一种可能的想法是编写单独的构造函数

//Something is the structure we work with
type Something struct {
     Text string 
     DefaultText string 
} 
// NewSomething create new instance of Something
func NewSomething(text string) Something {
   something := Something{}
   something.Text = text
   something.DefaultText = "default text"
   return something
}

一种可能的想法是编写单独的构造函数

//Something is the structure we work with
type Something struct {
     Text string 
     DefaultText string 
} 
// NewSomething create new instance of Something
func NewSomething(text string) Something {
   something := Something{}
   something.Text = text
   something.DefaultText = "default text"
   return something
}

Force a method to get the struct (the constructor way). From this post: A good design is to make your type unexported, but provide an exported constructor function like NewMyType() in which you can properly initialize your struct / type. Also return an interface type and not a concrete type, and the interface should contain everything others want to do with your value. And your concrete type must implement that interface of course. This can be done by simply making the type itself unexported. You can export the function NewSomething and even the fields Text and DefaultText, but just don't export the struct type something. Another way to customize it for you own module is by using a Config struct to set default values (Option 5 in the link). Not a good way though.

我发现这个帖子很有帮助，也很有教育意义。其他答案已经提供了很好的指导，但我想用一个易于参考的方法总结我的结论(即复制粘贴):

package main

import (
    "fmt"
)

// Define an interface that is exported by your package.
type Foo interface {
  GetValue() string // A function that'll return the value initialized with a default.
  SetValue(v string) // A function that can update the default value.
}

// Define a struct type that is not exported by your package.
type foo struct {
  value string
}

// A factory method to initialize an instance of `foo`,
// the unexported struct, with a default value.
func NewFoo() Foo {
  return &foo{
    value: "I am the DEFAULT value.",
  }
}

// Implementation of the interface's `GetValue`
// for struct `foo`.
func (f *foo) GetValue() string {
  return f.value
}

// Implementation of the interface's `SetValue`
// for struct `foo`.
func (f *foo) SetValue(v string) {
  f.value = v
}

func main() {
  f := NewFoo()
  fmt.Printf("value: `%s`\n", f.GetValue())
  f.SetValue("I am the UPDATED value.")
  fmt.Printf("value: `%s`\n", f.GetValue())
}

选项1的一个问题是 Victor Zamanian认为，如果没有导出类型，那么包的用户就不能将其声明为函数参数的类型等。解决这个问题的一种方法是导出一个接口，而不是输出结构。

package candidate
// Exporting interface instead of struct
type Candidate interface {}
// Struct is not exported
type candidate struct {
    Name string
    Votes uint32 // Defaults to 0
}
// We are forced to call the constructor to get an instance of candidate
func New(name string) Candidate {
    return candidate{name, 0}  // enforce the default value here
}

这允许我们使用导出的Candidate接口声明函数参数类型。 我从这个解决方案中看到的唯一缺点是，我们所有的方法都需要在接口定义中声明，但你可能会说这是一种很好的实践。

有一种使用标签的方法 允许多个默认值。

假设您有以下结构，默认有2个 标记default0和default1。

type A struct {
   I int    `default0:"3" default1:"42"`
   S string `default0:"Some String..." default1:"Some Other String..."`
}

现在可以设置默认值了。

func main() {

ptr := &A{}

Set(ptr, "default0")
fmt.Printf("ptr.I=%d ptr.S=%s\n", ptr.I, ptr.S)
// ptr.I=3 ptr.S=Some String...

Set(ptr, "default1")
fmt.Printf("ptr.I=%d ptr.S=%s\n", ptr.I, ptr.S)
// ptr.I=42 ptr.S=Some Other String...
}

这是一个操场上的完整程序。

如果你对一个更复杂的例子感兴趣，可以说with 切片和映射，然后，看看creasty/defaultse