Java中是否内置了一个函数，使字符串中每个单词的第一个字符大写，而不影响其他字符?
例子:
乔恩·斯基特->乔恩·斯基特 miles o'Brien -> miles o'Brien (B仍然是大写，这排除了Title Case) 老麦当劳->
*(老麦当劳也会被发现，但我不指望它有那么聪明。)
快速浏览一下Java字符串文档就会发现只有toUpperCase()和toLowerCase()，它们当然没有提供所需的行为。当然，谷歌的结果主要是这两个函数。它看起来像一个已经被发明出来的轮子，所以问一下也无妨，这样我以后就可以用它了。
当前回答
String text="hello";
StringBuffer sb=new StringBuffer();
char[] ch=text.toCharArray();
for(int i=0;i<ch.length;i++){
if(i==0){
sb.append(Character.toUpperCase(ch[i]));
}
else{
sb.append(ch[i]);
}
}
text=sb.toString();
System.out.println(text);
}
其他回答
String s="hi dude i want apple";
s = s.replaceAll("\\s+"," ");
String[] split = s.split(" ");
s="";
for (int i = 0; i < split.length; i++) {
split[i]=Character.toUpperCase(split[i].charAt(0))+split[i].substring(1);
s+=split[i]+" ";
System.out.println(split[i]);
}
System.out.println(s);
使用org.apache.commons.lang.StringUtils可以使它变得非常简单。
capitalizeStr = StringUtils.capitalize(str);
Simple answer by program:
public class StringCamelCase {
public static void main(String[] args) {
String[] articles = {"the ", "a ", "one ", "some ", "any "};
String[] result = new String[articles.length];
int i = 0;
for (String string : articles) {
result[i++] = toUpercaseForstChar(string);
}
for (String string : result) {
System.out.println(string);
}
}
public static String toUpercaseForstChar(String string){
return new String(new char[]{string.charAt(0)}).toUpperCase() + string.substring(1,string.length());
}
}
这是另一种表达方式:
private String capitalize(String line)
{
StringTokenizer token =new StringTokenizer(line);
String CapLine="";
while(token.hasMoreTokens())
{
String tok = token.nextToken().toString();
CapLine += Character.toUpperCase(tok.charAt(0))+ tok.substring(1)+" ";
}
return CapLine.substring(0,CapLine.length()-1);
}
下面是这个问题的Kotlin版本:
fun capitalizeFirstLetterOfEveryWord(text: String): String
{
if (text.isEmpty() || text.isBlank())
{
return ""
}
if (text.length == 1)
{
return Character.toUpperCase(text[0]).toString()
}
val textArray = text.split(" ")
val stringBuilder = StringBuilder()
for ((index, item) in textArray.withIndex())
{
// If item is empty string, continue to next item
if (item.isEmpty())
{
continue
}
stringBuilder
.append(Character.toUpperCase(item[0]))
// If the item has only one character then continue to next item because we have already capitalized it.
if (item.length == 1)
{
continue
}
for (i in 1 until item.length)
{
stringBuilder
.append(Character.toLowerCase(item[i]))
}
if (index < textArray.lastIndex)
{
stringBuilder
.append(" ")
}
}
return stringBuilder.toString()
}
