我使用以下JavaScript代码打开了一个网络摄像头:

const stream = await navigator.mediaDevices.getUserMedia({ /* ... */ });

是否有任何JavaScript代码停止或关闭网络摄像头?


当前回答

下面的代码适用于我:

public vidOff() {

      let stream = this.video.nativeElement.srcObject;
      let tracks = stream.getTracks();

      tracks.forEach(function (track) {
          track.stop();
      });

      this.video.nativeElement.srcObject = null;
      this.video.nativeElement.stop();
  }

其他回答

FF, Chrome和Opera已经开始通过导航器公开getUserMedia。mediaDevices现在是标准(可能会改变:)

在线演示

navigator.mediaDevices.getUserMedia({audio:true,video:true})
    .then(stream => {
        window.localStream = stream;
    })
    .catch( (err) =>{
        console.log(err);
    });
// later you can do below
// stop both video and audio
localStream.getTracks().forEach( (track) => {
track.stop();
});
// stop only audio
localStream.getAudioTracks()[0].stop();
// stop only video
localStream.getVideoTracks()[0].stop();

试试下面的方法:

var mediaStream = null;
    navigator.getUserMedia(
        {
            audio: true,
            video: true
        },
        function (stream) {
            mediaStream = stream;
            mediaStream.stop = function () {
                this.getAudioTracks().forEach(function (track) {
                    track.stop();
                });
                this.getVideoTracks().forEach(function (track) { //in case... :)
                    track.stop();
                });
            };
            /*
             * Rest of your code.....
             * */
        });

    /*
    * somewhere insdie your code you call
    * */
    mediaStream.stop();

您可以直接使用成功处理程序中返回给getUserMedia的流对象来结束流。如。

localMediaStream.stop()

视频。Src =""或null只会从视频标签中删除源。它不会释放硬件。

有溪流形式成功的参考吗

var streamRef;

var handleVideo = function (stream) {
    streamRef = stream;
}

//this will stop video and audio both track
streamRef.getTracks().map(function (val) {
    val.stop();
});

下面的代码适用于我:

public vidOff() {

      let stream = this.video.nativeElement.srcObject;
      let tracks = stream.getTracks();

      tracks.forEach(function (track) {
          track.stop();
      });

      this.video.nativeElement.srcObject = null;
      this.video.nativeElement.stop();
  }