如果你想避免取模，你也可以使用四个基本操作的组合:)

26 - (26 // 7 * 7) = 5

从Python 3.7开始，有一个新的math.remainder()函数:

from math import remainder
print(remainder(26,7))

输出:

-2.0  # not 5

注意，如上所述，它与%不同。

引用文档:

math.remainder(x, y) Return the IEEE 754-style remainder of x with respect to y. For finite x and finite nonzero y, this is the difference x - n*y, where n is the closest integer to the exact value of the quotient x / y. If x / y is exactly halfway between two consecutive integers, the nearest even integer is used for n. The remainder r = remainder(x, y) thus always satisfies abs(r) <= 0.5 * abs(y). Special cases follow IEEE 754: in particular, remainder(x, math.inf) is x for any finite x, and remainder(x, 0) and remainder(math.inf, x) raise ValueError for any non-NaN x. If the result of the remainder operation is zero, that zero will have the same sign as x. On platforms using IEEE 754 binary floating-point, the result of this operation is always exactly representable: no rounding error is introduced.

Issue29962描述了创建新函数的基本原理。

如果你想避免取模，你也可以使用四个基本操作的组合:)

26 - (26 // 7 * 7) = 5

除法的余数可以使用运算符%来发现:

>>> 26%7
5

如果你同时需要商和模，有一个内置的divmod函数:

>>> seconds= 137
>>> minutes, seconds= divmod(seconds, 60)

26 % 7(你将得到余数)

26 / 7(你会得到除数，可以是浮点值)

26 // 7(你将得到除数，只有整数值)

我们可以用模算子(%)来解决这个问题

26%7 = 5;

但 26 / 7 = 3，因为它会给出商，而%运算符会给出余数。