如何在Android应用程序中获取当前时间和日期?


当前回答

Java

Long date=System.currentTimeMillis();
SimpleDateFormat dateFormat =new SimpleDateFormat("dd / MMMM / yyyy - HH:mm", Locale.getDefault());
String dateStr = dateFormat.format(date);

科特林

日期(毫秒)和13位数字(十六进制到日期)

val date=System.currentTimeMillis() //here the date comes in 13 digits
val dtlong = Date(date)
val sdfdate = SimpleDateFormat(pattern, Locale.getDefault()).format(dtlong)

日期格式化程序

"dd / MMMM / yyyy - HH:mm" -> 29 / April / 2022 - 12:03 
"dd / MM / yyyy" -> 29 / 03 / 2022
"dd / MMM / yyyy" -> 29 / Mar / 2022 (shortens the month) 
"EEE, d MMM yyyy HH:mm:ss" -> Wed, 4 Jul 2022 12:08:56

其他回答

好吧,我有一些问题的答案的API,所以我融合了这段代码:

Time t = new Time(Time.getCurrentTimezone());
t.setToNow();
String date1 = t.format("%Y/%m/%d");

Date date = new Date(System.currentTimeMillis());
SimpleDateFormat dateFormat = new SimpleDateFormat("hh:mm aa", Locale.ENGLISH);
String var = dateFormat.format(date);
String horafecha = var+ " - " + date1;

tvTime.setText(horafecha);

输出:

03:25 PM - 2017/10/03
final Calendar c = Calendar.getInstance();
int mYear = c.get(Calendar.YEAR);
int mMonth = c.get(Calendar.MONTH);
int mDay = c.get(Calendar.DAY_OF_MONTH);

textView.setText("" + mDay + "-" + mMonth + "-" + mYear);

试着用简单的方法获取当前的日期和时间:

SimpleDateFormat sdf = new SimpleDateFormat("yyyy.MM.dd G 'at' HH:mm:ss z");
String currentDateandTime = sdf.format(new Date());

您应该根据新的API使用calendar类。Date类现在已弃用。

Calendar cal = Calendar.getInstance();

String date = "" + cal.get(Calendar.DATE) + "-" + (cal.get(Calendar.MONTH)+1) + "-" + cal.get(Calendar.YEAR);

String time = "" + cal.get(Calendar.HOUR_OF_DAY) + ":" + cal.get(Calendar.MINUTE);

如果需要当前日期:

Calendar cc = Calendar.getInstance();
int year = cc.get(Calendar.YEAR);
int month = cc.get(Calendar.MONTH);
int mDay = cc.get(Calendar.DAY_OF_MONTH);
System.out.println("Date", year + ":" + month + ":" + mDay);

如果需要当前时间:

 int mHour = cc.get(Calendar.HOUR_OF_DAY);
 int mMinute = cc.get(Calendar.MINUTE);
 System.out.println("time_format" + String.format("%02d:%02d", mHour , mMinute));