是否可以查询包含以下列的表名

LIKE '%myName%'

?


当前回答

这是你问题的答案

SELECT c.name AS ColumnName, t.name AS TableName
FROM sys.columns c
    JOIN sys.tables t ON c.object_id = t.object_id
WHERE c.name LIKE '%myName%';

其他回答

如果只需要表名,可以运行:

select object_name(object_id) from sys.columns
where name like '%received_at%'

如果你也想要Schema Name(在很多情况下你会这样做,因为你会有很多不同的模式,除非你能记住数据库中的每个表及其所属的位置,否则这可能很有用),运行:

select OBJECT_SCHEMA_NAME(object_id),object_name(object_id) from sys.columns
where name like '%received_at%'

最后,如果你想要一个更好的格式(尽管这是代码(在我看来)变得太复杂而不容易编写的地方):

select concat(OBJECT_SCHEMA_NAME(object_id),'.',object_name(object_id)) from sys.columns
where name like '%received_at%'

注意,您还可以根据我的功能创建一个函数:

CREATE PROCEDURE usp_tablecheck
--Scan through all tables to identify all tables with columns that have the provided string
--Stephen B
@name nvarchar(200)
AS
SELECT CONCAT(OBJECT_SCHEMA_NAME(object_id),'.',object_name(object_id)) AS [Table Name], name AS [Column] FROM sys.columns
WHERE name LIKE CONCAT('%',@name,'%')
ORDER BY [Table Name] ASC, [Column] ASC
GO

值得注意的是,凹入功能是在2012年添加的。对于2008r2和更早版本,使用+连接字符串。

自从我发布这个之后,我已经重新格式化了进程。它现在有点高级了,但看起来更乱了(但它在一个proc中,所以你永远不会看到它),而且格式更好。

此版本允许您将其保存在管理数据库中,然后在任何数据库中进行搜索。将@db的分隔符从“master”更改为您希望的默认数据库(注意:除非将字符串连接更改为使用+运算符,否则使用CONCAT()函数只能用于2012+)。

CREATE PROCEDURE [dbo].[usp_tablecheck]
    --Scan through all tables to identify all tables in the specified database with columns that have the provided string
    --Stephen B
    @name nvarchar(200)
    ,@db nvarchar(200) = 'master'
AS
    DECLARE @sql nvarchar(4000) = CONCAT('
        SELECT concat(OBJECT_SCHEMA_NAME(col.object_id,DB_ID(''',@db,''')),''.'',object_name(col.object_id,DB_ID(''',@db,'''))) AS [Table Name]
            ,col.name AS [Column] 
        FROM ',@db,'.sys.columns col
        LEFT JOIN ',@db,'.sys.objects ob 
            ON ob.object_id = col.object_id
        WHERE 
            col.name LIKE CONCAT(''%'',''',@name,''',''%'') 
            AND ob.type =''U''
        ORDER BY [Table Name] ASC
            ,[Column] ASC')
    EXECUTE (@sql)
GO

我刚试过,这个效果很好

USE YourDatabseName
GO
SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%YourColumnName%'
ORDER BY schema_name, table_name;

只将YourDatabaseName更改为数据库,将YourcolumnName更改为您要查找的列名,其余的保持原样。

希望这有所帮助

SELECT  [TABLE_NAME] ,
        [INFORMATION_SCHEMA].COLUMNS.COLUMN_NAME
FROM    INFORMATION_SCHEMA.COLUMNS
WHERE   INFORMATION_SCHEMA.COLUMNS.COLUMN_NAME LIKE '%NAME%' ;

希望这不是一个重复的答案,但我想做的是在sql语句中生成一个sql语句,这将允许我搜索我要查找的值(而不仅仅是具有这些字段名称的表(因为通常我需要删除与我要查找列名称的id相关的任何信息):

  SELECT  'Select * from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'

然后我可以复制并粘贴运行我的第一列“SQLToRun”。。。然后我将“Select*from”替换为“Delete from”,它允许我删除对该给定ID的任何引用!将这些结果写入文件,以备不时之需。

注意***在运行delete语句之前,请确保消除所有bakup表。。。

  SELECT  'Delete from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'

我们还可以使用以下语法:-

select * from INFORMATION_SCHEMA.COLUMNS 
where COLUMN_NAME like '%clientid%' 
order by TABLE_NAME