假设我有一个垂直线性布局:
[v1]
[v2]
默认情况下,v1已经可见= GONE。我想用一个展开动画显示v1,同时下推v2。
我是这样做的:
Animation a = new Animation()
{
int initialHeight;
@Override
protected void applyTransformation(float interpolatedTime, Transformation t) {
final int newHeight = (int)(initialHeight * interpolatedTime);
v.getLayoutParams().height = newHeight;
v.requestLayout();
}
@Override
public void initialize(int width, int height, int parentWidth, int parentHeight) {
super.initialize(width, height, parentWidth, parentHeight);
initialHeight = height;
}
@Override
public boolean willChangeBounds() {
return true;
}
};
但是用这个解决方案,当动画开始时我有一个眨眼。我认为这是由于v1在应用动画之前显示全尺寸。
用javascript,这是一行jQuery!android有什么简单的方法吗?
加上Tom Esterez的精彩回答和Erik B的精彩更新,我想我应该发布我自己的观点,将扩展和收缩方法压缩为一个。通过这种方式,你可以有这样一个动作……
button.setOnClickListener(v -> expandCollapse(view));
... 它调用下面的方法,并让它在每次onClick()之后弄清楚要做什么…
public static void expandCollapse(View view) {
boolean expand = view.getVisibility() == View.GONE;
Interpolator easeInOutQuart = PathInterpolatorCompat.create(0.77f, 0f, 0.175f, 1f);
view.measure(
View.MeasureSpec.makeMeasureSpec(((View) view.getParent()).getWidth(), View.MeasureSpec.EXACTLY),
View.MeasureSpec.makeMeasureSpec(0, View.MeasureSpec.UNSPECIFIED)
);
int height = view.getMeasuredHeight();
int duration = (int) (height/view.getContext().getResources().getDisplayMetrics().density);
Animation animation = new Animation() {
@Override protected void applyTransformation(float interpolatedTime, Transformation t) {
if (expand) {
view.getLayoutParams().height = 1;
view.setVisibility(View.VISIBLE);
if (interpolatedTime == 1) {
view.getLayoutParams().height = ViewGroup.LayoutParams.WRAP_CONTENT;
} else {
view.getLayoutParams().height = (int) (height * interpolatedTime);
}
view.requestLayout();
} else {
if (interpolatedTime == 1) {
view.setVisibility(View.GONE);
} else {
view.getLayoutParams().height = height - (int) (height * interpolatedTime);
view.requestLayout();
}
}
}
@Override public boolean willChangeBounds() {
return true;
}
};
animation.setInterpolator(easeInOutQuart);
animation.setDuration(duration);
view.startAnimation(animation);
}
这是我的解决方案。我认为这样更简单。它只是扩展了视图,但很容易扩展。
public class WidthExpandAnimation extends Animation
{
int _targetWidth;
View _view;
public WidthExpandAnimation(View view)
{
_view = view;
}
@Override
protected void applyTransformation(float interpolatedTime, Transformation t)
{
if (interpolatedTime < 1.f)
{
int newWidth = (int) (_targetWidth * interpolatedTime);
_view.layout(_view.getLeft(), _view.getTop(),
_view.getLeft() + newWidth, _view.getBottom());
}
else
_view.requestLayout();
}
@Override
public void initialize(int width, int height, int parentWidth, int parentHeight)
{
super.initialize(width, height, parentWidth, parentHeight);
_targetWidth = width;
}
@Override
public boolean willChangeBounds() {
return true;
}
}
你可以稍微改变一下使用ViewPropertyAnimator。若要折叠,请将视图缩放到1像素的高度,然后隐藏它。展开,显示它,然后展开到它的高度。
private void collapse(final View view) {
view.setPivotY(0);
view.animate().scaleY(1/view.getHeight()).setDuration(1000).withEndAction(new Runnable() {
@Override public void run() {
view.setVisibility(GONE);
}
});
}
private void expand(View view, int height) {
float scaleFactor = height / view.getHeight();
view.setVisibility(VISIBLE);
view.setPivotY(0);
view.animate().scaleY(scaleFactor).setDuration(1000);
}
枢轴告诉视图从哪里开始缩放,默认是在中间。持续时间是可选的(默认= 1000)。你也可以设置插值器来使用,比如.setInterpolator(new accelerateeraderateinterpolator ())