我有一些复选框:
<input type='checkbox' value="apple" checked>
<input type='checkbox' value="orange">
<input type='checkbox' value="pear" checked>
<input type='checkbox' value="naartjie">
我想绑定到我的控制器中的一个列表，这样每当一个复选框被更改时，控制器就会维护一个包含所有选中值的列表，例如，['apple'， 'pear']。
Ng-model似乎只能将一个复选框的值绑定到控制器中的一个变量。
是否有其他方法可以将这四个复选框绑定到控制器中的列表?
当前回答
这里有一个快速的可重用的小指令，它似乎可以做你想做的事情。我简单地称之为清单。它在复选框更改时更新数组，并在数组更改时更新复选框。
app.directive('checkList', function() {
return {
scope: {
list: '=checkList',
value: '@'
},
link: function(scope, elem, attrs) {
var handler = function(setup) {
var checked = elem.prop('checked');
var index = scope.list.indexOf(scope.value);
if (checked && index == -1) {
if (setup) elem.prop('checked', false);
else scope.list.push(scope.value);
} else if (!checked && index != -1) {
if (setup) elem.prop('checked', true);
else scope.list.splice(index, 1);
}
};
var setupHandler = handler.bind(null, true);
var changeHandler = handler.bind(null, false);
elem.bind('change', function() {
scope.$apply(changeHandler);
});
scope.$watch('list', setupHandler, true);
}
};
});
这里有一个控制器和一个显示如何使用它的视图。
<div ng-app="myApp" ng-controller='MainController'>
<span ng-repeat="fruit in fruits">
<input type='checkbox' value="{{fruit}}" check-list='checked_fruits'> {{fruit}}<br />
</span>
<div>The following fruits are checked: {{checked_fruits | json}}</div>
<div>Add fruit to the array manually:
<button ng-repeat="fruit in fruits" ng-click='addFruit(fruit)'>{{fruit}}</button>
</div>
</div>
app.controller('MainController', function($scope) {
$scope.fruits = ['apple', 'orange', 'pear', 'naartjie'];
$scope.checked_fruits = ['apple', 'pear'];
$scope.addFruit = function(fruit) {
if ($scope.checked_fruits.indexOf(fruit) != -1) return;
$scope.checked_fruits.push(fruit);
};
});
(这些按钮演示了更改数组也会更新复选框。)
最后，这里有一个关于Plunker指令的例子:http://plnkr.co/edit/3YNLsyoG4PIBW6Kj7dRK?p=preview
其他回答
一种简单的HTML方法:
<input type="checkbox" ng-checked="fruits.indexOf('apple') > -1" ng-click="fruits.indexOf('apple') > -1 ? fruits.splice(fruits.indexOf('apple'), 1) : fruits.push('apple')"> <input type="checkbox" ng-checked="fruits.indexOf('orange') > -1" ng-click="fruits.indexOf('orange') > -1 ? fruits.splice(fruits.indexOf('orange'), 1) : fruits.push('orange')"> <input type="checkbox" ng-checked="fruits.indexOf('pear') > -1" ng-click="fruits.indexOf('pear') > -1 ? fruits.splice(fruits.indexOf('pear'), 1) : fruits.push('pear')"> <input type="checkbox" ng-checked="fruits.indexOf('naartjie') > -1" ng-click="fruits.indexOf('apple') > -1 ? fruits.splice(fruits.indexOf('apple'), 1) : fruits.push('naartjie')">
我改编了Yoshi接受的答案来处理复杂的对象(而不是字符串)。
HTML
<div ng-controller="TestController">
<p ng-repeat="permission in allPermissions">
<input type="checkbox" ng-checked="selectedPermissions.containsObjectWithProperty('id', permission.id)" ng-click="toggleSelection(permission)" />
{{permission.name}}
</p>
<hr />
<p>allPermissions: | <span ng-repeat="permission in allPermissions">{{permission.name}} | </span></p>
<p>selectedPermissions: | <span ng-repeat="permission in selectedPermissions">{{permission.name}} | </span></p>
</div>
JavaScript
Array.prototype.indexOfObjectWithProperty = function(propertyName, propertyValue)
{
for (var i = 0, len = this.length; i < len; i++) {
if (this[i][propertyName] === propertyValue) return i;
