我通过OAuth从Twitter导入XML。

我正在做一个请求http://twitter.com/account/verify_credentials.xml,它返回以下XML:

<?xml version="1.0" encoding="UTF-8"?>
<user>
  <id>16434938</id>
  <name>Lloyd Sparkes</name>
  <screen_name>lloydsparkes</screen_name>
  <location>Hockley, Essex, UK</location>
  <description>Student</description>
  <profile_image_url>http://a3.twimg.com/profile_images/351849613/twitterProfilePhoto_normal.jpg</profile_image_url>
  <url>http://www.lloydsparkes.co.uk</url>
  <protected>false</protected>
  <followers_count>115</followers_count>
  <profile_background_color>9fdaf4</profile_background_color>
  <profile_text_color>000000</profile_text_color>
  <profile_link_color>220f7b</profile_link_color>
  <profile_sidebar_fill_color>FFF7CC</profile_sidebar_fill_color>
  <profile_sidebar_border_color>F2E195</profile_sidebar_border_color>
  <friends_count>87</friends_count>
  <created_at>Wed Sep 24 14:26:09 +0000 2008</created_at>
  <favourites_count>0</favourites_count>
  <utc_offset>0</utc_offset>
  <time_zone>London</time_zone>
  <profile_background_image_url>http://s.twimg.com/a/1255366924/images/themes/theme12/bg.gif</profile_background_image_url>
  <profile_background_tile>false</profile_background_tile>
  <statuses_count>1965</statuses_count>
  <notifications>false</notifications>
  <geo_enabled>false</geo_enabled>
  <verified>false</verified>
  <following>false</following>
  <status>
    <created_at>Mon Oct 12 19:23:47 +0000 2009</created_at>
    <id>4815268670</id>
    <text>&#187; @alexmuller your kidding? it should all be &quot;black tie&quot; dress code</text>
    <source>&lt;a href=&quot;http://code.google.com/p/wittytwitter/&quot; rel=&quot;nofollow&quot;&gt;Witty&lt;/a&gt;</source>
    <truncated>false</truncated>
    <in_reply_to_status_id>4815131457</in_reply_to_status_id>
    <in_reply_to_user_id>8645442</in_reply_to_user_id>
    <favorited>false</favorited>
    <in_reply_to_screen_name>alexmuller</in_reply_to_screen_name>
    <geo/>
  </status>
</user>

我使用下面的代码来反序列化:

    public User VerifyCredentials()
    {
        string url = "http://twitter.com/account/verify_credentials.xml";
        string xml = _oauth.oAuthWebRequestAsString(oAuthTwitter.Method.GET, url, null);

        XmlSerializer xs = new XmlSerializer(typeof(User),"");

        MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(xml));

        return (User)xs.Deserialize(ms);
    }

我有以下为我的用户类:

 [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class User
{

    [XmlElement(ElementName = "id")]       
    public long Id { get; set; }

    [XmlElement(ElementName = "name")] 
    public string Name { get; set; }

    [XmlElement(ElementName = "screen_name")]       
    public string ScreenName { get; set; }

    [XmlElement(ElementName = "location")]       
    public string Location { get; set; }

    [XmlElement(ElementName = "description")]      
    public string Description { get; set; }

    [XmlElement(ElementName = "profile_image_url")]      
    public string ProfileImageUrl { get; set; }

    [XmlElement(ElementName = "url")]       
    public string Url { get; set; }

    [XmlElement(ElementName = "protected")]      
    public bool Protected { get; set; }

    [XmlElement(ElementName = "followers_count")]      
    public int FollowerCount { get; set; }

    [XmlElement(ElementName = "profile_background_color")]       
    public string ProfileBackgroundColor { get; set; }

    [XmlElement(ElementName = "profile_text_color")]       
    public string ProfileTextColor { get; set; }

    [XmlElement(ElementName = "profile_link_color")]       
    public string ProfileLinkColor { get; set; }

    [XmlElement(ElementName = "profile_sidebar_fill_color")]       
    public string ProfileSidebarFillColor { get; set; }

