是否可以查询包含以下列的表名

LIKE '%myName%'

?


当前回答

这是你问题的答案

SELECT c.name AS ColumnName, t.name AS TableName
FROM sys.columns c
    JOIN sys.tables t ON c.object_id = t.object_id
WHERE c.name LIKE '%myName%';

其他回答

您可以通过column_name过滤器从INFORMATION_SCHEMA.COLUMNS中找到它

Select DISTINCT TABLE_NAME as TableName,COLUMN_NAME as ColumnName
     From INFORMATION_SCHEMA.COLUMNS Where column_name like '%myname%'
DECLARE @columnName as varchar(100)
SET @columnName = 'ColumnName'

SELECT t.name AS Table, c.name AS Column,
ty.name AS Type, c.max_length AS Length
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
INNER JOIN sys.types ty ON c.system_type_id = ty.system_type_id
WHERE c.name LIKE @columnName
ORDER BY t.name, c.name
SELECT COLUMN_NAME, TABLE_NAME
  FROM INFORMATION_SCHEMA.COLUMNS    
 WHERE COLUMN_NAME LIKE '%myName%'

希望这不是一个重复的答案,但我想做的是在sql语句中生成一个sql语句,这将允许我搜索我要查找的值(而不仅仅是具有这些字段名称的表(因为通常我需要删除与我要查找列名称的id相关的任何信息):

  SELECT  'Select * from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'

然后我可以复制并粘贴运行我的第一列“SQLToRun”。。。然后我将“Select*from”替换为“Delete from”,它允许我删除对该给定ID的任何引用!将这些结果写入文件,以备不时之需。

注意***在运行delete语句之前,请确保消除所有bakup表。。。

  SELECT  'Delete from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'

我们还可以使用以下语法:-

select * from INFORMATION_SCHEMA.COLUMNS 
where COLUMN_NAME like '%clientid%' 
order by TABLE_NAME