有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?
我知道有一个名为UIDevice.currentDevice()的属性。模型，但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。
我也知道在Objective-C中使用以下方法可以轻松完成:
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我正在Swift中开发我的iPhone应用程序，所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?
当前回答
下面是获取硬件字符串的代码，但是您需要比较这些硬件字符串才能知道它是哪个设备。我已经创建了一个类，包含几乎所有的设备字符串(我们保持字符串最新的新设备)。使用方便，请检查
吉hub /恶魔大师
Objective-C: GitHub/DeviceUtil
public func hardwareString() -> String {
var name: [Int32] = [CTL_HW, HW_MACHINE]
var size: Int = 2
sysctl(&name, 2, nil, &size, &name, 0)
var hw_machine = [CChar](count: Int(size), repeatedValue: 0)
sysctl(&name, 2, &hw_machine, &size, &name, 0)
let hardware: String = String.fromCString(hw_machine)!
return hardware
}
其他回答
我已经实现了一个超轻量级的库，可以根据给出的一些答案来检测使用的设备:https://github.com/schickling/Device.swift
它可以通过迦太基安装，并像这样使用:
import Device
let deviceType = UIDevice.currentDevice().deviceType
switch deviceType {
case .IPhone6: print("Do stuff for iPhone6")
case .IPadMini: print("Do stuff for iPad mini")
default: print("Check other available cases of DeviceType")
}
我发现很多答案都用了字符串。我决定改变@HAS答案使用一个enum:
public enum Devices: String {
case IPodTouch5
case IPodTouch6
case IPhone4
case IPhone4S
case IPhone5
case IPhone5C
case IPhone5S
case IPhone6
case IPhone6Plus
case IPhone6S
case IPhone6SPlus
case IPhone7
case IPhone7Plus
case IPhoneSE
case IPad2
case IPad3
case IPad4
case IPadAir
case IPadAir2
case IPadMini
case IPadMini2
case IPadMini3
case IPadMini4
case IPadPro
case AppleTV
case Simulator
case Other
}
public extension UIDevice {
public var modelName: Devices {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 , value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return Devices.IPodTouch5
case "iPod7,1": return Devices.IPodTouch6
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return Devices.IPhone4
case "iPhone4,1": return Devices.IPhone4S
case "iPhone5,1", "iPhone5,2": return Devices.IPhone5
case "iPhone5,3", "iPhone5,4": return Devices.IPhone5C
case "iPhone6,1", "iPhone6,2": return Devices.IPhone5S
case "iPhone7,2": return Devices.IPhone6
case "iPhone7,1": return Devices.IPhone6Plus
case "iPhone8,1": return Devices.IPhone6S
case "iPhone8,2": return Devices.IPhone6SPlus
case "iPhone9,1", "iPhone9,3": return Devices.IPhone7
case "iPhone9,2", "iPhone9,4": return Devices.IPhone7Plus
case "iPhone8,4": return Devices.IPhoneSE
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return Devices.IPad2
case "iPad3,1", "iPad3,2", "iPad3,3": return Devices.IPad3
case "iPad3,4", "iPad3,5", "iPad3,6": return Devices.IPad4
case "iPad4,1", "iPad4,2", "iPad4,3": return Devices.IPadAir
case "iPad5,3", "iPad5,4": return Devices.IPadAir2
case "iPad2,5", "iPad2,6", "iPad2,7": return Devices.IPadMini
case "iPad4,4", "iPad4,5", "iPad4,6": return Devices.IPadMini2
case "iPad4,7", "iPad4,8", "iPad4,9": return Devices.IPadMini3
case "iPad5,1", "iPad5,2": return Devices.IPadMini4
case "iPad6,3", "iPad6,4", "iPad6,7", "iPad6,8":return Devices.IPadPro
case "AppleTV5,3": return Devices.AppleTV
case "i386", "x86_64": return Devices.Simulator
default: return Devices.Other
}
}
}
在swift中处理c结构体是很痛苦的。尤其是当里面有c数组的时候。以下是我的解决方案:继续使用objective-c。只需创建一个包装器objective-c类来完成这项工作，然后在swift中使用该类。下面是一个示例类，它就是这样做的:
@interface DeviceInfo : NSObject
+ (NSString *)model;
@end
#import "DeviceInfo.h"
#import <sys/utsname.h>
@implementation DeviceInfo
+ (NSString *)model
{
struct utsname systemInfo;
uname(&systemInfo);
return [NSString stringWithCString: systemInfo.machine encoding: NSUTF8StringEncoding];
}
@end
在迅捷的一面:
let deviceModel = DeviceInfo.model()
extension UIDevice {
public static let hardwareModel: String = {
var path = [CTL_HW, HW_MACHINE]
var n = 0
sysctl(&path, 2, nil, &n, nil, 0)
var a: [UInt8] = .init(repeating: 0, count: n)
sysctl(&path, 2, &a, &n, nil, 0)
return .init(cString: a)
}()
}
UIDevice.hardwareModel // → iPhone9,3
我在UIDevice上做了这个“纯Swift”扩展。
