这是你问题的答案

SELECT c.name AS ColumnName, t.name AS TableName
FROM sys.columns c
    JOIN sys.tables t ON c.object_id = t.object_id
WHERE c.name LIKE '%myName%';

我不知道为什么很多人建议使用sys.columns加入sys.table。

您可以使用以下代码：

SELECT Object_name(object_id) AS TableName,
       *
FROM   sys.columns
WHERE  NAME LIKE '%MyName%' 

or

如果还需要架构名称：

SELECT *
FROM   information_schema.columns
WHERE  column_name LIKE '%MyName%' 

SELECT  [TABLE_NAME] ,
        [INFORMATION_SCHEMA].COLUMNS.COLUMN_NAME
FROM    INFORMATION_SCHEMA.COLUMNS
WHERE   INFORMATION_SCHEMA.COLUMNS.COLUMN_NAME LIKE '%NAME%' ;

我们还可以使用以下语法：-

select * from INFORMATION_SCHEMA.COLUMNS 
where COLUMN_NAME like '%clientid%' 
order by TABLE_NAME

您可以通过column_name过滤器从INFORMATION_SCHEMA.COLUMNS中找到它

Select DISTINCT TABLE_NAME as TableName,COLUMN_NAME as ColumnName
     From INFORMATION_SCHEMA.COLUMNS Where column_name like '%myname%'

这应该是有效的：

SELECT name 
FROM sysobjects 
WHERE id IN ( SELECT id 
              FROM syscolumns 
              WHERE name like '%column_name%' )