这段代码工作,并向我发送电子邮件就好:

import smtplib
#SERVER = "localhost"

FROM = 'monty@python.com'

TO = ["jon@mycompany.com"] # must be a list

SUBJECT = "Hello!"

TEXT = "This message was sent with Python's smtplib."

# Prepare actual message

message = """\
From: %s
To: %s
Subject: %s

%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)

# Send the mail

server = smtplib.SMTP('myserver')
server.sendmail(FROM, TO, message)
server.quit()

然而,如果我试图将它包装在这样一个函数中:

def sendMail(FROM,TO,SUBJECT,TEXT,SERVER):
    import smtplib
    """this is some test documentation in the function"""
    message = """\
        From: %s
        To: %s
        Subject: %s
        %s
        """ % (FROM, ", ".join(TO), SUBJECT, TEXT)
    # Send the mail
    server = smtplib.SMTP(SERVER)
    server.sendmail(FROM, TO, message)
    server.quit()

我得到以下错误:

 Traceback (most recent call last):
  File "C:/Python31/mailtest1.py", line 8, in <module>
    sendmail.sendMail(sender,recipients,subject,body,server)
  File "C:/Python31\sendmail.py", line 13, in sendMail
    server.sendmail(FROM, TO, message)
  File "C:\Python31\lib\smtplib.py", line 720, in sendmail
    self.rset()
  File "C:\Python31\lib\smtplib.py", line 444, in rset
    return self.docmd("rset")
  File "C:\Python31\lib\smtplib.py", line 368, in docmd
    return self.getreply()
  File "C:\Python31\lib\smtplib.py", line 345, in getreply
    raise SMTPServerDisconnected("Connection unexpectedly closed")
smtplib.SMTPServerDisconnected: Connection unexpectedly closed

有人能告诉我为什么吗?


当前回答

下面是Python 3的一个例子。X,比2.x简单得多:

import smtplib
from email.message import EmailMessage
def send_mail(to_email, subject, message, server='smtp.example.cn',
              from_email='xx@example.com'):
    # import smtplib
    msg = EmailMessage()
    msg['Subject'] = subject
    msg['From'] = from_email
    msg['To'] = ', '.join(to_email)
    msg.set_content(message)
    print(msg)
    server = smtplib.SMTP(server)
    server.set_debuglevel(1)
    server.login(from_email, 'password')  # user & password
    server.send_message(msg)
    server.quit()
    print('successfully sent the mail.')

调用这个函数:

send_mail(to_email=['12345@qq.com', '12345@126.com'],
          subject='hello', message='Your analysis has done!')

以下仅限中国用户使用:

If you use 126/163, NetEase Mail, you need to set" Client Authorization Password ", like below:

裁判:https://stackoverflow.com/a/41470149/2803344 https://docs.python.org/3/library/email.examples.html#email-examples

其他回答

只是为了补充答案,以便您的邮件传递系统可以扩展。

我建议有一个配置文件(可以是.json, .yml, .ini等),包含发件人的电子邮件配置,密码和收件人。

通过这种方式,您可以根据需要创建不同的可定制项目。

下面是一个包含3个文件,config, functions和main的小示例。纯文本邮件。

config_email.ini

[email_1]
sender = test@test.com
password = XXXXXXXXXXX
recipients= ["email_2@test.com", "email_2@test.com"]

[email_2]
sender = test_2@test.com
password = XXXXXXXXXXX
recipients= ["email_2@test.com", "email_2@test.com", "email_3@test.com"]

这些项将从main.py调用,它将返回它们各自的值。

函数functions_email.py文件:

import smtplib,configparser,json
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

def get_credentials(item):
    parse = configparser.ConfigParser()
    parse.read('config_email.ini')
    sender = parse[item]['sender ']
    password = parse[item]['password']
    recipients= json.loads(parse[item]['recipients'])
    return sender,password,recipients

def get_msg(sender,recipients,subject,mail_body):
    msg = MIMEMultipart()
    msg['Subject'] = subject
    msg['From'] = sender 
    msg['To'] = ', '.join(recipients)       
    text = """\
    """+mail_body+""" """
    part1 = MIMEText(text, "plain")
    msg.attach(part1)
    return msg

def send_email(msg,sender,password,recipients):
    s = smtplib.SMTP('smtp.test.com')
    s.login(sender,password)
    s.sendmail(sender, recipients, msg.as_string())
    s.quit()    

文件main.py:

from functions_email import *

sender,password,recipients = get_credenciales('email_2')
subject= 'text to subject'
mail_body = 'body....................'
msg = get_msg(sender,recipients ,subject,mail_body)    
send_email(msg,sender,password,recipients)

最好的问候!

