假设我有一个垂直线性布局:

[v1]
[v2]

默认情况下,v1已经可见= GONE。我想用一个展开动画显示v1,同时下推v2。

我是这样做的:

Animation a = new Animation()
{
    int initialHeight;

    @Override
    protected void applyTransformation(float interpolatedTime, Transformation t) {
        final int newHeight = (int)(initialHeight * interpolatedTime);
        v.getLayoutParams().height = newHeight;
        v.requestLayout();
    }

    @Override
    public void initialize(int width, int height, int parentWidth, int parentHeight) {
        super.initialize(width, height, parentWidth, parentHeight);
        initialHeight = height;
    }

    @Override
    public boolean willChangeBounds() {
        return true;
    }
};

但是用这个解决方案,当动画开始时我有一个眨眼。我认为这是由于v1在应用动画之前显示全尺寸。

用javascript,这是一行jQuery!android有什么简单的方法吗?


当前回答

这是一个片段,我用来调整一个视图(线性布局)的宽度与动画。

代码应该根据目标大小进行扩展或收缩。如果你想要一个fill_parent宽度,你必须在将标志设置为true时将父类. getmeasuredwidth作为目标宽度。

希望它能帮助到你们中的一些人。

public class WidthResizeAnimation extends Animation {
int targetWidth;
int originaltWidth;
View view;
boolean expand;
int newWidth = 0;
boolean fillParent;

public WidthResizeAnimation(View view, int targetWidth, boolean fillParent) {
    this.view = view;
    this.originaltWidth = this.view.getMeasuredWidth();
    this.targetWidth = targetWidth;
    newWidth = originaltWidth;
    if (originaltWidth > targetWidth) {
        expand = false;
    } else {
        expand = true;
    }
    this.fillParent = fillParent;
}

@Override
protected void applyTransformation(float interpolatedTime, Transformation t) {
    if (expand && newWidth < targetWidth) {
        newWidth = (int) (newWidth + (targetWidth - newWidth) * interpolatedTime);
    }

    if (!expand && newWidth > targetWidth) {
        newWidth = (int) (newWidth - (newWidth - targetWidth) * interpolatedTime);
    }
    if (fillParent && interpolatedTime == 1.0) {
        view.getLayoutParams().width = -1;

    } else {
        view.getLayoutParams().width = newWidth;
    }
    view.requestLayout();
}

@Override
public void initialize(int width, int height, int parentWidth, int parentHeight) {
    super.initialize(width, height, parentWidth, parentHeight);
}

@Override
public boolean willChangeBounds() {
    return true;
}

}

其他回答

这是非常简单的droidQuery。首先,考虑这样的布局:

<LinearLayout
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:orientation="vertical" >
    <LinearLayout
        android:id="@+id/v1"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content" >
        <TextView
            android:layout_width="wrap_content"
            android:layout_height="wrap_content" 
            android:text="View 1" />
    </LinearLayout>
    <LinearLayout
        android:id="@+id/v2"
        android:layout_width="wrap_content"
        android:layout_height="0dp" >
        <TextView
            android:layout_width="wrap_content"
            android:layout_height="wrap_content" 
            android:text="View 2" />
        <TextView
            android:layout_width="wrap_content"
            android:layout_height="wrap_content" 
            android:text="View 3" />
    </LinearLayout>
</LinearLayout>

我们可以使用下面的代码将高度动画到所需的值-比如100dp:

//convert 100dp to pixel value
int height = (int) TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, 100, getResources().getDisplayMetrics());

然后使用droidQuery进行动画。最简单的方法是:

$.animate("{ height: " + height + "}", new AnimationOptions());

为了让动画更吸引人,可以考虑添加一个easing:

$.animate("{ height: " + height + "}", new AnimationOptions().easing($.Easing.BOUNCE));

你也可以使用duration()方法改变AnimationOptions上的持续时间,或者处理动画结束时发生的事情。对于一个复杂的例子,试试:

$.animate("{ height: " + height + "}", new AnimationOptions().easing($.Easing.BOUNCE)
                                                             .duration(1000)
                                                             .complete(new Function() {
                                                                 @Override
                                                                 public void invoke($ d, Object... args) {
                                                                     $.toast(context, "finished", Toast.LENGTH_SHORT);
                                                                 }
                                                             }));

这是我的解决方案。我认为这样更简单。它只是扩展了视图,但很容易扩展。

public class WidthExpandAnimation extends Animation
{
    int _targetWidth;
    View _view;

    public WidthExpandAnimation(View view)
    {
        _view = view;
    }

    @Override
    protected void applyTransformation(float interpolatedTime, Transformation t)
    {
        if (interpolatedTime < 1.f)
        {
            int newWidth = (int) (_targetWidth * interpolatedTime);

            _view.layout(_view.getLeft(), _view.getTop(),
                    _view.getLeft() + newWidth, _view.getBottom());
        }
        else
            _view.requestLayout();
    }

    @Override
    public void initialize(int width, int height, int parentWidth, int parentHeight)
    {
        super.initialize(width, height, parentWidth, parentHeight);

        _targetWidth = width;
    }

    @Override
    public boolean willChangeBounds() {
        return true;
    }
}

好吧,我刚刚发现了一个非常丑陋的解决方案:

public static Animation expand(final View v, Runnable onEnd) {
    try {
        Method m = v.getClass().getDeclaredMethod("onMeasure", int.class, int.class);
        m.setAccessible(true);
        m.invoke(
            v,
            MeasureSpec.makeMeasureSpec(0, MeasureSpec.UNSPECIFIED),
            MeasureSpec.makeMeasureSpec(((View)v.getParent()).getMeasuredHeight(), MeasureSpec.AT_MOST)
        );
    } catch (Exception e){
        Log.e("test", "", e);
    }
    final int initialHeight = v.getMeasuredHeight();
    Log.d("test", "initialHeight="+initialHeight);

    v.getLayoutParams().height = 0;
    v.setVisibility(View.VISIBLE);
    Animation a = new Animation()
    {
        @Override
        protected void applyTransformation(float interpolatedTime, Transformation t) {
            final int newHeight = (int)(initialHeight * interpolatedTime);
            v.getLayoutParams().height = newHeight;
            v.requestLayout();
        }

        @Override
        public boolean willChangeBounds() {
            return true;
        }
    };
    a.setDuration(5000);
    v.startAnimation(a);
    return a;
}

请随意提出一个更好的解决方案!

展开/折叠视图的最佳解决方案:

    @Override
    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
        View view = buttonView.getId() == R.id.tb_search ? fSearch : layoutSettings;
        transform(view, 200, isChecked
            ? ViewGroup.LayoutParams.WRAP_CONTENT
            : 0);
    }

    public static void transform(final View v, int duration, int targetHeight) {
        int prevHeight  = v.getHeight();
        v.setVisibility(View.VISIBLE);
        ValueAnimator animator;
        if (targetHeight == ViewGroup.LayoutParams.WRAP_CONTENT) {
            v.measure(ViewGroup.LayoutParams.MATCH_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT);
            animator = ValueAnimator.ofInt(prevHeight, v.getMeasuredHeight());
        } else {
            animator = ValueAnimator.ofInt(prevHeight, targetHeight);
        }
        animator.addUpdateListener(animation -> {
            v.getLayoutParams().height = (animation.getAnimatedFraction() == 1.0f)
                    ? targetHeight
                    : (int) animation.getAnimatedValue();
            v.requestLayout();
        });
        animator.setInterpolator(new LinearInterpolator());
        animator.setDuration(duration);
        animator.start();
    }

我想对上面非常有用的答案补充一些东西。如果你不知道你最终得到的高度,因为你的views .getHeight()返回0,你可以做下面的事情来获得高度:

contentView.measure(DUMMY_HIGH_DIMENSION, DUMMY_HIGH_DIMENSION);
int finalHeight = view.getMeasuredHeight();

其中DUMMY_HIGH_DIMENSIONS是宽度/高度(以像素为单位),您的视图被限制为…当视图被ScrollView封装时,有这么大的数字是合理的。