我怎样才能将我的JS对象转换为FormData?
我这样做的原因是，我有一个用~100个表单字段值构造的对象。
var item = {
description: 'Some Item',
price : '0.00',
srate : '0.00',
color : 'red',
...
...
}
现在我被要求将上传文件功能添加到我的表单，当然，通过JSON是不可能的，所以我计划移动到FormData。那么有什么方法可以将我的JS对象转换为FormData呢?
当前回答
递归地
const toFormData = (f => f(f))(h => f => f(x => h(h)(f)(x)))(f => fd => pk => d => { if (d instanceof Object) { Object.keys(d).forEach(k => { const v = d[k] if (pk) k = `${pk}[${k}]` if (v instanceof Object && !(v instanceof Date) && !(v instanceof File)) { return f(fd)(k)(v) } else { fd.append(k, v) } }) } return fd })(new FormData())() let data = { name: 'John', age: 30, colors: ['red', 'green', 'blue'], children: [ { name: 'Max', age: 3 }, { name: 'Madonna', age: 10 } ] } console.log('data', data) document.getElementById("data").insertAdjacentHTML('beforeend', JSON.stringify(data)) let formData = toFormData(data) for (let key of formData.keys()) { console.log(key, formData.getAll(key).join(',')) document.getElementById("item").insertAdjacentHTML('beforeend', `<li>${key} = ${formData.getAll(key).join(',')}</li>`) } <p id="data"></p> <ul id="item"></ul>
其他回答
也许你正在寻找这个，一个代码，接收你的javascript对象，从它创建一个FormData对象，然后POST它到你的服务器使用新的Fetch API:
let myJsObj = {'someIndex': 'a value'};
let datos = new FormData();
for (let i in myJsObj){
datos.append( i, myJsObj[i] );
}
fetch('your.php', {
method: 'POST',
body: datos
}).then(response => response.json())
.then(objson => {
console.log('Success:', objson);
})
.catch((error) => {
console.error('Error:', error);
});
很简单，可以这样做:
var item: { some1: "ajbd" , some2: "dds".. }
let myFormData = new FormData();
const abc = item.some1;
const xyz = item.some2;
myFormData.append('field1', abc);
myFormData.append('field2', xyz);
fetch('http:url', {
method: 'POST',
headers: {
'Content-Type': false,
},
body: myFormData,
}).
do promise ..
我有一个场景，在构造表单数据时，嵌套的JSON必须以线性方式序列化，因为这是服务器期望值的方式。所以，我写了一个小的递归函数来翻译JSON，就像这样:
{
"orderPrice":"11",
"cardNumber":"************1234",
"id":"8796191359018",
"accountHolderName":"Raj Pawan",
"expiryMonth":"02",
"expiryYear":"2019",
"issueNumber":null,
"billingAddress":{
"city":"Wonderland",
"code":"8796682911767",
"firstname":"Raj Pawan",
"lastname":"Gumdal",
"line1":"Addr Line 1",
"line2":null,
"state":"US-AS",
"region":{
"isocode":"US-AS"
},
"zip":"76767-6776"
}
}
变成这样:
{
"orderPrice":"11",
"cardNumber":"************1234",
"id":"8796191359018",
"accountHolderName":"Raj Pawan",
"expiryMonth":"02",
"expiryYear":"2019",
"issueNumber":null,
"billingAddress.city":"Wonderland",
"billingAddress.code":"8796682911767",
"billingAddress.firstname":"Raj Pawan",
"billingAddress.lastname":"Gumdal",
"billingAddress.line1":"Addr Line 1",
"billingAddress.line2":null,
"billingAddress.state":"US-AS",
"billingAddress.region.isocode":"US-AS",
"billingAddress.zip":"76767-6776"
}
服务器将接受这种转换格式的表单数据。
函数如下:
function jsonToFormData (inJSON, inTestJSON, inFormData, parentKey) {
// http://stackoverflow.com/a/22783314/260665
// Raj: Converts any nested JSON to formData.
var form_data = inFormData || new FormData();
var testJSON = inTestJSON || {};
for ( var key in inJSON ) {
// 1. If it is a recursion, then key has to be constructed like "parent.child" where parent JSON contains a child JSON
// 2. Perform append data only if the value for key is not a JSON, recurse otherwise!
var constructedKey = key;
if (parentKey) {
constructedKey = parentKey + "." + key;
}
var value = inJSON[key];
if (value && value.constructor === {}.constructor) {
// This is a JSON, we now need to recurse!
jsonToFormData (value, testJSON, form_data, constructedKey);
} else {
form_data.append(constructedKey, inJSON[key]);
testJSON[constructedKey] = inJSON[key];
}
}
return form_data;
}
调用:
var testJSON = {};
var form_data = jsonToFormData (jsonForPost, testJSON);
我使用testJSON只是为了查看转换后的结果，因为我无法提取form_data的内容。AJAX post call:
$.ajax({
type: "POST",
url: somePostURL,
data: form_data,
processData : false,
contentType : false,
success: function (data) {
},
error: function (e) {
}
});
如果您有一个对象，您可以轻松地创建一个FormData对象，并将该对象的名称和值附加到FormData。
你还没有发布任何代码，所以这是一个通用的例子;
var form_data = new FormData();
for ( var key in item ) {
form_data.append(key, item[key]);
}
$.ajax({
url : 'http://example.com/upload.php',
data : form_data,
processData : false,
contentType : false,
type: 'POST'
}).done(function(data){
// do stuff
});
在MDN的文档中有更多的例子
我可能有点晚了，但这就是我创建的将单个对象转换为FormData的方法。
function formData(formData, filesIgnore = []) {
let data = new FormData();
let files = filesIgnore;
Object.entries(formData).forEach(([key, value]) => {
if (typeof value === 'object' && !files.includes(key)) {
data.append(key, JSON.stringify(value) || null);
} else if (files.includes(key)) {
data.append(key, value[0] || null);
} else {
data.append(key, value || null);
}
})
return data;
}
它是如何工作的? 它将转换并返回所有属性，除了您在忽略列表中设置的File对象(第二个参数)。如果有人能告诉我一个更好的方法来确定这将有帮助!)变成一个json字符串使用json .stringify。然后在您的服务器上，您只需要将其转换回JSON对象。
例子:
let form = {
first_name: 'John',
last_name: 'Doe',
details: {
phone_number: 1234 5678 910,
address: '123 Some Street',
},
profile_picture: [object FileList] // set by your form file input. Currently only support 1 file per property.
}
function submit() {
let data = formData(form, ['profile_picture']);
axios.post('/url', data).then(res => {
console.log('object uploaded');
})
}
我仍然有点新的Http请求和JavaScript，所以任何反馈将高度赞赏!