    [XmlElement(ElementName = "profile_sidebar_border_color")]      
    public string ProfileSidebarBorderColor { get; set; }

    [XmlElement(ElementName = "friends_count")]     
    public int FriendsCount { get; set; }

    [XmlElement(ElementName = "created_at")]     
    public string CreatedAt { get; set; }

    [XmlElement(ElementName = "favourties_count")]      
    public int FavouritesCount { get; set; }

    [XmlElement(ElementName = "utc_offset")]      
    public int UtcOffset { get; set; }

    [XmlElement(ElementName = "time_zone")]       
    public string Timezone { get; set; }

    [XmlElement(ElementName = "profile_background_image_url")]        
    public string ProfileBackgroundImageUrl { get; set; }

    [XmlElement(ElementName = "profile_background_tile")]        
    public bool ProfileBackgroundTile { get; set; }

    [XmlElement(ElementName = "statuese_count")]        
    public int StatusesCount { get; set; }

    [XmlElement(ElementName = "notifications")]       
    public string Notifications { get; set; }

    [XmlElement(ElementName = "geo_enabled")]       
    public bool GeoEnabled { get; set; }

    [XmlElement(ElementName = "Verified")]        
    public bool Verified { get; set; }

    [XmlElement(ElementName = "following")]
    public string Following { get; set; }

    [XmlElement(ElementName = "status", IsNullable=true)]
    public Status CurrentStatus { get; set; }

}

但是当它反序列化上面的XML时,应用程序抛出如下:

$exception {" XML文档(2,2)中存在错误。"}系统。异常{系统。InvalidOperationException}

InnerException {"<user xmlns= " >不是预期的。"}系统。异常{系统。InvalidOperationException}

现在我已经四处搜索,我能找到的最佳解决方案是在序列化内容时向序列化器添加空白名称空间,但我没有序列化它,所以我不能。

我还有一些用于接收状态的代码,这些代码工作得很好。

有人能解释一下为什么会出现错误吗?以及一个可能的解决方案?


要么用XmlRoot属性装饰根实体,该属性将在编译时使用。

[XmlRoot(Namespace = "www.contoso.com", ElementName = "MyGroupName", DataType = "string", IsNullable=true)]

或在运行时反序列化时指定根属性。

XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "user";
// xRoot.Namespace = "http://www.cpandl.com";
xRoot.IsNullable = true;

XmlSerializer xs = new XmlSerializer(typeof(User),xRoot);

正如John Saunders所说,检查类名/属性名是否与XML的大写字母匹配。如果不是这样,问题也会出现。


更简单的方法是在类的顶部添加以下注释:

[Serializable, XmlRoot("user")]
public partial class User
{
}

错误信息是如此模糊,对于我来说,我有这样的代码:

var streamReader = new StreamReader(response.GetResponseStream());
var xmlSerializer = new XmlSerializer(typeof(aResponse));
theResponse = (bResponse) xmlSerializer.Deserialize(streamReader);

注意xmlSerializer是用aResponse实例化的,但在反序列化时,我意外地将它强制转换为bresonance。


XmlSerializer xs = new XmlSerializer(typeof(User), new XmlRootAttribute("yourRootName")); 

我的问题是我的一个元素有xmlns属性:

<?xml version="1.0" encoding="utf-8"?>
<RETS ReplyCode="0">
    <RETS-RESPONSE xmlns="blahblah">
        ...
    </RETS-RESPONSE>
</RETS>

无论我尝试什么,xmlns属性似乎破坏了序列化器,所以我从xml文件中删除了xmlns="…"的任何痕迹:

<?xml version="1.0" encoding="utf-8"?>
<RETS ReplyCode="0">
    <RETS-RESPONSE>
        ...
    </RETS-RESPONSE>
</RETS>

瞧!一切工作。

我现在解析xml文件,在反序列化之前删除这个属性。 不确定为什么这样工作,也许我的情况不同,因为包含xmlns属性的元素不是根元素。


对我来说唯一有效的方法就是用大卫瓦伦丁的密码。使用根属性。在Person类中没有帮助。

我有这个简单的Xml:

