intiCap的可重用方法:

    public class YarlagaddaSireeshTest{

    public static void main(String[] args) {
        String FinalStringIs = "";
        String testNames = "sireesh yarlagadda test";
        String[] name = testNames.split("\\s");

        for(String nameIs :name){
            FinalStringIs += getIntiCapString(nameIs) + ",";
        }
        System.out.println("Final Result "+ FinalStringIs);
    }

    public static String getIntiCapString(String param) {
        if(param != null && param.length()>0){          
            char[] charArray = param.toCharArray(); 
            charArray[0] = Character.toUpperCase(charArray[0]); 
            return new String(charArray); 
        }
        else {
            return "";
        }
    }
}

这是我的解决方案。

今晚我偶然发现了这个问题，并决定研究一下。我发现Neelam Singh的答案几乎在那里，所以我决定解决这个问题(断在空字符串上)，导致系统崩溃。

您正在寻找的方法名为capString(String s)。 它把“这里才早上5点”变成了“这里才早上5点”。

代码注释得很好，喜欢吧。

package com.lincolnwdaniel.interactivestory.model;

    public class StringS {

    /**
     * @param s is a string of any length, ideally only one word
     * @return a capitalized string.
     * only the first letter of the string is made to uppercase
     */
    public static String capSingleWord(String s) {
        if(s.isEmpty() || s.length()<2) {
            return Character.toUpperCase(s.charAt(0))+"";
        } 
        else {
            return Character.toUpperCase(s.charAt(0)) + s.substring(1);
        }
    }

    /**
     *
     * @param s is a string of any length
     * @return a title cased string.
     * All first letter of each word is made to uppercase
     */
    public static String capString(String s) {
        // Check if the string is empty, if it is, return it immediately
        if(s.isEmpty()){
            return s;
        }

        // Split string on space and create array of words
        String[] arr = s.split(" ");
        // Create a string buffer to hold the new capitalized string
        StringBuffer sb = new StringBuffer();

        // Check if the array is empty (would be caused by the passage of s as an empty string [i.g "" or " "],
        // If it is, return the original string immediately
        if( arr.length < 1 ){
            return s;
        }

        for (int i = 0; i < arr.length; i++) {
            sb.append(Character.toUpperCase(arr[i].charAt(0)))
                    .append(arr[i].substring(1)).append(" ");
        }
        return sb.toString().trim();
    }
}

import java.io.*;
public class Upch2
{
   BufferedReader br= new BufferedReader( new InputStreamReader(System.in));
   public void main()throws IOException
    { 
        System.out.println("Pl. Enter A Line");
        String s=br.readLine();
        String s1=" ";
        s=" "+s;
        int len=s.length();
        s= s.toLowerCase();
        for(int j=1;j<len;j++)
         {
           char  ch=s.charAt(j);

           if(s.charAt(j-1)!=' ')
           {
             ch=Character.toLowerCase((s.charAt(j)));
           }
           else
           {
             ch=Character.toUpperCase((s.charAt(j)));
            }
            s1=s1+ch;
          }
     System.out.println(" "+s1);
  }
}

Simple answer by program:


public class StringCamelCase {
    public static void main(String[] args) {
        String[] articles = {"the ", "a ", "one ", "some ", "any "};
        String[] result = new String[articles.length];
        int i = 0;
        for (String string : articles) {
            result[i++] = toUpercaseForstChar(string);
        }

        for (String string : result) {
            System.out.println(string);
        }
    }
    public static String toUpercaseForstChar(String string){
        return new String(new char[]{string.charAt(0)}).toUpperCase() + string.substring(1,string.length());
    }
}

这是另一种表达方式:

private String capitalize(String line)
{
    StringTokenizer token =new StringTokenizer(line);
    String CapLine="";
    while(token.hasMoreTokens())
    {
        String tok = token.nextToken().toString();
        CapLine += Character.toUpperCase(tok.charAt(0))+ tok.substring(1)+" ";        
    }
    return CapLine.substring(0,CapLine.length()-1);
}

来自Java 9+

你可以像这样使用String::replaceAll:

public static void upperCaseAllFirstCharacter(String text) {
    String regex = "\\b(.)(.*?)\\b";
    String result = Pattern.compile(regex).matcher(text).replaceAll(
            matche -> matche.group(1).toUpperCase() + matche.group(2)
    );

    System.out.println(result);
}

例子:

upperCaseAllFirstCharacter("hello this is Just a test");

输出

Hello This Is Just A Test