如何在Python中声明常量?

在Java中,我们做:

public static final String CONST_NAME = "Name";

当前回答

我为python const写了一个util lib: Kkconst - pypi 支持str, int, float, datetime

const字段实例将保持其基类型行为。

例如:

from __future__ import print_function
from kkconst import (
    BaseConst,
    ConstFloatField,
)

class MathConst(BaseConst):
    PI = ConstFloatField(3.1415926, verbose_name=u"Pi")
    E = ConstFloatField(2.7182818284, verbose_name=u"mathematical constant")  # Euler's number"
    GOLDEN_RATIO = ConstFloatField(0.6180339887, verbose_name=u"Golden Ratio")

magic_num = MathConst.GOLDEN_RATIO
assert isinstance(magic_num, ConstFloatField)
assert isinstance(magic_num, float)

print(magic_num)  # 0.6180339887
print(magic_num.verbose_name)  # Golden Ratio

更多详细用法,你可以阅读pypi url: Pypi或github

其他回答

在Python中,不能将变量或值声明为常量。


为了让程序员知道变量是常量,通常用大写:

CONST_NAME = "Name"

要在常量发生变化时引发异常,请参阅Alex Martelli的《Python中的常量》。注意,这在实践中并不常用。


从Python 3.8开始,有一个类型。最后一个变量注释,它将告诉静态类型检查器(如myypy)您的变量不应该被重新分配。这是最接近于Java的final。然而,它实际上并不能阻止重新分配:

from typing import Final

a: Final[int] = 1

# Executes fine, but mypy will report an error if you run mypy on this:
a = 2

也许pconst库会帮助你(github)。

$ PIP安装pconst

from pconst import const
const.APPLE_PRICE = 100
const.APPLE_PRICE = 200

“APPLE_PRICE”的常量值不可编辑。

你可以使用StringVar或IntVar等,你的常量是const_val

val = 'Stackoverflow'
const_val = StringVar(val)
const.trace('w', reverse)

def reverse(*args):
    const_val.set(val)

我最近发现了一个非常简洁的更新,它会自动引发有意义的错误消息,并阻止通过__dict__访问:

class CONST(object):
    __slots__ = ()
    FOO = 1234

CONST = CONST()

# ----------

print(CONST.FOO)    # 1234

CONST.FOO = 4321              # AttributeError: 'CONST' object attribute 'FOO' is read-only
CONST.__dict__['FOO'] = 4321  # AttributeError: 'CONST' object has no attribute '__dict__'
CONST.BAR = 5678              # AttributeError: 'CONST' object has no attribute 'BAR'

我们将自己定义为一个实例,然后使用插槽来确保不能添加其他属性。这也删除了__dict__访问路由。当然,整个对象仍然可以重新定义。

编辑-原始解决方案

我可能忽略了一个技巧,但这似乎对我有用:

class CONST(object):
    FOO = 1234

    def __setattr__(self, *_):
        pass

CONST = CONST()

#----------

print CONST.FOO    # 1234

CONST.FOO = 4321
CONST.BAR = 5678

print CONST.FOO    # Still 1234!
print CONST.BAR    # Oops AttributeError

创建实例允许神奇的__setattr__方法介入并拦截设置FOO变量的尝试。如果您愿意,可以在这里抛出异常。通过类名实例化实例可以防止直接通过类进行访问。

对于一个值来说,这非常麻烦,但是您可以将许多值附加到CONST对象上。有一个上层的类,类名似乎也有点难看,但我认为它总体上是相当简洁的。

我知道这是一个老问题,但由于新的解决方案仍在添加,我想使可能的解决方案列表更加完整。你可以通过从类中继承属性来实现实例中的常量,如下所示:

class ConstantError(Exception):
    pass  # maybe give nice error message

class AllowConstants:
    _constants = None
    _class_constants = None

    def __init__(self):
        self._constants = {}
        if self._class_constants is not None:
            self._constants.update(self._class_constants)

    def constant(self, name, value):
        assert isinstance(name, str)
        assert self._constants is not None, "AllowConstants was not initialized"
        if name in self._constants or name in self.__dict__:
            raise ConstantError(name)
        self._constants[name] = value

    def __getattr__(self, attr):
        if attr in self._constants:
            return self._constants[attr]
        raise AttributeError(attr)

    def __setattr__(self, attr, val):
        if self._constants is None:
            # not finished initialization
            self.__dict__[attr] = val
        else:
            if attr in self._constants:
                raise ConstantError(attr)
            else:
                self.__dict__[attr] = val

    def __dir__(self):
        return super().__dir__() + list(self._constants.keys())

