Powershell + Curl + Zimbra SOAP API

${my_xml} = @"
<?xml version=\"1.0\" encoding=\"UTF-8\"?>
<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\">
  <soapenv:Body>
   <GetFolderRequest xmlns=\"urn:zimbraMail\">
    <folder>
       <path>Folder Name</path>
    </folder>
   </GetFolderRequest>
  </soapenv:Body>
</soapenv:Envelope>
"@

${my_curl} = "c:\curl.exe"
${cookie} = "c:\cookie.txt"

${zimbra_soap_url} = "https://zimbra:7071/service/admin/soap"
${curl_getfolder_args} = "-b", "${cookie}",
            "--header", "Content-Type: text/xml;charset=UTF-8",
            "--silent",
            "--data-raw", "${my_xml}",
            "--url", "${zimbra_soap_url}"

[xml]${my_response} = & ${my_curl} ${curl_getfolder_args}
${my_response}.Envelope.Body.GetFolderResponse.folder.id

你可以使用选项——data with file。

将xml内容写入名为soap_get.xml的文件，并使用curl命令发送请求:

curl -X POST——header "Content-Type:text/xml;charset=UTF-8"——data @soap_get.xml

如果你在Windows上使用curl:

curl -H "Content-Type: application/xml" -d "<?xml version="""1.0""" encoding="""UTF-8""" standalone="""yes"""?><message><sender>Me</sender><content>Hello!</content></message>" http://localhost:8080/webapp/rest/hello

您可以使用该命令:

curl -X POST --header 'Content-Type: multipart/form-data' --header 'Accept: application/json' --header 'Authorization: <<Removed>>' -F file=@"/home/xxx/Desktop/customers.json"  'API_SERVER_URL' -k 

Powershell + Curl + Zimbra SOAP API

${my_xml} = @"
<?xml version=\"1.0\" encoding=\"UTF-8\"?>
<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\">
  <soapenv:Body>
   <GetFolderRequest xmlns=\"urn:zimbraMail\">
    <folder>
       <path>Folder Name</path>
    </folder>
   </GetFolderRequest>
  </soapenv:Body>
</soapenv:Envelope>
"@

${my_curl} = "c:\curl.exe"
${cookie} = "c:\cookie.txt"

${zimbra_soap_url} = "https://zimbra:7071/service/admin/soap"
${curl_getfolder_args} = "-b", "${cookie}",
            "--header", "Content-Type: text/xml;charset=UTF-8",
            "--silent",
            "--data-raw", "${my_xml}",
            "--url", "${zimbra_soap_url}"

[xml]${my_response} = & ${my_curl} ${curl_getfolder_args}
${my_response}.Envelope.Body.GetFolderResponse.folder.id

下面是如何在Windows上使用curl命令行在Windows上POST XML。最好使用batch/。CMD文件:

curl -i -X POST -H "Content-Type: text/xml" -d             ^
"^<?xml version=\"1.0\" encoding=\"UTF-8\" ?^>                ^
    ^<Transaction^>                                           ^
        ^<SomeParam1^>Some-Param-01^</SomeParam1^>            ^
        ^<Password^>SomePassW0rd^</Password^>                 ^
        ^<Transaction_Type^>00^</Transaction_Type^>           ^
        ^<CardHoldersName^>John Smith^</CardHoldersName^>     ^
        ^<DollarAmount^>9.97^</DollarAmount^>                 ^
        ^<Card_Number^>4111111111111111^</Card_Number^>       ^
        ^<Expiry_Date^>1118^</Expiry_Date^>                   ^
        ^<VerificationStr2^>123^</VerificationStr2^>          ^
        ^<CVD_Presence_Ind^>1^</CVD_Presence_Ind^>            ^
        ^<Reference_No^>Some Reference Text^</Reference_No^>  ^
        ^<Client_Email^>john@smith.com^</Client_Email^>       ^
        ^<Client_IP^>123.4.56.7^</Client_IP^>                 ^
        ^<Tax1Amount^>^</Tax1Amount^>                         ^
        ^<Tax2Amount^>^</Tax2Amount^>                         ^
    ^</Transaction^>                                          ^
" "http://localhost:8080"