JavaScript有Array.join()

js>["Bill","Bob","Steve"].join(" and ")
Bill and Bob and Steve

Java有这样的东西吗?我知道我可以用StringBuilder自己拼凑一些东西:

static public String join(List<String> list, String conjunction)
{
   StringBuilder sb = new StringBuilder();
   boolean first = true;
   for (String item : list)
   {
      if (first)
         first = false;
      else
         sb.append(conjunction);
      sb.append(item);
   }
   return sb.toString();
}

. .但是如果像这样的东西已经是JDK的一部分,那么这样做就没有意义了。


当前回答

实现它的一个正统方法是定义一个新函数:

public static String join(String joinStr, String... strings) {
    if (strings == null || strings.length == 0) {
        return "";
    } else if (strings.length == 1) {
        return strings[0];
    } else {
        StringBuilder sb = new StringBuilder(strings.length * 1 + strings[0].length());
        sb.append(strings[0]);
        for (int i = 1; i < strings.length; i++) {
            sb.append(joinStr).append(strings[i]);
        }
        return sb.toString();
    }
}

示例:

String[] array = new String[] { "7, 7, 7", "Bill", "Bob", "Steve",
        "[Bill]", "1,2,3", "Apple ][","~,~" };

String joined;
joined = join(" and ","7, 7, 7", "Bill", "Bob", "Steve", "[Bill]", "1,2,3", "Apple ][","~,~");
joined = join(" and ", array); // same result

System.out.println(joined);

输出:

7,7,7和比尔,鲍勃,史蒂夫和[比尔],1,2,3和苹果][和~,~

其他回答

不是开箱即用,但许多库都有类似的:

Commons Lang:

org.apache.commons.lang.StringUtils.join(list, conjunction);

春天:

org.springframework.util.StringUtils.collectionToDelimitedString(list, conjunction);

如果你想在没有任何外部库的情况下使用JDK,那么你拥有的代码是正确的方法。在JDK中没有可以使用的简单的“一行程序”。

如果您可以使用外部库,我建议您查看Apache Commons库中的org.apache.commons.lang.StringUtils类。

用法示例:

List<String> list = Arrays.asList("Bill", "Bob", "Steve");
String joinedResult = StringUtils.join(list, " and ");

用java 1.8的流可以使用,

import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

List<String> list = Arrays.asList("Bill","Bob","Steve").
String str = list.stream().collect(Collectors.joining(" and "));

EDIT

我还注意到toString()底层实现问题,以及包含分隔符的元素,但我认为我是偏执狂。

鉴于我对此有两点看法,我将我的答案改为:

static String join( List<String> list , String replacement  ) {
    StringBuilder b = new StringBuilder();
    for( String item: list ) { 
        b.append( replacement ).append( item );
    }
    return b.toString().substring( replacement.length() );
}

这看起来和最初的问题很相似。

所以如果你不想把整个罐子添加到你的项目中,你可以使用这个。

我认为你原来的代码没有问题。实际上,每个人都建议的替代方案看起来几乎相同(尽管它做了一些额外的验证)

这里有Apache 2.0许可证。

public static String join(Iterator iterator, String separator) {
    // handle null, zero and one elements before building a buffer
    if (iterator == null) {
        return null;
    }
    if (!iterator.hasNext()) {
        return EMPTY;
    }
    Object first = iterator.next();
    if (!iterator.hasNext()) {
        return ObjectUtils.toString(first);
    }

    // two or more elements
    StringBuffer buf = new StringBuffer(256); // Java default is 16, probably too small
    if (first != null) {
        buf.append(first);
    }

    while (iterator.hasNext()) {
        if (separator != null) {
            buf.append(separator);
        }
        Object obj = iterator.next();
        if (obj != null) {
            buf.append(obj);
        }
    }
    return buf.toString();
}

现在我们知道了,谢谢开源

你可以从Spring框架的StringUtils中使用它。我知道它已经被提到过,但是实际上您可以只使用这段代码,它就可以立即工作,而不需要Spring。

// from https://github.com/spring-projects/spring-framework/blob/master/spring-core/src/main/java/org/springframework/util/StringUtils.java

/*
 * Copyright 2002-2017 the original author or authors.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */
public class StringUtils {
    public static String collectionToDelimitedString(Collection<?> coll, String delim, String prefix, String suffix) {
        if(coll == null || coll.isEmpty()) {
            return "";
        }
        StringBuilder sb = new StringBuilder();
        Iterator<?> it = coll.iterator();
        while (it.hasNext()) {
            sb.append(prefix).append(it.next()).append(suffix);
            if (it.hasNext()) {
                sb.append(delim);
            }
        }
        return sb.toString();
    }
}