我想从我的应用程序中的URL加载图像,所以我首先尝试了Objective-C和它的工作,但是,与Swift,我有一个编译错误:

'imageWithData'不可用:使用对象构造'UIImage(data:)'

我的函数:

@IBOutlet var imageView : UIImageView

override func viewDidLoad() {
    super.viewDidLoad()

    var url:NSURL = NSURL.URLWithString("http://myURL/ios8.png")
    var data:NSData = NSData.dataWithContentsOfURL(url, options: nil, error: nil)

    imageView.image = UIImage.imageWithData(data)// Error here
}

在objective - c中:

- (void)viewDidLoad {
    [super viewDidLoad];

    NSURL *url = [NSURL URLWithString:(@"http://myURL/ios8.png")];
    NSData *data = [NSData dataWithContentsOfURL:url];

    _imageView.image = [UIImage imageWithData: data];
    _labelURL.text = @"http://www.quentinroussat.fr/assets/img/iOS%20icon's%20Style/ios8.png";
 }

有人能解释一下为什么imageWithData:不能与Swift一起工作,我该如何解决这个问题。


当前回答

Swift 3错误处理

let url = URL(string: arr[indexPath.row] as! String)
if url != nil {
    DispatchQueue.global().async {
        let data = try? Data(contentsOf: url!) //make sure your image in this url does exist, otherwise unwrap in a if let check / try-catch
        DispatchQueue.main.async {
            if data != nil {
                cell.imgView.image = UIImage(data:data!)
            }else{
                cell.imgView.image = UIImage(named: "default.png")
            }
        }
    }
}

与扩展

extension UIImageView {

    func setCustomImage(_ imgURLString: String?) {
        guard let imageURLString = imgURLString else {
            self.image = UIImage(named: "default.png")
            return
        }
        DispatchQueue.global().async { [weak self] in
            let data = try? Data(contentsOf: URL(string: imageURLString)!)
            DispatchQueue.main.async {
                self?.image = data != nil ? UIImage(data: data!) : UIImage(named: "default.png")
            }
        }
    }
}

扩展使用

myImageView. setCustomImage("url")

具有缓存支持

let imageCache = NSCache<NSString, UIImage>()

extension UIImageView {

    func loadImageUsingCacheWithURLString(_ URLString: String, placeHolder: UIImage?) {

        self.image = nil
        if let cachedImage = imageCache.object(forKey: NSString(string: URLString)) {
            self.image = cachedImage
            return
        }

        if let url = URL(string: URLString) {
            URLSession.shared.dataTask(with: url, completionHandler: { (data, response, error) in

                //print("RESPONSE FROM API: \(response)")
                if error != nil {
                    print("ERROR LOADING IMAGES FROM URL: \(String(describing: error))")
                    DispatchQueue.main.async { [weak self] in
                        self?.image = placeHolder
                    }
                    return
                }
                DispatchQueue.main.async { [weak self] in
                    if let data = data {
                        if let downloadedImage = UIImage(data: data) {
                            imageCache.setObject(downloadedImage, forKey: NSString(string: URLString))
                            self?.image = downloadedImage
                        }
                    }
                }
            }).resume()
        }
    }
}

其他回答

你需要做的是:

UIImage(data: data)

在Swift中,他们已经用规则构造函数取代了大多数Objective C工厂方法。

See:

https://developer.apple.com/library/prerelease/ios/documentation/Swift/Conceptual/BuildingCocoaApps/InteractingWithObjective-CAPIs.html#//apple_ref/doc/uid/TP40014216-CH4-XID_26

AsyncImage是在iOS 15之后正式引入的,一个同步加载和显示图像的视图。

 var imageView : AsyncImage

imageView = AsyncImage(url: URL(string: entry.photo))
    .frame(width: 200, height: 200)

它还支持:

使用init(url:scale:content:placeholder:)指定一个自定义占位符。 要获得对加载过程的更多控制,请使用init(url:scale:transaction:content:)

详见文档

干净的方式:

extension URL {
    var favIcon16: UIImage? { getFav(ofSize: .s) }
    var favIcon32: UIImage? { getFav(ofSize: .m) }
    var favIcon64: UIImage? { getFav(ofSize: .l) }
    var favIcon128: UIImage? { getFav(ofSize: .xl) }
    var favIcon256: UIImage? { getFav(ofSize: .xxl) }
    var favIcon512: UIImage? { getFav(ofSize: .xxxl) }

    private func getFav(ofSize s: FavSize) -> UIImage? {
        guard UIApplication.shared.canOpenURL(self),
              let favUrl = URL(string: "https://www.google.com/s2/favicons?sz=\(s.rawValue)&domain=\(self.absoluteURL)"),
              let data = try? Data(contentsOf: favUrl)
        else { return nil }
        return UIImage(data: data)
 }
    private enum FavSize: Int, CaseIterable { case s = 16, m = 32, l = 64, xl = 128, xxl = 256, xxxl = 512 }
}

和用法:

let myUrl = URL(string: "http://facebook.com")
myImgView.image = myUrl.favIcon16

为了在UITableView或UICollectionView中获得更好的性能,使用轻量级库智能惰性加载,如果你想从url异步加载图像,可以使用这种惰性加载方法

因此,在这个项目中,我们可以通过使用操作和操作队列并发优化应用程序的性能,在任何视图(UICollectionView或UITableView)中下载多个图像。以下是这个项目的重点智能延迟加载:创建图像下载服务。根据单元格的可见性优先下载。

ImageDownloadService类将创建一个单例实例,并有一个NSCache实例来缓存已下载的图像。我们已经将Operation类继承给TOperation,以便根据我们的需要修改功能。我认为就功能而言,operation子类的属性非常清楚。我们使用KVO监测操作状态的变化。

斯威夫特4

这个方法将从一个网站异步下载图像并缓存它:

    func getImageFromWeb(_ urlString: String, closure: @escaping (UIImage?) -> ()) {
        guard let url = URL(string: urlString) else {
return closure(nil)
        }
        let task = URLSession(configuration: .default).dataTask(with: url) { (data, response, error) in
            guard error == nil else {
                print("error: \(String(describing: error))")
                return closure(nil)
            }
            guard response != nil else {
                print("no response")
                return closure(nil)
            }
            guard data != nil else {
                print("no data")
                return closure(nil)
            }
            DispatchQueue.main.async {
                closure(UIImage(data: data!))
            }
        }; task.resume()
    }

在使用:

    getImageFromWeb("http://www.apple.com/euro/ios/ios8/a/generic/images/og.png") { (image) in
        if let image = image {
            let imageView = UIImageView(frame: CGRect(x: 0, y: 0, width: 200, height: 200))
            imageView.image = image
            self.view.addSubview(imageView)
        } // if you use an Else statement, it will be in background
    }