如何使用PHP找到两个日期之间的天数?
当前回答
我阅读了所有以前的解决方案,没有一个使用PHP 5.3工具:DateTime::Diff和DateInterval::Days
DateInterval::Days精确地包含日期之间的天数。没有必要创造一些特别和奇异的东西。
/**
* We suppose that PHP is configured in UTC
* php.ini configuration:
* [Date]
* ; Defines the default timezone used by the date functions
* ; http://php.net/date.timezone
* date.timezone = UTC
* @link http://php.net/date.timezone
*/
/**
* getDaysBetween2Dates
*
* Return the difference of days between $date1 and $date2 ($date1 - $date2)
* if $absolute parameter is false, the return value is negative if $date2 is after than $date1
*
* @param DateTime $date1
* @param DateTime $date2
* @param Boolean $absolute
* = true
* @return integer
*/
function getDaysBetween2Dates(DateTime $date1, DateTime $date2, $absolute = true)
{
$interval = $date2->diff($date1);
// if we have to take in account the relative position (!$absolute) and the relative position is negative,
// we return negatif value otherwise, we return the absolute value
return (!$absolute and $interval->invert) ? - $interval->days : $interval->days;
}
echo '<h3>2020-03-01 - 2020-02-01: 29 days as it\'s a standard leap year</h3>';
echo getDaysBetween2Dates(new DateTime("2020-03-01"), new DateTime("2020-02-01"), false);
echo '<h3>1900-03-01 - 1900-02-01: 28 days as it\'s a "standard" century</h3>';
echo getDaysBetween2Dates(new DateTime("1900-03-01"), new DateTime("1900-02-01"), false);
echo '<h3>2000-03-01 - 2000-02-01: 29 days as it\'s a century multiple of 400: 2000=400x5</h3>';
echo getDaysBetween2Dates(new DateTime("2000-03-01"), new DateTime("2000-02-01"), false);
echo '<h3>2020-03-01 - 2020-04-01: -28 days as 2020-03-01 is before 2020-04-01</h3>';
echo getDaysBetween2Dates(new DateTime("2020-02-01"), new DateTime("2020-03-01"), false);
其他回答
这是我的改进版本,显示1年2月25天(s),如果通过第二个参数。
class App_Sandbox_String_Util {
/**
* Usage: App_Sandbox_String_Util::getDateDiff();
* @param int $your_date timestamp
* @param bool $hr human readable. e.g. 1 year(s) 2 day(s)
* @see http://stackoverflow.com/questions/2040560/finding-the-number-of-days-between-two-dates
* @see http://qSandbox.com
*/
static public function getDateDiff($your_date, $hr = 0) {
$now = time(); // or your date as well
$datediff = $now - $your_date;
$days = floor( $datediff / ( 3600 * 24 ) );
$label = '';
if ($hr) {
if ($days >= 365) { // over a year
$years = floor($days / 365);
$label .= $years . ' Year(s)';
$days -= 365 * $years;
}
if ($days) {
$months = floor( $days / 30 );
$label .= ' ' . $months . ' Month(s)';
$days -= 30 * $months;
}
if ($days) {
$label .= ' ' . $days . ' day(s)';
}
} else {
$label = $days;
}
return $label;
}
}
你可以通过简单的方法找到约会对象
<?php
$start = date_create('1988-08-10');
$end = date_create(); // Current time and date
$diff = date_diff( $start, $end );
echo 'The difference is ';
echo $diff->y . ' years, ';
echo $diff->m . ' months, ';
echo $diff->d . ' days, ';
echo $diff->h . ' hours, ';
echo $diff->i . ' minutes, ';
echo $diff->s . ' seconds';
// Output: The difference is 28 years, 5 months, 19 days, 20 hours, 34 minutes, 36 seconds
echo 'The difference in days : ' . $diff->days;
// Output: The difference in days : 10398
如果你正在使用MySql
function daysSince($date, $date2){
$q = "SELECT DATEDIFF('$date','$date2') AS days;";
$result = execQ($q);
$row = mysql_fetch_array($result,MYSQL_BOTH);
return ($row[0]);
}
function execQ($q){
$result = mysql_query( $q);
if(!$result){echo ('Database error execQ' . mysql_error());echo $q;}
return $result;
}
$start = '2013-09-08';
$end = '2013-09-15';
$diff = (strtotime($end)- strtotime($start))/24/3600;
echo $diff;
如果你使用的是PHP 5.3 >,这是目前为止最准确的计算绝对差值的方法:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$abs_diff = $later->diff($earlier)->format("%a"); //3
如果你需要一个相对的(带符号的)天数,可以用这个代替:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$pos_diff = $earlier->diff($later)->format("%r%a"); //3
$neg_diff = $later->diff($earlier)->format("%r%a"); //-3
更多关于php的DateInterval格式可以在这里找到:https://www.php.net/manual/en/dateinterval.format.php
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