您可以尝试下面的代码删除文件或文件夹，而不管它们是空的还是非空的。

import shutil
import os

directory = "path/to/the/root/folder"
files_in_directory = os.listdir(directory)

for file in files_in_directory:
    try:
        path_to_file_or_folder = os.path.join(directory, file)
        shutil.rmtree(path_to_file_or_folder)
    except:
        os.unlink(path_to_file_or_folder)

删除一个文件夹，即使它可能不存在(避免Charles Chow回答中的竞态条件)，但当其他事情出错时仍然有错误(例如权限问题，磁盘读取错误，文件不是目录)

对于Python 3.x:

import shutil

def ignore_absent_file(func, path, exc_inf):
    except_instance = exc_inf[1]
    if isinstance(except_instance, FileNotFoundError):
        return
    raise except_instance

shutil.rmtree(dir_to_delete, onerror=ignore_absent_file)

Python 2.7的代码几乎是一样的:

import shutil
import errno

def ignore_absent_file(func, path, exc_inf):
    except_instance = exc_inf[1]
    if isinstance(except_instance, OSError) and \
        except_instance.errno == errno.ENOENT:
        return
    raise except_instance

shutil.rmtree(dir_to_delete, onerror=ignore_absent_file)

在我的情况下，删除的唯一方法是使用所有的可能性，因为我的代码应该运行cmd.exe或powershell.exe。如果是你的情况，只需要用下面的代码创建一个函数就可以了:

        #!/usr/bin/env python3

        import shutil
        from os import path, system
        import sys

        # Try to delete the folder ---------------------------------------------
        if (path.isdir(folder)):
            shutil.rmtree(folder, ignore_errors=True)

        if (path.isdir(folder)):
            try:
                system("rd -r {0}".format(folder))
            except Exception as e:
                print("WARN: Failed to delete => {0}".format(e),file=sys.stderr)

        if (path.isdir(self.backup_folder_wrk)):
            try:
                system("rd /s /q {0}".format(folder))
            except Exception as e:
                print("WARN: Failed to delete => {0}".format(e),file=sys.stderr)

        if (path.isdir(folder)):
            print("WARN: Failed to delete {0}".format(folder),file=sys.stderr)
        # -------------------------------------------------------------------------------------

如果你确定你想要删除整个目录树，并且不再对目录的内容感兴趣，那么爬行整个目录树是愚蠢的…只需从python中调用本机操作系统命令即可。它将更快，更有效，更少的内存消耗。

RMDIR c:\blah /s /q 

例如*那晚尼克斯。

rm -rf /home/whatever 

在python中，代码看起来像..

import sys
import os

mswindows = (sys.platform == "win32")

def getstatusoutput(cmd):
    """Return (status, output) of executing cmd in a shell."""
    if not mswindows:
        return commands.getstatusoutput(cmd)
    pipe = os.popen(cmd + ' 2>&1', 'r')
    text = pipe.read()
    sts = pipe.close()
    if sts is None: sts = 0
    if text[-1:] == '\n': text = text[:-1]
    return sts, text


def deleteDir(path):
    """deletes the path entirely"""
    if mswindows: 
        cmd = "RMDIR "+ path +" /s /q"
    else:
        cmd = "rm -rf "+path
    result = getstatusoutput(cmd)
    if(result[0]!=0):
        raise RuntimeError(result[1])

import shutil
shutil.rmtree(dest, ignore_errors=True)

如果你不想使用shutil模块，你可以使用os模块。

from os import listdir, rmdir, remove
for i in listdir(directoryToRemove):
    os.remove(os.path.join(directoryToRemove, i))
rmdir(directoryToRemove) # Now the directory is empty of files