如何使用PHP找到两个日期之间的天数?


当前回答

$datediff = floor(strtotime($date1)/(60*60*24)) - floor(strtotime($date2)/(60*60*24));

如果需要的话:

$datediff=abs($datediff);

其他回答

面向对象的风格:

$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');

程序上的风格:

$datetime1 = date_create('2009-10-11');
$datetime2 = date_create('2009-10-13');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a days');

如果你有以秒为单位的时间(即unix时间戳),那么你可以简单地减去时间并除以86400(秒/天)

尝试使用碳

$d1 = \Carbon\Carbon::now()->subDays(92);
$d2 = \Carbon\Carbon::now()->subDays(10);
$days_btw = $d1->diffInDays($d2);

你也可以用

\Carbon\Carbon::parse('')

使用给定的时间戳字符串创建一个Carbon date对象。

易于使用date_diff

$from=date_create(date('Y-m-d'));
$to=date_create("2013-03-15");
$diff=date_diff($to,$from);
print_r($diff);
echo $diff->format('%R%a days');

详见:https://blog.devgenius.io/how-to-find-the-number-of-days-between-two-dates-in-php-1404748b1e84

PHP中两个日期之间的天数

      function dateDiff($date1, $date2)  //days find function
        { 
            $diff = strtotime($date2) - strtotime($date1); 
            return abs(round($diff / 86400)); 
        } 
       //start day
       $date1 = "11-10-2018";        
       // end day
       $date2 = "31-10-2018";    
       // call the days find fun store to variable 
       $dateDiff = dateDiff($date1, $date2); 

       echo "Difference between two dates: ". $dateDiff . " Days ";