有压痕问题。下面的代码将工作:

import textwrap

def sendMail(FROM,TO,SUBJECT,TEXT,SERVER):
    import smtplib
    """this is some test documentation in the function"""
    message = textwrap.dedent("""\
        From: %s
        To: %s
        Subject: %s
        %s
        """ % (FROM, ", ".join(TO), SUBJECT, TEXT))
    # Send the mail
    server = smtplib.SMTP(SERVER)
    server.sendmail(FROM, TO, message)
    server.quit()

当我需要在Python中发送邮件时,我使用mailgun API,它在发送邮件时遇到了很多麻烦。他们有一个很棒的应用程序/api,可以让你每月发送5000封免费电子邮件。

发送电子邮件是这样的:

def send_simple_message():
    return requests.post(
        "https://api.mailgun.net/v3/YOUR_DOMAIN_NAME/messages",
        auth=("api", "YOUR_API_KEY"),
        data={"from": "Excited User <mailgun@YOUR_DOMAIN_NAME>",
              "to": ["bar@example.com", "YOU@YOUR_DOMAIN_NAME"],
              "subject": "Hello",
              "text": "Testing some Mailgun awesomness!"})

您还可以跟踪事件和更多信息,参见快速入门指南。

我建议您使用标准包email和smtplib一起发送电子邮件。请看下面的例子(摘自Python文档)。注意,如果遵循这种方法,“简单”任务确实很简单,而更复杂的任务(如附加二进制对象或发送纯/HTML多部分消息)将很快完成。

# Import smtplib for the actual sending function
import smtplib

# Import the email modules we'll need
from email.mime.text import MIMEText

# Open a plain text file for reading.  For this example, assume that
# the text file contains only ASCII characters.
with open(textfile, 'rb') as fp:
    # Create a text/plain message
    msg = MIMEText(fp.read())

# me == the sender's email address
# you == the recipient's email address
msg['Subject'] = 'The contents of %s' % textfile
msg['From'] = me
msg['To'] = you

# Send the message via our own SMTP server, but don't include the
# envelope header.
s = smtplib.SMTP('localhost')
s.sendmail(me, [you], msg.as_string())
s.quit()

要将电子邮件发送到多个目的地,您还可以遵循Python文档中的示例:

# Import smtplib for the actual sending function
import smtplib

# Here are the email package modules we'll need
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart

# Create the container (outer) email message.
msg = MIMEMultipart()
msg['Subject'] = 'Our family reunion'
# me == the sender's email address
# family = the list of all recipients' email addresses
msg['From'] = me
msg['To'] = ', '.join(family)
msg.preamble = 'Our family reunion'

# Assume we know that the image files are all in PNG format
for file in pngfiles:
    # Open the files in binary mode.  Let the MIMEImage class automatically
    # guess the specific image type.
    with open(file, 'rb') as fp:
        img = MIMEImage(fp.read())
    msg.attach(img)

# Send the email via our own SMTP server.
s = smtplib.SMTP('localhost')
s.sendmail(me, family, msg.as_string())
s.quit()

如您所见,MIMEText对象中的报头To必须是由逗号分隔的电子邮件地址组成的字符串。另一方面,sendmail函数的第二个参数必须是一个字符串列表(每个字符串都是一个电子邮件地址)。

所以,如果你有三个电子邮件地址:person1@example.com, person2@example.com和person3@example.com,你可以这样做(明显的部分省略了):

to = ["person1@example.com", "person2@example.com", "person3@example.com"]
msg['To'] = ",".join(to)
s.sendmail(me, to, msg.as_string())

",".join(to)部分从列表中生成一个单独的字符串,用逗号分隔。

从你的问题中,我猜你还没有读过Python教程——如果你想在Python中有所了解,这是必须的——标准库的文档大部分都很出色。

我想我应该把我的两个比特放在这里,因为我刚刚明白了它是如何工作的。

似乎你没有在你的服务器连接设置上指定端口,这影响了我一点,当我试图连接到我的SMTP服务器,没有使用默认端口:25。

根据smtplib。SMTP文档,您的ehlo或helo请求/响应应该自动处理,所以您不必担心这一点(但如果其他都失败了,可能需要确认)。

另一个问题是你是否允许在你的SMTP服务器上进行SMTP连接?对于像GMAIL和ZOHO这样的网站,你必须实际进入并激活电子邮件帐户中的IMAP连接。您的邮件服务器可能不允许SMTP连接不是来自'localhost'也许?一些值得调查的事情。

最后一件事是你可能想尝试在TLS上发起连接。现在大多数服务器都需要这种类型的身份验证。

您将看到我在电子邮件中插入了两个TO字段。msg['TO']和msg['FROM'] msg字典项允许正确的信息显示在电子邮件本身的标题中,这可以在电子邮件的接收端的TO / FROM字段中看到(你甚至可以在这里添加一个Reply TO字段)。TO和FROM字段本身就是服务器所需要的。我知道我听说过一些电子邮件服务器拒绝邮件,如果他们没有适当的电子邮件标题。

这是我使用的代码,在一个函数中,为我工作,使用我的本地计算机和远程SMTP服务器(ZOHO所示)发送*.txt文件的内容:

def emailResults(folder, filename):

    # body of the message
    doc = folder + filename + '.txt'
    with open(doc, 'r') as readText:
        msg = MIMEText(readText.read())

    # headers
    TO = 'to_user@domain.com'
    msg['To'] = TO
    FROM = 'from_user@domain.com'
    msg['From'] = FROM
    msg['Subject'] = 'email subject |' + filename

    # SMTP
    send = smtplib.SMTP('smtp.zoho.com', 587)
    send.starttls()
    send.login('from_user@domain.com', 'password')
    send.sendmail(FROM, TO, msg.as_string())
    send.quit()