我最近发现onActivityResult已弃用。我们该怎么处理呢?
有什么替代方案吗?
我最近发现onActivityResult已弃用。我们该怎么处理呢?
有什么替代方案吗?
当前回答
dor506回答为我工作,因为我在我的大多数项目中使用BaseActivity,所以对我来说更容易在单个文件中更改代码,而不是我所有的活动。我已经写了这个代码的java版本。
BaseActivity代码:
private int requestCode = -1;
private ActivityResultLauncher<Intent> resultHandler = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mContext = this;
registerForActivityResult();
}
private final void registerForActivityResult() {
if (shouldRegisterForActivityResult()) {
this.resultHandler = registerForActivityResult(new ActivityResultContracts.StartActivityForResult(),
new ActivityResultCallback() {
public void onActivityResult(Object var1) {
this.onActivityResult((ActivityResult)var1);
}
public final void onActivityResult(ActivityResult result) {
Intrinsics.checkNotNullExpressionValue(result, "result");
AppActivityClass.onActivityResult(result.getData(), AppActivityClass.this.requestCode, result.getResultCode());
AppActivityClass.this.requestCode = -1;
}
});
}
}
public final void startActivityForResult(int requestCode, Intent intent) {
this.requestCode = requestCode;
if (resultHandler != null) {
resultHandler.launch(intent);
}
}
protected static void onActivityResult(Intent intent, int requestCode, int resultCode) {
}
protected Boolean shouldRegisterForActivityResult() {
return false;
}
现在在任何活动中使用这样的代码:
@Override
protected Boolean shouldRegisterForActivityResult() {
return true; // this will override the baseactivity method and we can use onactivityresult
}
private void someMethod(){
Intent i = new Intent(mContext,SomeOtherClassActivity.class);
startActivityForResult(101,i);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == 101) {
if (resultCode == RESULT_OK) {
//revert from called class
}
}
}
其他回答
在替换已弃用的方法startActivityForResult(…)时,需要遵循4个简单的步骤。
In place of overridden method onActivityResult(..) - ActivityResultLauncher<Intent> activityResultLaunch = registerForActivityResult( new ActivityResultContracts.StartActivityForResult(), new ActivityResultCallback<ActivityResult>() { @Override public void onActivityResult(ActivityResult result) { if (result.getResultCode() == 123) { // ToDo : Do your stuff... } else if(result.getResultCode() == 321) { // ToDo : Do your stuff... } } });
对于多个自定义请求,将条件附加为
if (result.getResultCode() == 123) {
..
} else if(result.getResultCode() == 131){
..
} // so on..
Imports : import androidx.activity.result.ActivityResult; import androidx.activity.result.ActivityResultCallback; import androidx.activity.result.ActivityResultLauncher; import androidx.activity.result.contract.ActivityResultContracts; In place of startActivityForResult(intent, 123), use Intent intent = new Intent(this, SampleActivity.class); activityResultLaunch.launch(intent); In SampleActivity.java class, while returning back to source activity, code will remain the same like - Intent intent = new Intent(); setResult(123, intent); finish();
编码快乐!:)
ActivityResultLauncher<Intent> someActivityResultLauncher = registerForActivityResult(
new ActivityResultContracts.StartActivityForResult(),
new ActivityResultCallback<ActivityResult>() {
@Override
public void onActivityResult(ActivityResult result) {
if (result.getResultCode() == Activity.RESULT_OK) {
}
}
});
如果你像这样实现你的base Activity,你可以继续使用旧的startActivityForResult。 唯一的限制是你必须使用setResult(result, intent)在你的活动中设置结果。 关键是让结果将请求代码带回结果使用者。
public class MyBaseActivity extends AppCompatActivity {
private ActivityResultLauncher<Intent> activityLauncher;
protected static String ACTIVITY_REQUEST_CODE = "my.activity.request.code";
protected _originalIntent;
public void launchActivityForResult(Intent intent, int requestCode){
intent.putExtra(UGM_ACTIVITY_REQUEST_CODE, requestCode);
activityLauncher.launch(intent);
}
//
//In order to be signature compatible for the rest of derived activities,
//we will override the deprecated method with our own implementation!
//
@SuppressWarnings( "deprecation" )
public void startActivityForResult(Intent intent, int requestCode){
launchActivityForResult(intent, requestCode);
}
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
_originalIntent = getIntent();
//set the default result
setResult(Activity.RESULT_OK, _originalIntent);
activityLauncher = registerForActivityResult(new ActivityResultContracts.StartActivityForResult(), new ActivityResultCallback<ActivityResult>() {
@Override
public void onActivityResult(ActivityResult result) {
Intent intent = result.getData();
int requestCode = intent.getIntExtra(ACTIVITY_REQUEST_CODE, -1);
MyBaseActivity.this.onActivityResult(requestCode, result.getResultCode(), intent);
}
});
}
}
下面我来解释一下这种新方法
private val scan =
registerForActivityResult(ActivityResultContracts.StartActivityForResult())
{ result: ActivityResult ->
if (result.resultCode == AppCompatActivity.RESULT_OK && result.data != null) {
var selected_hub = result!!.data!!.getParcelableExtra<ExtendedBluetoothDevice>(Utils.EXTRA_DEVICE)
Log.d(TAG,"RECONNECT PROCESS "+selected_hub!!.name)
reconnect(selected_hub!!)
}
}
从活动或片段调用此方法
private fun callScan() {
val intent = Intent(requireActivity(), ScanningMeshDevices::class.java)
scan.launch(intent)
}
在我的情况下,我试图使用意图,我直接移动到下一个活动,而不使用谷歌登录。
对我有用的是:
在OnCreate中为登录按钮设置onClickListener:
btnSignIn.setOnClickListener {
signIn()
}
private fun signIn() {
val intent = client.signInIntent
mainActivityResultLauncher.launch(intent)
}
在上面的代码中,我写了去下一个活动的意图,但我必须写client.signInIntent
var mainActivityResultLauncher = registerForActivityResult(ActivityResultContracts.StartActivityForResult()){ result ->
if(result.resultCode == Activity.RESULT_OK){
val data = result.data
val task = GoogleSignIn.getSignedInAccountFromIntent(data)
try {
// Google Sign In was successful, authenticate with Firebase
val account = task.getResult(ApiException::class.java)!!
Log.d(TAG, "firebaseAuthWithGoogle:" + account.id)
firebaseAuthWithGoogle(account.idToken!!)
} catch (e: ApiException) {
// Google Sign In failed, update UI appropriately
Log.w(TAG, "Google sign in failed", e)
}
}
}