如果你正在寻找一个更优雅的解决方案，你可以使用我在GitHub上发布的µ-框架DeviceKit(也可以通过CocoaPods, Carthage和Swift Package Manager获得)。
代码如下:
import UIKit
public extension UIDevice {
static let modelName: String = {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
func mapToDevice(identifier: String) -> String { // swiftlint:disable:this cyclomatic_complexity
#if os(iOS)
switch identifier {
case "iPod5,1": return "iPod touch (5th generation)"
case "iPod7,1": return "iPod touch (6th generation)"
case "iPod9,1": return "iPod touch (7th generation)"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPhone12,1": return "iPhone 11"
case "iPhone12,3": return "iPhone 11 Pro"
case "iPhone12,5": return "iPhone 11 Pro Max"
case "iPhone13,1": return "iPhone 12 mini"
case "iPhone13,2": return "iPhone 12"
case "iPhone13,3": return "iPhone 12 Pro"
case "iPhone13,4": return "iPhone 12 Pro Max"
case "iPhone14,4": return "iPhone 13 mini"
case "iPhone14,5": return "iPhone 13"
case "iPhone14,2": return "iPhone 13 Pro"
case "iPhone14,3": return "iPhone 13 Pro Max"
case "iPhone14,7": return "iPhone 14"
case "iPhone14,8": return "iPhone 14 Plus"
case "iPhone15,2": return "iPhone 14 Pro"
case "iPhone15,3": return "iPhone 14 Pro Max"
case "iPhone8,4": return "iPhone SE"
case "iPhone12,8": return "iPhone SE (2nd generation)"
case "iPhone14,6": return "iPhone SE (3rd generation)"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4": return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad (3rd generation)"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad (4th generation)"
case "iPad6,11", "iPad6,12": return "iPad (5th generation)"
case "iPad7,5", "iPad7,6": return "iPad (6th generation)"
case "iPad7,11", "iPad7,12": return "iPad (7th generation)"
case "iPad11,6", "iPad11,7": return "iPad (8th generation)"
case "iPad12,1", "iPad12,2": return "iPad (9th generation)"
case "iPad13,18", "iPad13,19": return "iPad (10th generation)"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad11,3", "iPad11,4": return "iPad Air (3rd generation)"
case "iPad13,1", "iPad13,2": return "iPad Air (4th generation)"
case "iPad13,16", "iPad13,17": return "iPad Air (5th generation)"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad mini 3"
case "iPad5,1", "iPad5,2": return "iPad mini 4"
case "iPad11,1", "iPad11,2": return "iPad mini (5th generation)"
case "iPad14,1", "iPad14,2": return "iPad mini (6th generation)"
case "iPad6,3", "iPad6,4": return "iPad Pro (9.7-inch)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4": return "iPad Pro (11-inch) (1st generation)"
case "iPad8,9", "iPad8,10": return "iPad Pro (11-inch) (2nd generation)"
case "iPad13,4", "iPad13,5", "iPad13,6", "iPad13,7": return "iPad Pro (11-inch) (3rd generation)"
case "iPad14,3", "iPad14,4": return "iPad Pro (11-inch) (4th generation)"
case "iPad6,7", "iPad6,8": return "iPad Pro (12.9-inch) (1st generation)"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8": return "iPad Pro (12.9-inch) (3rd generation)"
case "iPad8,11", "iPad8,12": return "iPad Pro (12.9-inch) (4th generation)"
case "iPad13,8", "iPad13,9", "iPad13,10", "iPad13,11":return "iPad Pro (12.9-inch) (5th generation)"
case "iPad14,5", "iPad14,6": return "iPad Pro (12.9-inch) (6th generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
case "AudioAccessory5,1": return "HomePod mini"
case "i386", "x86_64", "arm64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "iOS"))"
default: return identifier
}
#elseif os(tvOS)
switch identifier {
case "AppleTV5,3": return "Apple TV 4"
case "AppleTV6,2": return "Apple TV 4K"
case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "tvOS"))"
default: return identifier
}
#endif
}
return mapToDevice(identifier: identifier)
}()
}
你这样称呼它:
let modelName = UIDevice.modelName
对于真实的设备，它返回例如:“iPad Pro(12.9英寸)(第五代)”，对于模拟器，它返回例如。模拟式iPad Pro(12.9英寸)(第五代)
下面是模型参考:
https://theiphonewiki.com/wiki/Models https://theiphonewiki.com/wiki/BORD
