配置解析器只支持基本类型的序列化。对于这种需求，我会使用JSON或YAML。

正如Peter Smit所提到的(https://stackoverflow.com/a/11866695/7424596) 您可能想要扩展ConfigParser，此外，还可以使用Interpolator来自动转换列表。

作为参考，在底部你可以找到自动转换配置的代码，如:

[DEFAULT]
keys = [
    Overall cost structure, Capacity, RAW MATERIALS,
    BY-PRODUCT CREDITS, UTILITIES, PLANT GATE COST,
    PROCESS DESCRIPTION, AT 50% CAPACITY, PRODUCTION COSTS,
    INVESTMENT, US$ MILLION, PRODUCTION COSTS, US ¢/LB,
    VARIABLE COSTS, PRODUCTION COSTS, MAINTENANCE MATERIALS
  ]

所以如果你请求密钥，你会得到:

<class 'list'>: ['Overall cost structure', 'Capacity', 'RAW MATERIALS', 'BY-PRODUCT CREDITS', 'UTILITIES', 'PLANT GATE COST', 'PROCESS DESCRIPTION', 'AT 50% CAPACITY', 'PRODUCTION COSTS', 'INVESTMENT', 'US$ MILLION', 'PRODUCTION COSTS', 'US ¢/LB', 'VARIABLE COSTS', 'PRODUCTION COSTS', 'MAINTENANCE MATERIALS']

代码:

class AdvancedInterpolator(Interpolation):
    def before_get(self, parser, section, option, value, defaults):
        is_list = re.search(parser.LIST_MATCHER, value)
        if is_list:
            return parser.getlist(section, option, raw=True)
        return value


class AdvancedConfigParser(ConfigParser):

    _DEFAULT_INTERPOLATION = AdvancedInterpolator()

    LIST_SPLITTER = '\s*,\s*'
    LIST_MATCHER = '^\[([\s\S]*)\]$'

    def _to_list(self, str):
        is_list = re.search(self.LIST_MATCHER, str)
        if is_list:
            return re.split(self.LIST_SPLITTER, is_list.group(1))
        else:
            return re.split(self.LIST_SPLITTER, str)


    def getlist(self, section, option, conv=lambda x:x.strip(), *, raw=False, vars=None,
                  fallback=_UNSET, **kwargs):
        return self._get_conv(
                section, option,
                lambda value: [conv(x) for x in self._to_list(value)],
                raw=raw,
                vars=vars,
                fallback=fallback,
                **kwargs
        )

    def getlistint(self, section, option, *, raw=False, vars=None,
            fallback=_UNSET, **kwargs):
        return self.getlist(section, option, int, raw=raw, vars=vars,
                fallback=fallback, **kwargs)

    def getlistfloat(self, section, option, *, raw=False, vars=None,
            fallback=_UNSET, **kwargs):
        return self.getlist(section, option, float, raw=raw, vars=vars,
                fallback=fallback, **kwargs)

    def getlistboolean(self, section, option, *, raw=False, vars=None,
            fallback=_UNSET, **kwargs):
        return self.getlist(section, option, self._convert_to_boolean,
                raw=raw, vars=vars, fallback=fallback, **kwargs)

请记住缩进的重要性。ConfigParser文档字符串: 值可以跨越多行，只要它们缩进得更深 而不是第一行的值。根据解析器的模式，为空白 行可以被视为多行值的一部分或被忽略。

我降落在这里想要吃掉这个…

[global]
spys = richard.sorge@cccp.gov, mata.hari@deutschland.gov

答案是用逗号分隔，然后去掉空格:

SPYS = [e.strip() for e in parser.get('global', 'spys').split(',')]

获取一个列表结果:

['richard.sorge@cccp.gov', 'mata.hari@deutschland.gov']

它可能不能准确地回答OP的问题，但可能是一些人正在寻找的简单答案。

我更喜欢的另一种方法，就是分割这些值，例如:

#/path/to/config.cfg
[Numbers]
first_row = 1,2,4,8,12,24,36,48

可以像这样加载到字符串或整数列表中，如下所示:

import configparser

config = configparser.ConfigParser()
config.read('/path/to/config.cfg')

# Load into a list of strings
first_row_strings = config.get('Numbers', 'first_row').split(',')

# Load into a list of integers
first_row_integers = [int(x) for x in config.get('Numbers', 'first_row').split(',')]

这种方法可以避免将值包装在括号中以JSON形式加载。

你可以在配置文件中使用列表，然后在python中解析它

from ast import literal_eval

literal_eval("[1,2,3,4]")

import json

json.loads("[1,2,3,4]")

你也可以在你的配置文件后面使用json文件，像这样:

your config file :
[A]
json_dis = .example.jason
--------------------
your code :
import configparser
config = configparser.ConfigParser()
config.read('config.ini')
# getting items of section A
config.items('A')
# result is a list of key-values

import ConfigParser
import os

class Parser(object):
    """attributes may need additional manipulation"""
    def __init__(self, section):
        """section to retun all options on, formatted as an object
        transforms all comma-delimited options to lists
        comma-delimited lists with colons are transformed to dicts
        dicts will have values expressed as lists, no matter the length
        """
        c = ConfigParser.RawConfigParser()
        c.read(os.path.join(os.path.dirname(__file__), 'config.cfg'))

        self.section_name = section

        self.__dict__.update({k:v for k, v in c.items(section)})

        #transform all ',' into lists, all ':' into dicts
        for key, value in self.__dict__.items():
            if value.find(':') > 0:
                #dict
                vals = value.split(',')
                dicts = [{k:v} for k, v in [d.split(':') for d in vals]]
                merged = {}
                for d in dicts:
                    for k, v in d.items():
                        merged.setdefault(k, []).append(v)
                self.__dict__[key] = merged
            elif value.find(',') > 0:
                #list
                self.__dict__[key] = value.split(',')

所以现在我的config.cfg文件，看起来像这样:

[server]
credentials=username:admin,password:$3<r3t
loggingdirs=/tmp/logs,~/logs,/var/lib/www/logs
timeoutwait=15

可以解析为我的小项目所需的足够细粒度的对象。

>>> import config
>>> my_server = config.Parser('server')
>>> my_server.credentials
{'username': ['admin'], 'password', ['$3<r3t']}
>>> my_server.loggingdirs:
['/tmp/logs', '~/logs', '/var/lib/www/logs']
>>> my_server.timeoutwait
'15'

这是为了非常快速地解析简单的配置，您失去了获取int、bool和其他类型输出的所有能力，既没有转换从Parser返回的对象，也没有重新执行Parser类在其他地方完成的解析工作。