题。

这对我来说很管用:

function deleteCookie(name) {
  document.cookie = 
    `${name}=; Expires=Thu, 01 Jan 1970 00:00:01 GMT; Path=/`;

    // Remove it from local storage too
    window.localStorage.removeItem(name);
}

function deleteAllCookies() {
  const cookies = document.cookie.split("; ");

  cookies.forEach((cookie) => {
    const name = cookie.split("=").shift();
    this.deleteCookie(name);
  });

  // Some sites backup cookies in `localStorage`
  window.localStorage.clear();
}

如果你想使用js-cookie npm包并按名称删除cookie:

import cookie from 'js-cookie'

export const removeAllCookiesByName = (cookieName: string) => {
  const hostParts = location.host.split('.')
  const domains = hostParts.reduce(
    (acc: string[], current, index) => [
      ...acc,
      hostParts.slice(index).join('.'),
    ],
    []
  )
  domains.forEach((domain) => cookie.remove(cookieName, { domain }))
}