我如何在MongoDB中执行SQL Join等效?

例如,假设你有两个集合(用户和评论),我想拉pid=444的所有评论以及每个评论的用户信息。

comments
  { uid:12345, pid:444, comment="blah" }
  { uid:12345, pid:888, comment="asdf" }
  { uid:99999, pid:444, comment="qwer" }

users
  { uid:12345, name:"john" }
  { uid:99999, name:"mia"  }

是否有一种方法可以一次性提取具有特定字段的所有评论(例如. ...find({pid:444}))和与每个评论相关的用户信息?

目前,我首先获取符合条件的注释,然后找出结果集中的所有uid,获取用户对象,并将它们与注释的结果合并。看来我做错了。


当前回答

在3.2.6之前,Mongodb不像mysql那样支持join查询。下面是适合你的解决方案。

 db.getCollection('comments').aggregate([
        {$match : {pid : 444}},
        {$lookup: {from: "users",localField: "uid",foreignField: "uid",as: "userData"}},
   ])

其他回答

MongoDB不允许连接,但是你可以使用插件来处理。检查mongo-join插件。这是最好的,我已经用过了。你可以直接使用npm安装它,就像这个npm install mongo-join。您可以通过示例查看完整的文档。

(++)非常有用的工具,当我们需要加入(N)个集合

(——)我们可以只在查询的顶层应用条件

例子

var Join = require('mongo-join').Join, mongodb = require('mongodb'), Db = mongodb.Db, Server = mongodb.Server;
db.open(function (err, Database) {
    Database.collection('Appoint', function (err, Appoints) {

        /* we can put conditions just on the top level */
        Appoints.find({_id_Doctor: id_doctor ,full_date :{ $gte: start_date },
            full_date :{ $lte: end_date }}, function (err, cursor) {
            var join = new Join(Database).on({
                field: '_id_Doctor', // <- field in Appoints document
                to: '_id',         // <- field in User doc. treated as ObjectID automatically.
                from: 'User'  // <- collection name for User doc
            }).on({
                field: '_id_Patient', // <- field in Appoints doc
                to: '_id',         // <- field in User doc. treated as ObjectID automatically.
                from: 'User'  // <- collection name for User doc
            })
            join.toArray(cursor, function (err, joinedDocs) {

                /* do what ever you want here */
                /* you can fetch the table and apply your own conditions */
                .....
                .....
                .....


                resp.status(200);
                resp.json({
                    "status": 200,
                    "message": "success",
                    "Appoints_Range": joinedDocs,


                });
                return resp;


            });

    });

不,看起来你并没有做错。MongoDB连接是“客户端”。就像你说的

目前,我首先获取符合条件的注释,然后找出结果集中的所有uid,获取用户对象,并将它们与注释的结果合并。看来我做错了。

1) Select from the collection you're interested in.
2) From that collection pull out ID's you need
3) Select from other collections
4) Decorate your original results.

它不是一个“真正的”连接,但它实际上比SQL连接有用得多,因为您不必处理“多”面连接的重复行,而是修饰最初选择的集合。

这一页上有很多废话和FUD。结果5年后,MongoDB仍然存在。

你可以使用Postgres中的mongo_fdw在MongoDB上运行包括join在内的SQL查询。

As others have pointed out you are trying to create a relational database from none relational database which you really don't want to do but anyways, if you have a case that you have to do this here is a solution you can use. We first do a foreach find on collection A( or in your case users) and then we get each item as an object then we use object property (in your case uid) to lookup in our second collection (in your case comments) if we can find it then we have a match and we can print or do something with it. Hope this helps you and good luck :)

db.users.find().forEach(
function (object) {
    var commonInBoth=db.comments.findOne({ "uid": object.uid} );
    if (commonInBoth != null) {
        printjson(commonInBoth) ;
        printjson(object) ;
    }else {
        // did not match so we don't care in this case
    }
});

从Mongo 3.2开始,这个问题的答案大多不再正确。添加到聚合管道中的新的$lookup操作符本质上与左外连接相同:

https://docs.mongodb.org/master/reference/operator/aggregation/lookup/#pipe._S_lookup

从文档中可以看出:

{
   $lookup:
     {
       from: <collection to join>,
       localField: <field from the input documents>,
       foreignField: <field from the documents of the "from" collection>,
       as: <output array field>
     }
}

当然,MongoDB不是一个关系数据库,开发人员正在谨慎地推荐$lookup的特定用例,但至少在3.2中,使用MongoDB进行连接是可能的。