根据React Router v4文档- Redux深度集成会话

深度整合需要:

“能够通过调度操作进行导航”

然而，他们推荐这种方法作为“深度集成”的替代方案:

“你可以将提供给路由组件的历史对象传递给你的操作，而不是分派操作来导航。”

所以你可以用withRouter高阶组件来包装你的组件:

export default withthrouter (connect(null， {actionCreatorName})(ReactComponent));

它将历史API传递给道具。你可以调用动作创建者传递历史作为参数。例如，在你的ReactComponent中:

onClick={() => {
  this.props.actionCreatorName(
    this.props.history,
    otherParams
  );
}}

然后，在actions/index.js中:

export function actionCreatorName(history, param) {
  return dispatch => {
    dispatch({
      type: SOME_ACTION,
      payload: param.data
    });
    history.push("/path");
  };
}

这个棘手的问题，花了我很多时间，但最终，我是这样解决的:

用withRouter包装容器，并将历史记录传递给mapDispatchToProps函数中的动作。实际操作中使用history.push('/url')进行导航。

行动:

export function saveData(history, data) {
  fetch.post('/save', data)
     .then((response) => {
       ...
       history.push('/url');
     })
};

容器:

import { withRouter } from 'react-router-dom';
...
const mapDispatchToProps = (dispatch, ownProps) => {
  return {
    save: (data) => dispatch(saveData(ownProps.history, data))}
};
export default withRouter(connect(mapStateToProps, mapDispatchToProps)(Container));

这对React Router v4.x有效。

React Router v4与v3(以及更早的版本)有本质上的不同，你不能像以前那样执行browserHistory.push()。

如果你想了解更多信息，这个讨论似乎是相关的:

创建一个新的browserHistory将不起作用，因为<BrowserRouter>创建了自己的历史实例，并侦听其上的更改。因此，不同的实例将更改url，但不更新<BrowserRouter>。 react-router不会在v4中公开browserHistory，只会在v2中公开。

相反，你有几个选择来做到这一点:

Use the withRouter high-order component Instead you should use the withRouter high order component, and wrap that to the component that will push to history. For example: import React from "react"; import { withRouter } from "react-router-dom"; class MyComponent extends React.Component { ... myFunction() { this.props.history.push("/some/Path"); } ... } export default withRouter(MyComponent); Check out the official documentation for more info: You can get access to the history object’s properties and the closest <Route>'s match via the withRouter higher-order component. withRouter will re-render its component every time the route changes with the same props as <Route> render props: { match, location, history }.

Use the context API Using the context might be one of the easiest solutions, but being an experimental API it is unstable and unsupported. Use it only when everything else fails. Here's an example: import React from "react"; import PropTypes from "prop-types"; class MyComponent extends React.Component { static contextTypes = { router: PropTypes.object } constructor(props, context) { super(props, context); } ... myFunction() { this.context.router.history.push("/some/Path"); } ... } Have a look at the official documentation on context: If you want your application to be stable, don't use context. It is an experimental API and it is likely to break in future releases of React. If you insist on using context despite these warnings, try to isolate your use of context to a small area and avoid using the context API directly when possible so that it's easier to upgrade when the API changes.

React路由器V4现在允许历史道具如下所示:

this.props.history.push("/dummy",value)

然后，只要位置道具可用，就可以访问该值 State:{value}不是组件状态。

根据React Router v4文档- Redux深度集成会话

深度整合需要:

“能够通过调度操作进行导航”

然而，他们推荐这种方法作为“深度集成”的替代方案:

“你可以将提供给路由组件的历史对象传递给你的操作，而不是分派操作来导航。”

所以你可以用withRouter高阶组件来包装你的组件:

export default withthrouter (connect(null， {actionCreatorName})(ReactComponent));

它将历史API传递给道具。你可以调用动作创建者传递历史作为参数。例如，在你的ReactComponent中:

onClick={() => {
  this.props.actionCreatorName(
    this.props.history,
    otherParams
  );
}}

然后，在actions/index.js中:

export function actionCreatorName(history, param) {
  return dispatch => {
    dispatch({
      type: SOME_ACTION,
      payload: param.data
    });
    history.push("/path");
  };
}

我可以通过使用bind()来实现这一点。我想点击索引中的一个按钮。Jsx，向服务器发布一些数据，评估响应，并重定向到success.jsx。以下是我的计算方法……

index.jsx:

import React, { Component } from "react"
import { postData } from "../../scripts/request"

class Main extends Component {
    constructor(props) {
        super(props)
        this.handleClick = this.handleClick.bind(this)
        this.postData = postData.bind(this)
    }

    handleClick() {
        const data = {
            "first_name": "Test",
            "last_name": "Guy",
            "email": "test@test.com"
        }

        this.postData("person", data)
    }

    render() {
        return (
            <div className="Main">
                <button onClick={this.handleClick}>Test Post</button>
            </div>
        )
    }
}

export default Main

request.js:

import { post } from "./fetch"

export const postData = function(url, data) {
    // post is a fetch() in another script...
    post(url, data)
        .then((result) => {
            if (result.status === "ok") {
                this.props.history.push("/success")
            }
        })
}

success.jsx:

import React from "react"

const Success = () => {
    return (
        <div className="Success">
            Hey cool, got it.
        </div>
    )
}

export default Success

通过在index中绑定这个到postData。jsx，我能够访问this.props.history在request.js…那么我就可以在不同的组件中重用这个函数，只是要确保我记得包含这个。构造函数()中的postData = postData.bind(this)。