Simple answer by program:


public class StringCamelCase {
    public static void main(String[] args) {
        String[] articles = {"the ", "a ", "one ", "some ", "any "};
        String[] result = new String[articles.length];
        int i = 0;
        for (String string : articles) {
            result[i++] = toUpercaseForstChar(string);
        }

        for (String string : result) {
            System.out.println(string);
        }
    }
    public static String toUpercaseForstChar(String string){
        return new String(new char[]{string.charAt(0)}).toUpperCase() + string.substring(1,string.length());
    }
}

我做了这个小类，可以用来大写一个句子中的每个单词。如果不是空格，可以更改字符串中的单词分隔符。

package com.ecnews.ecnews_v01.Helpers;

  public class Capitalize {

  String sentence;
  String separator = " ";

  public Capitalize(String sentence) {
    this.sentence = sentence;
  }

  public void setSeparator(String separator) {
    this.separator = separator;
  }

  public String getCapitalized() {
    StringBuilder capitalized = new StringBuilder("");
    for (String word : sentence.split(separator)) {
        capitalized.append(separator+Character.toUpperCase(word.charAt(0)) + word.substring(1));
    }
    return capitalized.toString().trim();
  }

}

例子:

String sourceName = new Capitalize("this is a test"). get资本化();

sourceName将是“This Is A Test”

因为没有人使用regexp，所以我们使用regexp。这个解决方案只是为了好玩。:)(更新:实际上我刚刚发现有一个regexp的答案，无论如何，我想把这个答案留在原地，因为它更好看:)):

public class Capitol 
{
    public static String now(String str)
    {
        StringBuffer b = new StringBuffer();
        Pattern p = Pattern.compile("\\b(\\w){1}");
        Matcher m = p.matcher(str);
        while (m.find())
        {
            String s = m.group(1);
            m.appendReplacement(b, s.toUpperCase());
        }
        m.appendTail(b);
        return b.toString();
    }
}

使用

Capitol.now("ab cd"));
Capitol.now("winnie the Pooh"));
Capitol.now("please talk loudly!"));
Capitol.now("miles o'Brien"));

用这段简单的代码:

String example="hello";

example=example.substring(0,1).toUpperCase()+example.substring(1, example.length());

System.out.println(example);

结果:你好

public static void main(String[] args) throws IOException {
    String words = "this is a test";

    System.out.println(Arrays.asList(words.split(" ")).stream().reduce("",(a, b)->(a + " " + b.substring(0, 1).toUpperCase() + b.substring(1))));


}

}

这是我的解决方案。

今晚我偶然发现了这个问题，并决定研究一下。我发现Neelam Singh的答案几乎在那里，所以我决定解决这个问题(断在空字符串上)，导致系统崩溃。

您正在寻找的方法名为capString(String s)。 它把“这里才早上5点”变成了“这里才早上5点”。

代码注释得很好，喜欢吧。

package com.lincolnwdaniel.interactivestory.model;

    public class StringS {

    /**
     * @param s is a string of any length, ideally only one word
     * @return a capitalized string.
     * only the first letter of the string is made to uppercase
     */
    public static String capSingleWord(String s) {
        if(s.isEmpty() || s.length()<2) {
            return Character.toUpperCase(s.charAt(0))+"";
        } 
        else {
            return Character.toUpperCase(s.charAt(0)) + s.substring(1);
        }
    }

    /**
     *
     * @param s is a string of any length
     * @return a title cased string.
     * All first letter of each word is made to uppercase
     */
    public static String capString(String s) {
        // Check if the string is empty, if it is, return it immediately
        if(s.isEmpty()){
            return s;
        }

        // Split string on space and create array of words
        String[] arr = s.split(" ");
        // Create a string buffer to hold the new capitalized string
        StringBuffer sb = new StringBuffer();

        // Check if the array is empty (would be caused by the passage of s as an empty string [i.g "" or " "],
        // If it is, return the original string immediately
        if( arr.length < 1 ){
            return s;
        }

        for (int i = 0; i < arr.length; i++) {
            sb.append(Character.toUpperCase(arr[i].charAt(0)))
                    .append(arr[i].substring(1)).append(" ");
        }
        return sb.toString().trim();
    }
}