如何在不使用第三方库的情况下使用Node.js下载文件?

我不需要什么特别的东西。我只想从给定的URL下载文件,然后将其保存到给定的目录。


当前回答

你可以使用https://github.com/douzi8/ajax-request#download

request.download('http://res.m.ctrip.com/html5/Content/images/57.png', 
  function(err, res, body) {}
);

其他回答

使用promise下载,它解析可读流。添加额外的逻辑来处理重定向。

var http = require('http');
var promise = require('bluebird');
var url = require('url');
var fs = require('fs');
var assert = require('assert');

function download(option) {
    assert(option);
    if (typeof option == 'string') {
        option = url.parse(option);
    }

    return new promise(function(resolve, reject) {
        var req = http.request(option, function(res) {
            if (res.statusCode == 200) {
                resolve(res);
            } else {
                if (res.statusCode === 301 && res.headers.location) {
                    resolve(download(res.headers.location));
                } else {
                    reject(res.statusCode);
                }
            }
        })
        .on('error', function(e) {
            reject(e);
        })
        .end();
    });
}

download('http://localhost:8080/redirect')
.then(function(stream) {
    try {

        var writeStream = fs.createWriteStream('holyhigh.jpg');
        stream.pipe(writeStream);

    } catch(e) {
        console.error(e);
    }
});
var requestModule=require("request");

requestModule(filePath).pipe(fs.createWriteStream('abc.zip'));
var fs = require('fs'),
    request = require('request');

var download = function(uri, filename, callback){
    request.head(uri, function(err, res, body){
    console.log('content-type:', res.headers['content-type']);
    console.log('content-length:', res.headers['content-length']);
    request(uri).pipe(fs.createWriteStream(filename)).on('close', callback);

    }); 
};   

download('https://www.cryptocompare.com/media/19684/doge.png', 'icons/taskks12.png', function(){
    console.log('done');
});

您可以创建一个HTTP GET请求,并将其响应管道到可写文件流:

const http = require('http'); // or 'https' for https:// URLs
const fs = require('fs');

const file = fs.createWriteStream("file.jpg");
const request = http.get("http://i3.ytimg.com/vi/J---aiyznGQ/mqdefault.jpg", function(response) {
   response.pipe(file);

   // after download completed close filestream
   file.on("finish", () => {
       file.close();
       console.log("Download Completed");
   });
});

如果您希望支持在命令行上收集信息(比如指定目标文件或目录或URL),可以使用类似Commander的工具。

更详细的解释在https://sebhastian.com/nodejs-download-file/

编写自己的解决方案,因为现有的不符合我的要求。

包括:

HTTPS下载(http下载时切换包到http) 基于承诺的函数 处理转发路径(状态302) 浏览器头-需要在一些cdn 来自URL的文件名(以及硬编码) 错误处理

打印出来的,更安全。如果你使用的是纯JS(没有Flow,没有TS),可以随意删除类型,或者转换为.d。ts文件

index.js

import httpsDownload from httpsDownload;
httpsDownload('https://example.com/file.zip', './');

httpsDownload.[js|ts]

import https from "https";
import fs from "fs";
import path from "path";

function download(
  url: string,
  folder?: string,
  filename?: string
): Promise<void> {
  return new Promise((resolve, reject) => {
    const req = https
      .request(url, { headers: { "User-Agent": "javascript" } }, (response) => {
        if (response.statusCode === 302 && response.headers.location != null) {
          download(
            buildNextUrl(url, response.headers.location),
            folder,
            filename
          )
            .then(resolve)
            .catch(reject);
          return;
        }

        const file = fs.createWriteStream(
          buildDestinationPath(url, folder, filename)
        );
        response.pipe(file);
        file.on("finish", () => {
          file.close();
          resolve();
        });
      })
      .on("error", reject);
    req.end();
  });
}

function buildNextUrl(current: string, next: string) {
  const isNextUrlAbsolute = RegExp("^(?:[a-z]+:)?//").test(next);
  if (isNextUrlAbsolute) {
    return next;
  } else {
    const currentURL = new URL(current);
    const fullHost = `${currentURL.protocol}//${currentURL.hostname}${
      currentURL.port ? ":" + currentURL.port : ""
    }`;
    return `${fullHost}${next}`;
  }
}

function buildDestinationPath(url: string, folder?: string, filename?: string) {
  return path.join(folder ?? "./", filename ?? generateFilenameFromPath(url));
}

function generateFilenameFromPath(url: string): string {
  const urlParts = url.split("/");
  return urlParts[urlParts.length - 1] ?? "";
}

export default download;