如何添加或更新查询字符串参数?

用javascript我怎么能添加一个查询字符串参数的url，如果不存在或如果它存在，更新当前值?我使用jquery为我的客户端开发。

当前回答

我写了下面的函数来实现我想要实现的:

function updateQueryStringParameter(uri, key, value) {
  var re = new RegExp("([?&])" + key + "=.*?(&|$)", "i");
  var separator = uri.indexOf('?') !== -1 ? "&" : "?";
  if (uri.match(re)) {
    return uri.replace(re, '$1' + key + "=" + value + '$2');
  }
  else {
    return uri + separator + key + "=" + value;
  }
}

2011-05-16 17:26:06

其他回答

根据@ellemayo给出的答案，我提出了以下解决方案，如果需要，可以禁用散列标签:

function updateQueryString(key, value, options) {
    if (!options) options = {};

    var url = options.url || location.href;
    var re = new RegExp("([?&])" + key + "=.*?(&|#|$)(.*)", "gi"), hash;

    hash = url.split('#');
    url = hash[0];
    if (re.test(url)) {
        if (typeof value !== 'undefined' && value !== null) {
            url = url.replace(re, '$1' + key + "=" + value + '$2$3');
        } else {
            url = url.replace(re, '$1$3').replace(/(&|\?)$/, '');
        }
    } else if (typeof value !== 'undefined' && value !== null) {
        var separator = url.indexOf('?') !== -1 ? '&' : '?';
        url = url + separator + key + '=' + value;
    }

    if ((typeof options.hash === 'undefined' || options.hash) &&
        typeof hash[1] !== 'undefined' && hash[1] !== null)
        url += '#' + hash[1];
    return url;
}

这样叫它:

updateQueryString('foo', 'bar', {
    url: 'http://my.example.com#hash',
    hash: false
});

结果:

http://my.example.com?foo=bar

2015-06-24 07:56:14

我想要的是:

使用浏览器的本地URL API 可以添加、更新、获取或删除吗期望在散列之后的查询字符串，例如对于单页应用程序

function queryParam(options = {}) { var defaults = { method: 'set', url: window.location.href, key: undefined, value: undefined, } for (var prop in defaults) { options[prop] = typeof options[prop] !== 'undefined' ? options[prop] : defaults[prop] } const existing = (options.url.lastIndexOf('?') > options.url.lastIndexOf('#')) ? options.url.substr(options.url.lastIndexOf('?') + 1) : '' const query = new URLSearchParams(existing) if (options.method === 'set') { query.set(options.key, options.value) return `${options.url.replace(`?${existing}`, '')}?${query.toString()}` } else if (options.method === 'get') { const val = query.get(options.key) let result = val === null ? val : val.toString() return result } else if (options.method === 'delete') { query.delete(options.key) let result = `${options.url.replace(`?${existing}`, '')}?${query.toString()}` const lastChar = result.charAt(result.length - 1) if (lastChar === '?') { result = `${options.url.replace(`?${existing}`, '')}` } return result } } // Usage: let url = 'https://example.com/sandbox/#page/' url = queryParam({ url, method: 'set', key: 'my-first-param', value: 'me' }) console.log(url) url = queryParam({ url, method: 'set', key: 'my-second-param', value: 'you' }) console.log(url) url = queryParam({ url, method: 'set', key: 'my-second-param', value: 'whomever' }) console.log(url) url = queryParam({ url, method: 'delete', key: 'my-first-param' }) console.log(url) const mySecondParam = queryParam({ url, method: 'get', key: 'my-second-param', }) console.log(mySecondParam) url = queryParam({ url, method: 'delete', key: 'my-second-param' }) console.log(url)

2022-10-14 07:05:05

如果你想一次设置多个参数:

function updateQueryStringParameters(uri, params) {
    for(key in params){
      var value = params[key],
          re = new RegExp("([?&])" + key + "=.*?(&|$)", "i"),
          separator = uri.indexOf('?') !== -1 ? "&" : "?";
      if (uri.match(re)) {
        uri = uri.replace(re, '$1' + key + "=" + value + '$2');
      }
      else {
        uri = uri + separator + key + "=" + value;
      }
    }
    return uri;
}

与@amateur的函数相同

如果jslint给出了一个错误，在for循环之后添加这个

if(params.hasOwnProperty(key))

2015-11-27 10:20:44

我知道这是相当旧的，但我想把我的工作版本在这里。

说明修改后的@elreimundo

2016-05-10 14:33:33

我从这里得出的结论(与“使用严格”相容;并不真正使用jQuery):

function decodeURIParams(query) {
  if (query == null)
    query = window.location.search;
  if (query[0] == '?')
    query = query.substring(1);

  var params = query.split('&');
  var result = {};
  for (var i = 0; i < params.length; i++) {
    var param = params[i];
    var pos = param.indexOf('=');
    if (pos >= 0) {
        var key = decodeURIComponent(param.substring(0, pos));
        var val = decodeURIComponent(param.substring(pos + 1));
        result[key] = val;
    } else {
        var key = decodeURIComponent(param);
        result[key] = true;
    }
  }
  return result;
}

function encodeURIParams(params, addQuestionMark) {
  var pairs = [];
  for (var key in params) if (params.hasOwnProperty(key)) {
    var value = params[key];
    if (value != null) /* matches null and undefined */ {
      pairs.push(encodeURIComponent(key) + '=' + encodeURIComponent(value))
    }
  }
  if (pairs.length == 0)
    return '';
  return (addQuestionMark ? '?' : '') + pairs.join('&');
}

//// alternative to $.extend if not using jQuery:
// function mergeObjects(destination, source) {
//   for (var key in source) if (source.hasOwnProperty(key)) {
//     destination[key] = source[key];
//   }
//   return destination;
// }

function navigateWithURIParams(newParams) {
  window.location.search = encodeURIParams($.extend(decodeURIParams(), newParams), true);
}

使用示例:

// add/update parameters
navigateWithURIParams({ foo: 'bar', boz: 42 });

// remove parameter
navigateWithURIParams({ foo: null });

// submit the given form by adding/replacing URI parameters (with jQuery)
$('.filter-form').submit(function(e) {
  e.preventDefault();
  navigateWithURIParams(decodeURIParams($(this).serialize()));
});

2013-02-05 03:37:52

如何添加或更新查询字符串参数?

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