在Jest测试中,我一直得到“localStorage is not defined”,这是有意义的,但我的选项是什么?碰壁。


当前回答

在这个网站的帮助下,我们找到了答案:https://groups.google.com/forum/#!主题/ jestjs / 9 ephunwvytg

设置一个包含以下内容的文件:

var localStorageMock = (function() {
  var store = {};
  return {
    getItem: function(key) {
      return store[key];
    },
    setItem: function(key, value) {
      store[key] = value.toString();
    },
    clear: function() {
      store = {};
    },
    removeItem: function(key) {
      delete store[key];
    }
  };
})();
Object.defineProperty(window, 'localStorage', { value: localStorageMock });

然后将以下行添加到包中。json在你的Jest配置

:“setupTestFrameworkScriptFile PATH_TO_YOUR_FILE”,

其他回答

不需要模拟localStorage—只需使用jsdom环境,这样您的测试就可以在类似浏览器的条件下运行。

在你的joke。config。js中,

module.exports = {
    // ...
    testEnvironment: "jsdom"
}
    

正如Niket Pathak在评论中提到的, 从jest@24 / jsdom@11.12.0及以上开始,localStorage将自动被模拟。

一个更好的替代方法,它处理未定义的值(它不需要toString()),如果值不存在则返回null。用react v15、redux和redux-auth-wrapper进行了测试

class LocalStorageMock {
  constructor() {
    this.store = {}
  }

  clear() {
    this.store = {}
  }

  getItem(key) {
    return this.store[key] || null
  }

  setItem(key, value) {
    this.store[key] = value
  }

  removeItem(key) {
    delete this.store[key]
  }
}

global.localStorage = new LocalStorageMock

@chiedo的好解决方案

然而,我们使用ES2015语法,我觉得这样写会更简洁一些。

class LocalStorageMock {
  constructor() {
    this.store = {};
  }

  clear() {
    this.store = {};
  }

  getItem(key) {
    return this.store[key] || null;
  }

  setItem(key, value) {
    this.store[key] = String(value);
  }

  removeItem(key) {
    delete this.store[key];
  }
}

global.localStorage = new LocalStorageMock;
Object.defineProperty(window, "localStorage", {
  value: {
    getItem: jest.fn(),
    setItem: jest.fn(),
    removeItem: jest.fn(),
  },
});

or

jest.spyOn(Object.getPrototypeOf(localStorage), "getItem");
jest.spyOn(Object.getPrototypeOf(localStorage), "setItem");