string类有一个构造函数，它接受一个以null结束的C-string:

char arr[ ] = "This is a test";

string str(arr);


//  You can also assign directly to a string.
str = "This is another string";

// or
str = arr;

另一个解可能是这样的，

char arr[] = "mom";
std::cout << "hi " << std::string(arr);

这避免了使用额外的变量。

#include <stdio.h>
#include <iostream>
#include <stdlib.h>
#include <string>

using namespace std;

int main ()
{
  char *tmp = (char *)malloc(128);
  int n=sprintf(tmp, "Hello from Chile.");

  string tmp_str = tmp;


  cout << *tmp << " : is a char array beginning with " <<n <<" chars long\n" << endl;
  cout << tmp_str << " : is a string with " <<n <<" chars long\n" << endl;

 free(tmp); 
 return 0;
}

OUT:

H : is a char array beginning with 17 chars long

Hello from Chile. :is a string with 17 chars long

投票最多的答案中漏掉了一个小问题。即字符数组可以包含0。如果我们将使用单参数构造函数如上所述，我们将丢失一些数据。可能的解决方案是:

cout << string("123\0 123") << endl;
cout << string("123\0 123", 8) << endl;

输出是:

123 123, 123

基于OP的位<O/T>，但我谷歌了“c++转换std::array char到字符串”，它把我带到这里，但没有一个现有的答案处理std::array<char， ..>:

#include <string>
#include <iostream>
#include <array>
 
int main()
{
  // initialize a char array with "hello\0";
  std::array<char, 6> bar{"hello"};
  // create a string from it using the .data() ptr,
  // this uses the `const char*` ctor of the string
  std::string myString(bar.data());
  // output
  std::cout << myString << std::endl;

  return 0;
}

输出

hello

示范