子类化this时,你创建的常量将受到保护:

class Example(AllowConstants):
    def __init__(self, a, b):
        super().__init__()
        self.constant("b", b)
        self.a = a

    def try_a(self, value):
        self.a = value

    def try_b(self, value):
        self.b = value

    def __str__(self):
        return str({"a": self.a, "b": self.b})

    def __repr__(self):
        return self.__str__()


example = Example(1, 2)
print(example)  # {'a': 1, 'b': 2}

example.try_a(5)
print(example)  # {'a': 5, 'b': 2}

example.try_b(6)  # ConstantError: b

example.a = 7
print(example)  # {'a': 7, 'b': 2}

example.b = 8  # ConstantError: b

print(hasattr(example, "b"))  # True

#  To show that constants really do immediately become constant: 

class AnotherExample(AllowConstants):
    def __init__(self):
        super().__init__()
        self.constant("a", 2)
        print(self.a)
        self.a=3


AnotherExample()  # 2  ConstantError: a


# finally, for class constants:
class YetAnotherExample(Example):
    _class_constants = {
        'BLA': 3
    }

    def __init__(self, a, b):
        super().__init__(a,b)

    def try_BLA(self, value):
        self.BLA = value

ex3 = YetAnotherExample(10, 20)
ex3.BLA  # 3
ex3.try_BLA(10)  # ConstantError: BLA
ex3.BLA = 4  # ConstantError: BLA

常量是局部的(从AllowConstants继承的类的每个实例都有自己的常量),只要它们没有被重新赋值,就像普通的属性一样,并且编写从这个继承的类允许或多或少与支持常量的语言相同的风格。

此外,如果您想通过直接访问实例来防止任何人更改值。_constants,您可以使用其他答案中建议的许多不允许这样做的容器之一。最后,如果你真的觉得有必要,你可以阻止人们设置所有的实例。通过AllowConstants的更多属性访问,将_constants赋给一个新字典。(当然,这些都不是非常python化的,但这不是重点)。

编辑(因为使python非python化是一个有趣的游戏):为了使继承更容易一点,你可以修改AllowConstants如下:

class AllowConstants:
    _constants = None
    _class_constants = None

    def __init__(self):
        self._constants = {}
        self._update_class_constants()

    def __init_subclass__(cls):
        """
        Without this, it is necessary to set _class_constants in any subclass of any class that has class constants
        """
        if cls._class_constants is not None:
            #prevent trouble where _class_constants is not overwritten
            possible_cases = cls.__mro__[1:-1] #0 will have cls and -1 will have object
            for case in possible_cases:
                if cls._class_constants is case._class_constants:
                    cls._class_constants = None
                    break

    def _update_class_constants(self):
        """
        Help with the inheritance of class constants
        """
        for superclass in self.__class__.__mro__:
            if hasattr(superclass, "_class_constants"):
                sccc = superclass._class_constants
                if sccc is not None:
                    for key in sccc:
                        if key in self._constants:
                            raise ConstantError(key)
                    self._constants.update(sccc)

    def constant(self, name, value):
        assert isinstance(name, str)
        assert self._constants is not None, "AllowConstants was not initialized"
        if name in self._constants or name in self.__dict__:
            raise ConstantError(name)
        self._constants[name] = value

    def __getattr__(self, attr):
        if attr in self._constants:
            return self._constants[attr]
        raise AttributeError(attr)

    def __setattr__(self, attr, val):
        if self._constants is None:
            # not finished initialization
            self.__dict__[attr] = val
        else:
            if attr in self._constants:
                raise ConstantError(attr)
            else:
                self.__dict__[attr] = val

    def __dir__(self):
        return super().__dir__() + list(self._constants.keys())

这样你就可以:

class Example(AllowConstants):
    _class_constants = {
        "BLA": 2
    }
    def __init__(self, a, b):
        super().__init__()
        self.constant("b", b)
        self.a = a

    def try_a(self, value):
        self.a = value

    def try_b(self, value):
        self.b = value

    def __str__(self):
        return str({"a": self.a, "b": self.b})

    def __repr__(self):
        return self.__str__()


class ChildExample1(Example):
    _class_constants = {
        "BLI": 88
    }


class ChildExample2(Example):
    _class_constants = {
        "BLA": 44
    }


example = ChildExample1(2,3)
print(example.BLA)  # 2
example.BLA = 8  # ConstantError BLA
print(example.BLI)  # 88
example.BLI = 8  # ConstantError BLI

example = ChildExample2(2,3)  # ConstantError BLA