利用ssube的答案。

这是一个可重用的版本。

Object.filterByKey = function (obj, predicate) {
  return Object.keys(obj)
    .filter(key => predicate(key))
    .reduce((out, key) => {
      out[key] = obj[key];
      return out;
    }, {});
}

叫它use

const raw = {
  item1: { key: 'sdfd', value:'sdfd' },
  item2: { key: 'sdfd', value:'sdfd' },
  item3: { key: 'sdfd', value:'sdfd' }
};

const allowed = ['item1', 'item3'];

var filtered = Object.filterByKey(raw, key => 
  return allowed.includes(key));
});

console.log(filtered);

ES6箭头函数的美妙之处在于，你不必将allowed作为参数传入。

基于以下两个答案:

https://stackoverflow.com/a/56081419/13819049 https://stackoverflow.com/a/54976713/13819049

我们可以:

const original = { a: 1, b: 2, c: 3 };
const allowed = ['a', 'b'];

const filtered = Object.fromEntries(allowed.map(k => [k, original[k]]));

哪个更干净更快:

https://jsbench.me/swkv2cbgkd/1

下面的方法获取要过滤的对象和任何属性。

函数removeObjectKeys(obj，…keysToRemove) { let mObject ={…obj} for (let key of keysToRemove) { const{[字符串(键)]:_，…rest} = mObject mObject ={…休息} ｝ 返回mObject ｝ Const obj = {123: "hello"， 345: "world"， 567: "and kitty"}; const filtered = removeObjectKeys(obj, 123); console.log(过滤); const twoFiltered = removeObjectKeys(obj, 345,567); console.log (twoFiltered);

好吧，这一行怎么样

    const raw = {
      item1: { key: 'sdfd', value: 'sdfd' },
      item2: { key: 'sdfd', value: 'sdfd' },
      item3: { key: 'sdfd', value: 'sdfd' }
    };

    const filteredKeys = ['item1', 'item3'];

    const filtered = Object.assign({}, ...filteredKeys.map(key=> ({[key]:raw[key]})));

这个函数将根据键列表筛选对象，它比前面的答案更有效，因为它不需要使用Array。在调用reduce之前进行筛选。所以它是O(n)而不是O(n +过滤)

function filterObjectByKeys (object, keys) {
  return Object.keys(object).reduce((accum, key) => {
    if (keys.includes(key)) {
      return { ...accum, [key]: object[key] }
    } else {
      return accum
    }
  }, {})
}

只是现代JS的另一个解决方案，没有外部库。

我在玩“解构”功能:

Const raw = { Item1: {key: 'sdfd'， value: 'sdfd'}， Item2: {key: 'sdfd'， value: 'sdfd'}， Item3:{键:'sdfd'，值:'sdfd'} }; var myNewRaw = (({item1, item3}) => ({item1, item3}))(raw); console.log (myNewRaw);