有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?
我知道有一个名为UIDevice.currentDevice()的属性。模型，但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。
我也知道在Objective-C中使用以下方法可以轻松完成:
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我正在Swift中开发我的iPhone应用程序，所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?
当前回答
Swift 3.0或更高版本
import UIKit
class ViewController: UIViewController {
let device = UIDevice.current
override func viewDidLoad() {
super.viewDidLoad()
let model = device.model
print(model) // e.g. "iPhone"
let modelName = device.modelName
print(modelName) // e.g. "iPhone 6" /* see the extension */
let deviceName = device.name
print(deviceName) // e.g. "My iPhone"
let systemName = device.systemName
print(systemName) // e.g. "iOS"
let systemVersion = device.systemVersion
print(systemVersion) // e.g. "10.3.2"
if let identifierForVendor = device.identifierForVendor {
print(identifierForVendor) // e.g. "E1X2XX34-5X6X-7890-123X-XXX456C78901"
}
}
}
并添加以下扩展
extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro 12.9 Inch 2. Generation"
case "iPad7,3", "iPad7,4": return "iPad Pro 10.5 Inch"
case "AppleTV5,3": return "Apple TV"
case "i386", "x86_64": return "Simulator"
default: return identifier
}
}
}
其他回答
斯威夫特3.1
我对简单地调用utsname的看法是:
func platform() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let size = Int(_SYS_NAMELEN) // is 32, but posix AND its init is 256....
let s = withUnsafeMutablePointer(to: &systemInfo.machine) {p in
p.withMemoryRebound(to: CChar.self, capacity: size, {p2 in
return String(cString: p2)
})
}
return s
}
和其他的一样，但对C/Swift和后面的复杂结构更清晰一些。 )：
返回值如"x86_64"
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
使用Swift 3 (Xcode 8.3)
func deviceName() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let str = withUnsafePointer(to: &systemInfo.machine.0) { ptr in
return String(cString: ptr)
}
return str
}
注意:根据官方开发论坛的回答，以这种方式使用元组是安全的。大Int8元组的内存对齐方式将与大Int8数组相同。即:连续且无填充。
我发现很多答案都用了字符串。我决定改变@HAS答案使用一个enum:
public enum Devices: String {
case IPodTouch5
case IPodTouch6
case IPhone4
case IPhone4S
case IPhone5
case IPhone5C
case IPhone5S
case IPhone6
case IPhone6Plus
case IPhone6S
case IPhone6SPlus
case IPhone7
case IPhone7Plus
case IPhoneSE
case IPad2
case IPad3
case IPad4
case IPadAir
case IPadAir2
case IPadMini
case IPadMini2
case IPadMini3
case IPadMini4
case IPadPro
case AppleTV
case Simulator
case Other
}
public extension UIDevice {
public var modelName: Devices {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 , value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return Devices.IPodTouch5
case "iPod7,1": return Devices.IPodTouch6
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return Devices.IPhone4
case "iPhone4,1": return Devices.IPhone4S
case "iPhone5,1", "iPhone5,2": return Devices.IPhone5
case "iPhone5,3", "iPhone5,4": return Devices.IPhone5C
case "iPhone6,1", "iPhone6,2": return Devices.IPhone5S
case "iPhone7,2": return Devices.IPhone6
case "iPhone7,1": return Devices.IPhone6Plus
case "iPhone8,1": return Devices.IPhone6S
case "iPhone8,2": return Devices.IPhone6SPlus
case "iPhone9,1", "iPhone9,3": return Devices.IPhone7
case "iPhone9,2", "iPhone9,4": return Devices.IPhone7Plus
case "iPhone8,4": return Devices.IPhoneSE
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return Devices.IPad2
case "iPad3,1", "iPad3,2", "iPad3,3": return Devices.IPad3
case "iPad3,4", "iPad3,5", "iPad3,6": return Devices.IPad4
case "iPad4,1", "iPad4,2", "iPad4,3": return Devices.IPadAir
case "iPad5,3", "iPad5,4": return Devices.IPadAir2
case "iPad2,5", "iPad2,6", "iPad2,7": return Devices.IPadMini
case "iPad4,4", "iPad4,5", "iPad4,6": return Devices.IPadMini2
case "iPad4,7", "iPad4,8", "iPad4,9": return Devices.IPadMini3
case "iPad5,1", "iPad5,2": return Devices.IPadMini4
case "iPad6,3", "iPad6,4", "iPad6,7", "iPad6,8":return Devices.IPadPro
case "AppleTV5,3": return Devices.AppleTV
case "i386", "x86_64": return Devices.Simulator
default: return Devices.Other
}
}
}
Swift 3.0或更高版本
import UIKit
class ViewController: UIViewController {
let device = UIDevice.current
override func viewDidLoad() {
super.viewDidLoad()
let model = device.model
print(model) // e.g. "iPhone"
let modelName = device.modelName
print(modelName) // e.g. "iPhone 6" /* see the extension */
let deviceName = device.name
print(deviceName) // e.g. "My iPhone"
let systemName = device.systemName
print(systemName) // e.g. "iOS"
let systemVersion = device.systemVersion
print(systemVersion) // e.g. "10.3.2"
if let identifierForVendor = device.identifierForVendor {
print(identifierForVendor) // e.g. "E1X2XX34-5X6X-7890-123X-XXX456C78901"
}
}
}
并添加以下扩展
extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro 12.9 Inch 2. Generation"
case "iPad7,3", "iPad7,4": return "iPad Pro 10.5 Inch"
case "AppleTV5,3": return "Apple TV"
case "i386", "x86_64": return "Simulator"
default: return identifier
}
}
}
