function main()
{
Hello();
}
function Hello()
{
// How do you find out the caller function is 'main'?
}
有办法找到调用堆栈吗?
当前回答
我认为下面的代码段可能会有帮助:
window.fnPureLog = function(sStatement, anyVariable) {
if (arguments.length < 1) {
throw new Error('Arguments sStatement and anyVariable are expected');
}
if (typeof sStatement !== 'string') {
throw new Error('The type of sStatement is not match, please use string');
}
var oCallStackTrack = new Error();
console.log(oCallStackTrack.stack.replace('Error', 'Call Stack:'), '\n' + sStatement + ':', anyVariable);
}
执行以下代码:
window.fnPureLog = function(sStatement, anyVariable) {
if (arguments.length < 1) {
throw new Error('Arguments sStatement and anyVariable are expected');
}
if (typeof sStatement !== 'string') {
throw new Error('The type of sStatement is not match, please use string');
}
var oCallStackTrack = new Error();
console.log(oCallStackTrack.stack.replace('Error', 'Call Stack:'), '\n' + sStatement + ':', anyVariable);
}
function fnBsnCallStack1() {
fnPureLog('Stock Count', 100)
}
function fnBsnCallStack2() {
fnBsnCallStack1()
}
fnBsnCallStack2();
日志是这样的:
Call Stack:
at window.fnPureLog (<anonymous>:8:27)
at fnBsnCallStack1 (<anonymous>:13:5)
at fnBsnCallStack2 (<anonymous>:17:5)
at <anonymous>:20:1
Stock Count: 100
其他回答
下面是一个函数来获得完整的stacktrace:
function stacktrace() {
var f = stacktrace;
var stack = 'Stack trace:';
while (f) {
stack += '\n' + f.name;
f = f.caller;
}
return stack;
}
注意，根据MDN文档，此解决方案已弃用，不应再使用
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function/caller
function Hello()
{
alert("caller is " + Hello.caller);
}
注意，这个特性不是标准的，来自Function.caller:
非标准的 这个特性是非标准的，不在标准轨道上。不要在面向Web的生产站点上使用它:它并不适用于每个用户。实现之间也可能存在很大的不兼容性，将来行为可能会发生变化。
以下是2008年的旧答案，在现代Javascript中不再支持:
function Hello()
{
alert("caller is " + arguments.callee.caller.toString());
}
在这里，除了函数名之外的所有内容都被RegExp从caller.toString()中剥离。
<!DOCTYPE html>
<meta charset="UTF-8">
<title>Show the callers name</title><!-- This validates as html5! -->
<script>
main();
function main() { Hello(); }
function Hello(){
var name = Hello.caller.toString().replace(/\s\([^#]+$|^[^\s]+\s/g,'');
name = name.replace(/\s/g,'');
if ( typeof window[name] !== 'function' )
alert ("sorry, the type of "+name+" is "+ typeof window[name]);
else
alert ("The name of the "+typeof window[name]+" that called is "+name);
}
</script>
由于之前的答案都不像我所寻找的那样(只得到最后一个函数调用者，而不是作为字符串或callstack的函数)，我在这里为那些像我一样的人发布了我的解决方案，希望这对他们有用:
function getCallerName(func) { if (!func) return "anonymous"; let caller = func.caller; if (!caller) return "anonymous"; caller = caller.toString(); if (!caller.trim().startsWith("function")) return "anonymous"; return caller.substring(0, caller.indexOf("(")).replace("function",""); } // Example of how to use "getCallerName" function function Hello(){ console.log("ex1 => " + getCallerName(Hello)); } function Main(){ Hello(); // another example console.log("ex3 => " + getCallerName(Main)); } Main();
使用严格模式开/关(JavaScript & TypeScript)，如果(!)调用者存在，你可以尝试这个
console.log(`caller:${(new Error()).stack?.split('\n')[2].trim().split(' ')[1]}`)