<?xml version="1.0"?>
<personList>
 <Person>
  <FirstName>AAAA</FirstName>
  <LastName>BBB</LastName>
 </Person>
 <Person>
  <FirstName>CCC</FirstName>
  <LastName>DDD</LastName>
 </Person>
</personList>

c#类:

public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
}

从Main方法反序列化c#代码:

XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "personList";
xRoot.IsNullable = true;
using (StreamReader reader = new StreamReader(xmlFilePath))
{
List<Person> result = (List<Person>)(new XmlSerializer(typeof(List<Person>), xRoot)).Deserialize(reader);
 int numOfPersons = result.Count;
}  

最简单、最好的解决方案是在希望反序列化的类中使用XMLRoot属性。

如:

[XmlRoot(ElementName = "YourPreferableNameHere")]
public class MyClass{
...
}

同样,使用以下程序集:

using System.Xml.Serialization;

我的问题是根元素实际上有一个xmlns="abc123"

因此必须创建XmlRoot("elementname",NameSpace="abc123")


以上这些对我都不起作用,但这是: 检查类的Root元素的名称是否与XML中区分大小写的名称完全相同。


在我的例子中,我的xml有多个名称空间和属性。 所以我使用这个网站来生成对象- https://xmltocsharp.azurewebsites.net/

并使用下面的代码进行反序列化

 XmlDocument doc =  new XmlDocument();
        doc.Load("PathTo.xml");
        User obj;
        using (TextReader textReader = new StringReader(doc.OuterXml))
        {
            using (XmlTextReader reader = new XmlTextReader(textReader))
            {
                XmlSerializer serializer = new XmlSerializer(typeof(User));
                obj = (User)serializer.Deserialize(reader);
            }
        }

对于这些错误,除了

... was not expected, 
... there is an error in XML document (1,2)
... System.FormatException Input String was not in correct format ...

除了这种方式

1-你需要检查xml响应作为字符串(响应,你试图反序列化到一个对象)

2-使用在线工具进行字符串unescape和xml美化/格式化

3-确保你试图映射/反序列化xml字符串的c#类(主类)有一个XmlRootAttribute,匹配响应的根元素。

例子:

我的XML响应是这样的:

<ShipmentCreationResponse xmlns="http://ws.aramex.net/ShippingAPI/v1/">
       <Transaction i:nil="true" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"/>
           ....

c#类定义+属性是这样的:

[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.CodeDom.Compiler.GeneratedCodeAttribute("System.ServiceModel", "4.0.0.0")]
[System.ServiceModel.MessageContractAttribute(WrapperName="ShipmentCreationResponse", WrapperNamespace="http://ws.aramex.net/ShippingAPI/v1/", IsWrapped=true)]
public partial class ShipmentCreationResponse {
  .........
}

注意,类定义没有“XmlRootAttribute”

[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://ws.aramex.net/ShippingAPI/v1/", IsNullable = false)]

当我尝试使用泛型方法反序列化:

public static T Deserialize<T>(string input) where T : class
{
    System.Xml.Serialization.XmlSerializer ser = new System.Xml.Serialization.XmlSerializer(typeof(T));

    using (System.IO.StringReader sr = new System.IO.StringReader(input))
    {
        return (T)ser.Deserialize(sr);
    }
}





var _Response = GeneralHelper.XMLSerializer.Deserialize<ASRv2.ShipmentCreationResponse>(xml);

我得到了上面的错误

... was not expected, ... there is an error in XML document (1,2) ...

现在,通过添加“XmlRootAttribute”,修复了这个问题,为每一个其他的请求/响应,我有一个类似的问题:

[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://ws.aramex.net/ShippingAPI/v1/", IsNullable = false)]

..

[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://ws.aramex.net/ShippingAPI/v1/")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://ws.aramex.net/ShippingAPI/v1/", IsNullable = false)]
public partial class ShipmentCreationResponse
{
    ........
}