}
return -1;
};
Array.prototype.containsObjectWithProperty = function(propertyName, propertyValue)
{
return this.indexOfObjectWithProperty(propertyName, propertyValue) != -1;
};
function TestController($scope)
{
$scope.allPermissions = [
{ "id" : 1, "name" : "ROLE_USER" },
{ "id" : 2, "name" : "ROLE_ADMIN" },
{ "id" : 3, "name" : "ROLE_READ" },
{ "id" : 4, "name" : "ROLE_WRITE" } ];
$scope.selectedPermissions = [
{ "id" : 1, "name" : "ROLE_USER" },
{ "id" : 3, "name" : "ROLE_READ" } ];
$scope.toggleSelection = function toggleSelection(permission) {
var index = $scope.selectedPermissions.indexOfObjectWithProperty('id', permission.id);
if (index > -1) {
$scope.selectedPermissions.splice(index, 1);
} else {
$scope.selectedPermissions.push(permission);
}
};
}
工作示例:http://jsfiddle.net/tCU8v/
这里还有另一个解决方案。我的解决方案的好处是:
它不需要任何额外的手表(这可能会影响性能) 它不需要控制器中的任何代码来保持干净 代码仍然有些短 它只需要很少的代码就可以在多个地方重用，因为它只是一个指令
下面是指令:
function ensureArray(o) {
var lAngular = angular;
if (lAngular.isArray(o) || o === null || lAngular.isUndefined(o)) {
return o;
}
return [o];
}
function checkboxArraySetDirective() {
return {
restrict: 'A',
require: 'ngModel',
link: function(scope, element, attrs, ngModel) {
var name = attrs.checkboxArraySet;
ngModel.$formatters.push(function(value) {
return (ensureArray(value) || []).indexOf(name) >= 0;
});
ngModel.$parsers.push(function(value) {
var modelValue = ensureArray(ngModel.$modelValue) || [],
oldPos = modelValue.indexOf(name),
wasSet = oldPos >= 0;
if (value) {
if (!wasSet) {
modelValue = angular.copy(modelValue);
modelValue.push(name);
}
} else if (wasSet) {
modelValue = angular.copy(modelValue);
modelValue.splice(oldPos, 1);
}
return modelValue;
});
}
}
}
最后就像这样使用它:
<input ng-repeat="fruit in ['apple', 'banana', '...']" type="checkbox" ng-model="fruits" checkbox-array-set="{{fruit}}" />
这就是全部了。唯一增加的是复选框-数组-set属性。
我喜欢Yoshi的回答。我增强了它，所以你可以对多个列表使用相同的函数。
<label ng-repeat="fruitName in fruits">
<input
type="checkbox"
name="selectedFruits[]"
value="{{fruitName}}"
ng-checked="selection.indexOf(fruitName) > -1"
ng-click="toggleSelection(fruitName, selection)"> {{fruitName}}
</label>
<label ng-repeat="veggieName in veggies">
<input
type="checkbox"
name="selectedVeggies[]"
value="{{veggieName}}"
ng-checked="veggieSelection.indexOf(veggieName) > -1"
ng-click="toggleSelection(veggieName, veggieSelection)"> {{veggieName}}
</label>
app.controller('SimpleArrayCtrl', ['$scope', function SimpleArrayCtrl($scope) {
// fruits
$scope.fruits = ['apple', 'orange', 'pear', 'naartjie'];
$scope.veggies = ['lettuce', 'cabbage', 'tomato']
// selected fruits
$scope.selection = ['apple', 'pear'];
$scope.veggieSelection = ['lettuce']
// toggle selection for a given fruit by name
$scope.toggleSelection = function toggleSelection(selectionName, listSelection) {
var idx = listSelection.indexOf(selectionName);
// is currently selected
if (idx > -1) {
listSelection.splice(idx, 1);
}
// is newly selected
else {
listSelection.push(selectionName);
}
};
}]);
http://plnkr.co/edit/KcbtzEyNMA8s1X7Hja8p?p=preview
根据这个线程中的回答，我创建了涵盖所有情况的清单模型指令:
简单的原语数组 对象数组(选择id或整个对象) 对象属性迭代
对于主题启动案例，它将是:
<label ng-repeat="fruit in ['apple', 'orange', 'pear', 'naartjie']">
<input type="checkbox" checklist-model="selectedFruits" checklist-value="fruit"> {{fruit}}
</label>
