我需要做一件非常简单的事情-找出软件键盘是否显示。这在Android中可行吗?


当前回答

就计算机而言,这是永远的问题,但这个问题仍然令人难以置信地相关! 所以我把上面的答案结合起来,做了一些改进……

public interface OnKeyboardVisibilityListener {
    void onVisibilityChanged(boolean visible);
}

public final void setKeyboardListener(final OnKeyboardVisibilityListener listener) {
    final View activityRootView = ((ViewGroup) getActivity().findViewById(android.R.id.content)).getChildAt(0);
    activityRootView.getViewTreeObserver().addOnGlobalLayoutListener(new OnGlobalLayoutListener() {

        private boolean wasOpened;

    private final Rect r = new Rect();

        @Override
        public void onGlobalLayout() {
            activityRootView.getWindowVisibleDisplayFrame(r);

            int heightDiff = activityRootView.getRootView().getHeight() - (r.bottom - r.top);
            boolean isOpen = heightDiff > 100;
            if (isOpen == wasOpened) {
                logDebug("Ignoring global layout change...");
                return;
            }

            wasOpened = isOpen;
            listener.onVisibilityChanged(isOpen);
        }
    });
}

这对我很管用。

其他回答

有一个隐藏的方法可以帮助这个,inputmethodmanager。getinputmethodwindowvisibleheight。但我不知道为什么要藏起来。

import android.content.Context
import android.os.Handler
import android.view.inputmethod.InputMethodManager

class SoftKeyboardStateWatcher(private val ctx: Context) {
  companion object {
    private const val DELAY = 10L
  }

  private val handler = Handler()
  private var isSoftKeyboardOpened: Boolean = false

  private val height: Int
    get() {
      val imm = ctx.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
      val method = imm.javaClass.getMethod("getInputMethodWindowVisibleHeight")
      method.isAccessible = true
      return method.invoke(imm) as Int
    }

  private val task: Runnable by lazy {
    Runnable {
      start()
      if (!isSoftKeyboardOpened && height > 0) {
        isSoftKeyboardOpened = true
        notifyOnSoftKeyboardOpened(height)
      } else if (isSoftKeyboardOpened && height == 0) {
        isSoftKeyboardOpened = false
        notifyOnSoftKeyboardClosed()
      }
    }
  }

  var listener: SoftKeyboardStateListener? = null

  interface SoftKeyboardStateListener {
    fun onSoftKeyboardOpened(keyboardHeightInPx: Int)
    fun onSoftKeyboardClosed()
  }

  fun start() {
    handler.postDelayed(task, DELAY)
  }

  fun stop() {
    handler.postDelayed({
      if (!isSoftKeyboardOpened) handler.removeCallbacks(task)
    }, DELAY * 10)
  }

  private fun notifyOnSoftKeyboardOpened(keyboardHeightInPx: Int) {
    listener?.onSoftKeyboardOpened(keyboardHeightInPx)
  }

  private fun notifyOnSoftKeyboardClosed() {
    listener?.onSoftKeyboardClosed()
  }
}

我知道这是一篇老文章,但我认为这是我所知道的最简单的方法,我的测试设备是Nexus 5。我还没有在其他设备上尝试过。希望其他人会分享他们的方法,如果他们发现我的代码不好:)

public static boolean isKeyboardShown(Context context, View view) {
        if (context == null || view == null) {
            return false;
        }
        InputMethodManager imm = (InputMethodManager) context
                .getSystemService(Context.INPUT_METHOD_SERVICE);
        return imm.hideSoftInputFromWindow(view.getWindowToken(), 0); 
}

imm。hideSoftInputFromWindow返回布尔值。

谢谢,

这个解决方案可能会重新打开键盘,但它是有效的。

InputMethodManager inputManager = ( (InputMethodManager) this.getSystemService(Context.INPUT_METHOD_SERVICE) );

private boolean isKeyboardShowing() {

    boolean isKeyboardShowing = inputManager.hideSoftInputFromWindow(irrelevantView.getWindowToken(), 0);
    if (isKeyboardShowing) {
        inputManager.showSoftInput(this.getCurrentFocus(), 0);
    }
    return isKeyboardShowing;
}

这里有一个工作区,以了解软键盘是否可见。

检查系统上正在运行的服务 ActivityManager.getRunningServices (max_count_of_services); 从返回的ActivityManager。运行ningserviceinfo实例,检查软键盘服务的clientCount值。 前面提到的clientCount将在每次显示软键盘时递增。例如,如果clientCount为 一开始是1,显示键盘时是2。 在键盘撤销时,clientCount递减。在本例中,它重置为1。

一些流行的键盘在它们的classname中有特定的关键字:

Google AOSP = IME
Swype = IME
Swiftkey = KeyboardService
Fleksy = keyboard
Adaptxt = IME (KPTAdaptxtIME)
Smart = Keyboard (SmartKeyboard)

从ActivityManager。RunningServiceInfo,在ClassNames中检查上述模式。同时,ActivityManager。RunningServiceInfo的clientPackage=android,表示键盘绑定到系统。

可以将上述信息进行严格的组合,以判断软键盘是否可见。

这些解决方案都不适用于棒棒糖。在Lollipop activityRootView.getRootView(). getheight()包含按钮栏的高度,而测量视图则不包含。我已经采用了上面最好/最简单的解决方案来处理棒棒糖。

    final View activityRootView = findViewById(R.id.activityRoot);
activityRootView.getViewTreeObserver().addOnGlobalLayoutListener(new OnGlobalLayoutListener() {
  @Override
  public void onGlobalLayout() {
    Rect r = new Rect();
    //r will be populated with the coordinates of your view that area still visible.
    activityRootView.getWindowVisibleDisplayFrame(r);

    int heightDiff = activityRootView.getRootView().getHeight() - (r.bottom - r.top);
    Resources res = getResources();
    // The status bar is 25dp, use 50dp for assurance
    float maxDiff =
        TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, 50, res.getDisplayMetrics());

    //Lollipop includes button bar in the root. Add height of button bar (48dp) to maxDiff
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {
      float buttonBarHeight =
          TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, 48, res.getDisplayMetrics());
      maxDiff += buttonBarHeight;
    }
    if (heightDiff > maxDiff) { // if more than 100 pixels, its probably a keyboard...
      ...do something here
    }
  }
});