有什么方法可以在jQueryAJAX错误消息中显示自定义异常消息作为警报吗?
例如,如果我想通过抛出新的ApplicationException(“用户名已经存在”),通过Struts在服务器端抛出异常;,我想在jQueryAJAX错误消息中捕获此消息(“用户名已存在”)。
jQuery("#save").click(function () {
if (jQuery('#form').jVal()) {
jQuery.ajax({
type: "POST",
url: "saveuser.do",
dataType: "html",
data: "userId=" + encodeURIComponent(trim(document.forms[0].userId.value)),
success: function (response) {
jQuery("#usergrid").trigger("reloadGrid");
clear();
alert("Details saved successfully!!!");
},
error: function (xhr, ajaxOptions, thrownError) {
alert(xhr.status);
alert(thrownError);
}
});
}
});
在错误回调中的第二个警报中,我向thrownError发出警报,我得到了未定义,xhr.status代码为500。
我不知道我错在哪里。我可以做什么来解决这个问题?
这就是我所做的,它目前在MVC 5应用程序中运行。
控制器的返回类型为ContentResult。
public ContentResult DoSomething()
{
if(somethingIsTrue)
{
Response.StatusCode = 500 //Anything other than 2XX HTTP status codes should work
Response.Write("My Message");
return new ContentResult();
}
//Do something in here//
string json = "whatever json goes here";
return new ContentResult{Content = json, ContentType = "application/json"};
}
在客户端,这是ajax函数的样子
$.ajax({
type: "POST",
url: URL,
data: DATA,
dataType: "json",
success: function (json) {
//Do something with the returned json object.
},
error: function (xhr, status, errorThrown) {
//Here the status code can be retrieved like;
xhr.status;
//The message added to Response object in Controller can be retrieved as following.
xhr.responseText;
}
});
使用以下命令在服务器上引发新异常:
Response.StatusCode=500
Response.StatusDescription=例如消息()
我认为StatusDescription返回到Ajax调用。。。
例子:
Try
Dim file As String = Request.QueryString("file")
If String.IsNullOrEmpty(file) Then Throw New Exception("File does not exist")
Dim sTmpFolder As String = "Temp\" & Session.SessionID.ToString()
sTmpFolder = IO.Path.Combine(Request.PhysicalApplicationPath(), sTmpFolder)
file = IO.Path.Combine(sTmpFolder, file)
If IO.File.Exists(file) Then
IO.File.Delete(file)
End If
Catch ex As Exception
Response.StatusCode = 500
Response.StatusDescription = ex.Message()
End Try
如果调用asp.net,将返回错误消息标题:
我没有自己编写所有的formatErrorMessage,但我发现它非常有用。
function formatErrorMessage(jqXHR, exception) {
if (jqXHR.status === 0) {
return ('Not connected.\nPlease verify your network connection.');
} else if (jqXHR.status == 404) {
return ('The requested page not found. [404]');
} else if (jqXHR.status == 500) {
return ('Internal Server Error [500].');
} else if (exception === 'parsererror') {
return ('Requested JSON parse failed.');
} else if (exception === 'timeout') {
return ('Time out error.');
} else if (exception === 'abort') {
return ('Ajax request aborted.');
} else {
return ('Uncaught Error.\n' + jqXHR.responseText);
}
}
var jqxhr = $.post(addresshere, function() {
alert("success");
})
.done(function() { alert("second success"); })
.fail(function(xhr, err) {
var responseTitle= $(xhr.responseText).filter('title').get(0);
alert($(responseTitle).text() + "\n" + formatErrorMessage(xhr, err) );
})