用javascript我怎么能添加一个查询字符串参数的url,如果不存在或如果它存在,更新当前值?我使用jquery为我的客户端开发。


当前回答

这样做的目的是:

function updateQueryString(url, key, value) {
    var arr =  url.split("#");
    var url = arr[0];
    var fragmentId = arr[1];
    var updatedQS = "";
    if (url.indexOf("?") == -1) {
        updatedQS = encodeURIComponent(key) + "=" + encodeURIComponent(value);
    }
    else {
        updatedQS = addOrModifyQS(url.substring(url.indexOf("?") + 1), key, value); 
    }
    url = url.substring(0, url.indexOf("?")) + "?" + updatedQS;
    if (typeof fragmentId !== 'undefined') {
        url = url + "#" + fragmentId;
    }
    return url;
}

function addOrModifyQS(queryStrings, key, value) {
    var oldQueryStrings = queryStrings.split("&");
    var newQueryStrings = new Array();
    var isNewKey = true;
    for (var i in oldQueryStrings) {
        var currItem = oldQueryStrings[i];
        var searchKey = key + "=";
        if (currItem.indexOf(searchKey) != -1) {
            currItem = encodeURIComponent(key) + "=" + encodeURIComponent(value);
            isNewKey = false;
        }
        newQueryStrings.push(currItem);
    }
    if (isNewKey) {
        newQueryStrings.push(encodeURIComponent(key) + "=" + encodeURIComponent(value));
    }
    return newQueryStrings.join("&");
}   

其他回答

根据@ellemayo给出的答案,我提出了以下解决方案,如果需要,可以禁用散列标签:

function updateQueryString(key, value, options) {
    if (!options) options = {};

    var url = options.url || location.href;
    var re = new RegExp("([?&])" + key + "=.*?(&|#|$)(.*)", "gi"), hash;

    hash = url.split('#');
    url = hash[0];
    if (re.test(url)) {
        if (typeof value !== 'undefined' && value !== null) {
            url = url.replace(re, '$1' + key + "=" + value + '$2$3');
        } else {
            url = url.replace(re, '$1$3').replace(/(&|\?)$/, '');
        }
    } else if (typeof value !== 'undefined' && value !== null) {
        var separator = url.indexOf('?') !== -1 ? '&' : '?';
        url = url + separator + key + '=' + value;
    }

    if ((typeof options.hash === 'undefined' || options.hash) &&
        typeof hash[1] !== 'undefined' && hash[1] !== null)
        url += '#' + hash[1];
    return url;
}

这样叫它:

updateQueryString('foo', 'bar', {
    url: 'http://my.example.com#hash',
    hash: false
});

结果:

http://my.example.com?foo=bar

我从这里得出的结论(与“使用严格”相容;并不真正使用jQuery):

function decodeURIParams(query) {
  if (query == null)
    query = window.location.search;
  if (query[0] == '?')
    query = query.substring(1);

  var params = query.split('&');
  var result = {};
  for (var i = 0; i < params.length; i++) {
    var param = params[i];
    var pos = param.indexOf('=');
    if (pos >= 0) {
        var key = decodeURIComponent(param.substring(0, pos));
        var val = decodeURIComponent(param.substring(pos + 1));
        result[key] = val;
    } else {
        var key = decodeURIComponent(param);
        result[key] = true;
    }
  }
  return result;
}

function encodeURIParams(params, addQuestionMark) {
  var pairs = [];
  for (var key in params) if (params.hasOwnProperty(key)) {
    var value = params[key];
    if (value != null) /* matches null and undefined */ {
      pairs.push(encodeURIComponent(key) + '=' + encodeURIComponent(value))
    }
  }
  if (pairs.length == 0)
    return '';
  return (addQuestionMark ? '?' : '') + pairs.join('&');
}

//// alternative to $.extend if not using jQuery:
// function mergeObjects(destination, source) {
//   for (var key in source) if (source.hasOwnProperty(key)) {
//     destination[key] = source[key];
//   }
//   return destination;
// }

function navigateWithURIParams(newParams) {
  window.location.search = encodeURIParams($.extend(decodeURIParams(), newParams), true);
}

使用示例:

// add/update parameters
navigateWithURIParams({ foo: 'bar', boz: 42 });

// remove parameter
navigateWithURIParams({ foo: null });

// submit the given form by adding/replacing URI parameters (with jQuery)
$('.filter-form').submit(function(e) {
  e.preventDefault();
  navigateWithURIParams(decodeURIParams($(this).serialize()));
});

我知道这是相当旧的,但我想把我的工作版本在这里。

function addOrUpdateUrlParam(uri, paramKey, paramVal) { var re = new RegExp("([?&])" + paramKey + "=[^&#]*", "i"); if (re.test(uri)) { uri = uri.replace(re, '$1' + paramKey + "=" + paramVal); } else { var separator = /\?/.test(uri) ? "&" : "?"; uri = uri + separator + paramKey + "=" + paramVal; } return uri; } jQuery(document).ready(function($) { $('#paramKey,#paramValue').on('change', function() { if ($('#paramKey').val() != "" && $('#paramValue').val() != "") { $('#uri').val(addOrUpdateUrlParam($('#uri').val(), $('#paramKey').val(), $('#paramValue').val())); } }); }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <input style="width:100%" type="text" id="uri" value="http://www.example.com/text.php"> <label style="display:block;">paramKey <input type="text" id="paramKey"> </label> <label style="display:block;">paramValue <input type="text" id="paramValue"> </label>

说明修改后的@elreimundo

一种不使用正则表达式的不同方法。支持url末尾的“散列”锚以及多个问号字符(?)。应该比正则表达式方法略快。

function setUrlParameter(url, key, value) {
  var parts = url.split("#", 2), anchor = parts.length > 1 ? "#" + parts[1] : '';
  var query = (url = parts[0]).split("?", 2);
  if (query.length === 1) 
    return url + "?" + key + "=" + value + anchor;

  for (var params = query[query.length - 1].split("&"), i = 0; i < params.length; i++)
    if (params[i].toLowerCase().startsWith(key.toLowerCase() + "="))
      return params[i] = key + "=" + value, query[query.length - 1] = params.join("&"), query.join("?") + anchor;

  return url + "&" + key + "=" + value + anchor
}

如果你想一次设置多个参数:

function updateQueryStringParameters(uri, params) {
    for(key in params){
      var value = params[key],
          re = new RegExp("([?&])" + key + "=.*?(&|$)", "i"),
          separator = uri.indexOf('?') !== -1 ? "&" : "?";
      if (uri.match(re)) {
        uri = uri.replace(re, '$1' + key + "=" + value + '$2');
      }
      else {
        uri = uri + separator + key + "=" + value;
      }
    }
    return uri;
}

与@amateur的函数相同

如果jslint给出了一个错误,在for循环之后添加这个

if(params.hasOwnProperty(key))