我试着在用户点击的时候分配一个UIImageView给一个动作。
我知道如何为一个UIButton创建一个动作,但我怎么能模仿一个UIButton相同的行为,但使用一个UIImageView?
我试着在用户点击的时候分配一个UIImageView给一个动作。
我知道如何为一个UIButton创建一个动作,但我怎么能模仿一个UIButton相同的行为,但使用一个UIImageView?
当前回答
Swift 4代码
步骤1在ViewdidLoad()中
let pictureTap = UITapGestureRecognizer(target: self, action: #selector(MyInfoTableViewController.imageTapped))
userImageView.addGestureRecognizer(pictureTap)
userImageView.isUserInteractionEnabled = true
步骤2添加“Following”功能
@objc func imageTapped() {
let imageView = userImageView
let newImageView = UIImageView(image: imageView?.image)
newImageView.frame = UIScreen.main.bounds
newImageView.backgroundColor = UIColor.black
newImageView.contentMode = .scaleAspectFit
newImageView.isUserInteractionEnabled = true
let tap = UITapGestureRecognizer(target: self, action: #selector(dismissFullscreenImage))
newImageView.addGestureRecognizer(tap)
self.view.addSubview(newImageView)
self.navigationController?.isNavigationBarHidden = true
self.tabBarController?.tabBar.isHidden = true
}
它已经过测试,工作正常
其他回答
@IBOutlet weak var imageView: UIImageView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
//ViewController is your current view controller
let tap = UITapGestureRecognizer(target: self, action: #selector(ViewController.tappedMe))
imageView.addGestureRecognizer(tap)
imageView.isUserInteractionEnabled = true
}
// Need to ass objective-c annotation
@objc
func tappedMe() {
print("Tapped on Image")
}
需要添加懒TapGestureRecognizer注册 因为“self”在UITapGestureRecognizer(目标:self…)将是nil如果它不是一个惰性变量。即使你设置isUserInteractionEnable = true,它不会注册没有惰性变量。
lazy var imageSelector : UIImageView = {
let image = UIImageView(image: "imageName.png")
//now add tap gesture
image.isUserInteractionEnabled = true
image.addGestureRecognizer(UITapGestureRecognizer(target: self, action: #selector(handleImageSelector)))
return image
}()
@objc private func handleImageSelector() {
print("Pressed image selector")
}
你需要添加一个手势识别器(对于点击使用UITapGestureRecognizer,对于点击和按住使用UILongPressGestureRecognizer)到你的UIImageView。
let tap = UITapGestureRecognizer(target: self, action: #selector(YourClass.tappedMe))
imageView.addGestureRecognizer(tap)
imageView.isUserInteractionEnabled = true
并像这样实现selector方法:
@objc func tappedMe()
{
println("Tapped on Image")
}
这是我发现的,更容易设置。
这是YouTube上的视频
打开库,寻找“Tap Gesture Recognizer”对象。 将对象拖到故事板中,并将委托设置为您想要触发动作的图像。 然后转到视图控制器,拖动相同的对象设置IBAction。
Swift4代码
尝试一些新的扩展方法:
import UIKit
extension UIView {
fileprivate struct AssociatedObjectKeys {
static var tapGestureRecognizer = "MediaViewerAssociatedObjectKey_mediaViewer"
}
fileprivate typealias Action = (() -> Void)?
fileprivate var tapGestureRecognizerAction: Action? {
set {
if let newValue = newValue {
// Computed properties get stored as associated objects
objc_setAssociatedObject(self, &AssociatedObjectKeys.tapGestureRecognizer, newValue, objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN)
}
}
get {
let tapGestureRecognizerActionInstance = objc_getAssociatedObject(self, &AssociatedObjectKeys.tapGestureRecognizer) as? Action
return tapGestureRecognizerActionInstance
}
}
public func addTapGestureRecognizer(action: (() -> Void)?) {
self.isUserInteractionEnabled = true
self.tapGestureRecognizerAction = action
let tapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(handleTapGesture))
self.addGestureRecognizer(tapGestureRecognizer)
}
@objc fileprivate func handleTapGesture(sender: UITapGestureRecognizer) {
if let action = self.tapGestureRecognizerAction {
action?()
} else {
print("no action")
}
}
}
现在,无论何时我们想要添加一个UITapGestureRecognizer到一个UIView或UIView的子类,如UIImageView,我们可以这样做,而不需要为选择器创建相关的函数!
用法:
profile_ImageView.addTapGestureRecognizer {
print("image tapped")
}