在我重新发明这个特殊的轮子之前,有没有人有一个很好的用Python计算目录大小的例程?如果该例程能以Mb/Gb等格式格式化大小,那就太好了。
当前回答
使用pathlib,我想出了这个一行程序来获取文件夹的大小:
sum(file.stat().st_size for file in Path(folder).rglob('*'))
这是我为一个漂亮的格式化输出:
from pathlib import Path
def get_folder_size(folder):
return ByteSize(sum(file.stat().st_size for file in Path(folder).rglob('*')))
class ByteSize(int):
_KB = 1024
_suffixes = 'B', 'KB', 'MB', 'GB', 'PB'
def __new__(cls, *args, **kwargs):
return super().__new__(cls, *args, **kwargs)
def __init__(self, *args, **kwargs):
self.bytes = self.B = int(self)
self.kilobytes = self.KB = self / self._KB**1
self.megabytes = self.MB = self / self._KB**2
self.gigabytes = self.GB = self / self._KB**3
self.petabytes = self.PB = self / self._KB**4
*suffixes, last = self._suffixes
suffix = next((
suffix
for suffix in suffixes
if 1 < getattr(self, suffix) < self._KB
), last)
self.readable = suffix, getattr(self, suffix)
super().__init__()
def __str__(self):
return self.__format__('.2f')
def __repr__(self):
return '{}({})'.format(self.__class__.__name__, super().__repr__())
def __format__(self, format_spec):
suffix, val = self.readable
return '{val:{fmt}} {suf}'.format(val=val, fmt=format_spec, suf=suffix)
def __sub__(self, other):
return self.__class__(super().__sub__(other))
def __add__(self, other):
return self.__class__(super().__add__(other))
def __mul__(self, other):
return self.__class__(super().__mul__(other))
def __rsub__(self, other):
return self.__class__(super().__sub__(other))
def __radd__(self, other):
return self.__class__(super().__add__(other))
def __rmul__(self, other):
return self.__class__(super().__rmul__(other))
用法:
>>> size = get_folder_size("c:/users/tdavis/downloads")
>>> print(size)
5.81 GB
>>> size.GB
5.810891855508089
>>> size.gigabytes
5.810891855508089
>>> size.PB
0.005674699077644618
>>> size.MB
5950.353260040283
>>> size
ByteSize(6239397620)
我还遇到了这个问题,它有一些更紧凑、可能更高效的打印文件大小的策略。
其他回答
递归的一行代码:
def getFolderSize(p):
from functools import partial
prepend = partial(os.path.join, p)
return sum([(os.path.getsize(f) if os.path.isfile(f) else getFolderSize(f)) for f in map(prepend, os.listdir(p))])
你说一句俏皮话… 这里有一句话:
sum([sum(map(lambda fname: os.path.getsize(os.path.join(directory, fname)), files)) for directory, folders, files in os.walk(path)])
尽管我可能会把它分开,它不执行检查。
要转换为kb,请参阅可重用库以获得人类可读版本的文件大小?然后算进去
当计算子目录的大小时,它应该更新其父目录的文件夹大小,这将一直进行下去,直到它到达根父目录。
下面的函数计算文件夹及其所有子文件夹的大小。
import os
def folder_size(path):
parent = {} # path to parent path mapper
folder_size = {} # storing the size of directories
folder = os.path.realpath(path)
for root, _, filenames in os.walk(folder):
if root == folder:
parent[root] = -1 # the root folder will not have any parent
folder_size[root] = 0.0 # intializing the size to 0
elif root not in parent:
immediate_parent_path = os.path.dirname(root) # extract the immediate parent of the subdirectory
parent[root] = immediate_parent_path # store the parent of the subdirectory
folder_size[root] = 0.0 # initialize the size to 0
total_size = 0
for filename in filenames:
filepath = os.path.join(root, filename)
total_size += os.stat(filepath).st_size # computing the size of the files under the directory
folder_size[root] = total_size # store the updated size
temp_path = root # for subdirectories, we need to update the size of the parent till the root parent
while parent[temp_path] != -1:
folder_size[parent[temp_path]] += total_size
temp_path = parent[temp_path]
return folder_size[folder]/1000000.0
使用pathlib,我想出了这个一行程序来获取文件夹的大小:
sum(file.stat().st_size for file in Path(folder).rglob('*'))
这是我为一个漂亮的格式化输出:
from pathlib import Path
def get_folder_size(folder):
return ByteSize(sum(file.stat().st_size for file in Path(folder).rglob('*')))
class ByteSize(int):
_KB = 1024
_suffixes = 'B', 'KB', 'MB', 'GB', 'PB'
def __new__(cls, *args, **kwargs):
return super().__new__(cls, *args, **kwargs)
def __init__(self, *args, **kwargs):
self.bytes = self.B = int(self)
self.kilobytes = self.KB = self / self._KB**1
self.megabytes = self.MB = self / self._KB**2
self.gigabytes = self.GB = self / self._KB**3
self.petabytes = self.PB = self / self._KB**4
*suffixes, last = self._suffixes
suffix = next((
suffix
for suffix in suffixes
if 1 < getattr(self, suffix) < self._KB
), last)
self.readable = suffix, getattr(self, suffix)
super().__init__()
def __str__(self):
return self.__format__('.2f')
def __repr__(self):
return '{}({})'.format(self.__class__.__name__, super().__repr__())
def __format__(self, format_spec):
suffix, val = self.readable
return '{val:{fmt}} {suf}'.format(val=val, fmt=format_spec, suf=suffix)
def __sub__(self, other):
return self.__class__(super().__sub__(other))
def __add__(self, other):
return self.__class__(super().__add__(other))
def __mul__(self, other):
return self.__class__(super().__mul__(other))
def __rsub__(self, other):
return self.__class__(super().__sub__(other))
def __radd__(self, other):
return self.__class__(super().__add__(other))
def __rmul__(self, other):
return self.__class__(super().__rmul__(other))
用法:
>>> size = get_folder_size("c:/users/tdavis/downloads")
>>> print(size)
5.81 GB
>>> size.GB
5.810891855508089
>>> size.gigabytes
5.810891855508089
>>> size.PB
0.005674699077644618
>>> size.MB
5950.353260040283
>>> size
ByteSize(6239397620)
我还遇到了这个问题,它有一些更紧凑、可能更高效的打印文件大小的策略。
要获取一个文件的大小,可以使用os.path.getsize()
>>> import os
>>> os.path.getsize("/path/file")
35L
它以字节为单位报告。
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