如何使用PHP找到两个日期之间的天数?
当前回答
你可以试试下面的代码:
$dt1 = strtotime("2019-12-12"); //Enter your first date
$dt2 = strtotime("12-12-2020"); //Enter your second date
echo abs(($dt1 - $dt2) / (60 * 60 * 24));
其他回答
这段代码为我工作,并用PHP 8版本测试:
function numberOfDays($startDate, $endDate)
{
//1) converting dates to timestamps
$startSeconds = strtotime($startDate);
$endSeconds = strtotime($endDate);
//2) Calculating the difference in timestamps
$diffSeconds = $startSeconds - $endSeconds;
//3) converting timestamps to days
$days=round($diffSeconds / 86400);
/* note :
1 day = 24 hours
24 * 60 * 60 = 86400 seconds
*/
//4) printing the number of days
printf("Difference between two dates: ". abs($days) . " Days ");
return abs($days);
}
如果你正在使用MySql
function daysSince($date, $date2){
$q = "SELECT DATEDIFF('$date','$date2') AS days;";
$result = execQ($q);
$row = mysql_fetch_array($result,MYSQL_BOTH);
return ($row[0]);
}
function execQ($q){
$result = mysql_query( $q);
if(!$result){echo ('Database error execQ' . mysql_error());echo $q;}
return $result;
}
function howManyDays($startDate,$endDate) {
$date1 = strtotime($startDate." 0:00:00");
$date2 = strtotime($endDate." 23:59:59");
$res = (int)(($date2-$date1)/86400);
return $res;
}
PHP中两个日期之间的天数
function dateDiff($date1, $date2) //days find function
{
$diff = strtotime($date2) - strtotime($date1);
return abs(round($diff / 86400));
}
//start day
$date1 = "11-10-2018";
// end day
$date2 = "31-10-2018";
// call the days find fun store to variable
$dateDiff = dateDiff($date1, $date2);
echo "Difference between two dates: ". $dateDiff . " Days ";
易于使用date_diff
$from=date_create(date('Y-m-d'));
$to=date_create("2013-03-15");
$diff=date_diff($to,$from);
print_r($diff);
echo $diff->format('%R%a days');
详见:https://blog.devgenius.io/how-to-find-the-number-of-days-between-two-dates-in-php-1404748b1e84
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