这里是一个lil程序，我是用来大写每个第一个字母单词在每个子文件夹的父目录。

private void capitalize(String string)
{
    List<String> delimiters = new ArrayList<>();
    delimiters.add(" ");
    delimiters.add("_");

    File folder = new File(string);
    String name = folder.getName();
    String[] characters = name.split("");

    String newName = "";
    boolean capitalizeNext = false;

    for (int i = 0; i < characters.length; i++)
    {
        String character = characters[i];

        if (capitalizeNext || i == 0)
        {
            newName += character.toUpperCase();
            capitalizeNext = false;
        }
        else
        {
            if (delimiters.contains(character)) capitalizeNext = true;
            newName += character;
        }
    }

    folder.renameTo(new File(folder.getParent() + File.separator + newName));
}

    s.toLowerCase().trim();
    result += Character.toUpperCase(s.charAt(0));
    result += s.substring(1, s.indexOf(" ") + 1);
    s = s.substring(s.indexOf(" ") + 1);

    do {
        if (s.contains(" ")) {
            result += " ";
            result += Character.toUpperCase(s.charAt(0));
            result += s.substring(1, s.indexOf(" "));
            s = s.substring(s.indexOf(" ") + 1);
        } else {
            result += " ";
            result += Character.toUpperCase(s.charAt(0));
            result += s.substring(1);
            break;
        }
    } while (true);
    System.out.println(result);

试试这个:

 private String capitalizer(String word){

        String[] words = word.split(" ");
        StringBuilder sb = new StringBuilder();
        if (words[0].length() > 0) {
            sb.append(Character.toUpperCase(words[0].charAt(0)) + words[0].subSequence(1, words[0].length()).toString().toLowerCase());
            for (int i = 1; i < words.length; i++) {
                sb.append(" ");
                sb.append(Character.toUpperCase(words[i].charAt(0)) + words[i].subSequence(1, words[i].length()).toString().toLowerCase());
            }
        }
        return  sb.toString();
    }

我需要做一个通用的toString(Object obj)帮助类函数，在那里我必须将字段名转换为方法名-传递对象的getXXX()。

下面是代码

/**
 * @author DPARASOU
 * Utility method to replace the first char of a string with uppercase but leave other chars as it is.
 * ToString() 
 * @param inStr - String
 * @return String
 */
public static String firstCaps(String inStr)
{
    if (inStr != null && inStr.length() > 0)
    {
        char[] outStr = inStr.toCharArray();
        outStr[0] = Character.toUpperCase(outStr[0]);
        return String.valueOf(outStr);
    }
    else
        return inStr;
}

我的toString()实用程序是这样的

public static String getToString(Object obj)
{
    StringBuilder toString = new StringBuilder();
    toString.append(obj.getClass().getSimpleName());
    toString.append("[");
    for(Field f : obj.getClass().getDeclaredFields())
    {
        toString.append(f.getName());
        toString.append("=");
        try{
            //toString.append(f.get(obj)); //access privilege issue
            toString.append(invokeGetter(obj, firstCaps(f.getName()), "get"));
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
        toString.append(", ");        
    }
    toString.setCharAt(toString.length()-2, ']');
    return toString.toString();
}

如果你需要大写标题，这可能很有用。它将每个由" "分隔的子字符串大写，除了"a"或"the"之类的指定字符串。我还没有运行它，因为已经晚了，不过应该没问题。一次使用Apache Commons StringUtils.join()。如果你愿意，你可以用一个简单的循环来代替它。

private static String capitalize(String string) {
    if (string == null) return null;
    String[] wordArray = string.split(" "); // Split string to analyze word by word.
    int i = 0;
lowercase:
    for (String word : wordArray) {
        if (word != wordArray[0]) { // First word always in capital
            String [] lowercaseWords = {"a", "an", "as", "and", "although", "at", "because", "but", "by", "for", "in", "nor", "of", "on", "or", "so", "the", "to", "up", "yet"};
            for (String word2 : lowercaseWords) {
                if (word.equals(word2)) {
                    wordArray[i] = word;
                    i++;
                    continue lowercase;
                }
            }
        }
        char[] characterArray = word.toCharArray();
        characterArray[0] = Character.toTitleCase(characterArray[0]);
        wordArray[i] = new String(characterArray);
        i++;
    }
    return StringUtils.join(wordArray, " "); // Re-join string
}

简单而精确的方法如下:

String name = "test";

name = (name.length() != 0) ?name.toString().toLowerCase().substring(0,1).toUpperCase().concat(name.substring(1)): name;

-------------------- 输出 -------------------- 测试 T 空 --------------------

如果您尝试将name值更改为三个值，则不会出错。无错。