我最近发现onActivityResult已弃用。我们该怎么处理呢?

有什么替代方案吗?


当前回答

dor506回答为我工作,因为我在我的大多数项目中使用BaseActivity,所以对我来说更容易在单个文件中更改代码,而不是我所有的活动。我已经写了这个代码的java版本。

BaseActivity代码:

private int requestCode = -1;
private ActivityResultLauncher<Intent> resultHandler = null;

 @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    mContext = this;

    registerForActivityResult();
}
  private final void registerForActivityResult() {
    if (shouldRegisterForActivityResult()) {
        this.resultHandler = registerForActivityResult(new ActivityResultContracts.StartActivityForResult(),
                new ActivityResultCallback() {

            public void onActivityResult(Object var1) {
                this.onActivityResult((ActivityResult)var1);
            }

            public final void onActivityResult(ActivityResult result) {
                Intrinsics.checkNotNullExpressionValue(result, "result");
                AppActivityClass.onActivityResult(result.getData(), AppActivityClass.this.requestCode, result.getResultCode());
                AppActivityClass.this.requestCode = -1;
            }
        });
    }
}

public final void startActivityForResult(int requestCode, Intent intent) {
    this.requestCode = requestCode;
    if (resultHandler != null) {
        resultHandler.launch(intent);
    }
}

protected static void onActivityResult(Intent intent, int requestCode, int resultCode) {
}

protected Boolean shouldRegisterForActivityResult() {
    return false;
}

现在在任何活动中使用这样的代码:

 @Override
protected Boolean shouldRegisterForActivityResult() {
    return true;  // this will override the baseactivity method and we can use onactivityresult
}

  private void someMethod(){
    Intent i = new Intent(mContext,SomeOtherClassActivity.class);
    startActivityForResult(101,i);
}

  @Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == 101) {
        if (resultCode == RESULT_OK) {
            //revert from called class
        }
    }
}

其他回答

在替换已弃用的方法startActivityForResult(…)时,需要遵循4个简单的步骤。

In place of overridden method onActivityResult(..) - ActivityResultLauncher<Intent> activityResultLaunch = registerForActivityResult( new ActivityResultContracts.StartActivityForResult(), new ActivityResultCallback<ActivityResult>() { @Override public void onActivityResult(ActivityResult result) { if (result.getResultCode() == 123) { // ToDo : Do your stuff... } else if(result.getResultCode() == 321) { // ToDo : Do your stuff... } } });

对于多个自定义请求,将条件附加为

if (result.getResultCode() == 123) {
..
} else if(result.getResultCode() == 131){
..
} // so on..

Imports : import androidx.activity.result.ActivityResult; import androidx.activity.result.ActivityResultCallback; import androidx.activity.result.ActivityResultLauncher; import androidx.activity.result.contract.ActivityResultContracts; In place of startActivityForResult(intent, 123), use Intent intent = new Intent(this, SampleActivity.class); activityResultLaunch.launch(intent); In SampleActivity.java class, while returning back to source activity, code will remain the same like - Intent intent = new Intent(); setResult(123, intent); finish();

编码快乐!:)

ActivityResultLauncher<Intent> someActivityResultLauncher = registerForActivityResult(
        new ActivityResultContracts.StartActivityForResult(),
        new ActivityResultCallback<ActivityResult>() {
            @Override
            public void onActivityResult(ActivityResult result) {
                if (result.getResultCode() == Activity.RESULT_OK) {

                }
            }
        });

如果你像这样实现你的base Activity,你可以继续使用旧的startActivityForResult。 唯一的限制是你必须使用setResult(result, intent)在你的活动中设置结果。 关键是让结果将请求代码带回结果使用者。

public class MyBaseActivity extends AppCompatActivity {
    private ActivityResultLauncher<Intent> activityLauncher;
    protected static String ACTIVITY_REQUEST_CODE = "my.activity.request.code";
    protected _originalIntent; 

    public void launchActivityForResult(Intent intent, int requestCode){
        intent.putExtra(UGM_ACTIVITY_REQUEST_CODE, requestCode);
        activityLauncher.launch(intent);
    }

    //
    //In order to be signature compatible for the rest of derived activities, 
    //we will override the deprecated method with our own implementation!
    //
    @SuppressWarnings( "deprecation" )
    public void startActivityForResult(Intent intent, int requestCode){
        launchActivityForResult(intent, requestCode);
    }

    @Override
    protected void onCreate(@Nullable Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

    _originalIntent = getIntent();
        //set the default result
        setResult(Activity.RESULT_OK, _originalIntent);

        activityLauncher = registerForActivityResult(new ActivityResultContracts.StartActivityForResult(), new ActivityResultCallback<ActivityResult>() {
            @Override
            public void onActivityResult(ActivityResult result) {
                Intent intent = result.getData();
                int requestCode = intent.getIntExtra(ACTIVITY_REQUEST_CODE, -1);
                MyBaseActivity.this.onActivityResult(requestCode, result.getResultCode(), intent);
            }
        });
    }

}

下面我来解释一下这种新方法

private val scan =
        registerForActivityResult(ActivityResultContracts.StartActivityForResult())
        { result: ActivityResult ->
            if (result.resultCode == AppCompatActivity.RESULT_OK && result.data != null) {

                var selected_hub = result!!.data!!.getParcelableExtra<ExtendedBluetoothDevice>(Utils.EXTRA_DEVICE)
                Log.d(TAG,"RECONNECT PROCESS "+selected_hub!!.name)
                reconnect(selected_hub!!)

            }
        }

从活动或片段调用此方法

private fun callScan() {
        val intent = Intent(requireActivity(), ScanningMeshDevices::class.java)
        scan.launch(intent)
    }

在我的情况下,我试图使用意图,我直接移动到下一个活动,而不使用谷歌登录。

对我有用的是:

在OnCreate中为登录按钮设置onClickListener:

     btnSignIn.setOnClickListener {
        signIn()
        }

    private fun signIn() {
        val intent = client.signInIntent
        mainActivityResultLauncher.launch(intent)
    }

在上面的代码中,我写了去下一个活动的意图,但我必须写client.signInIntent

    var mainActivityResultLauncher = registerForActivityResult(ActivityResultContracts.StartActivityForResult()){ result ->

        if(result.resultCode == Activity.RESULT_OK){
            val data = result.data
            val task = GoogleSignIn.getSignedInAccountFromIntent(data)
            try {
                // Google Sign In was successful, authenticate with Firebase
                val account = task.getResult(ApiException::class.java)!!
                Log.d(TAG, "firebaseAuthWithGoogle:" + account.id)
                firebaseAuthWithGoogle(account.idToken!!)
            } catch (e: ApiException) {
                // Google Sign In failed, update UI appropriately
                Log.w(TAG, "Google sign in failed", e)
            }
        }
    }